Mattingly "AI & Prompt Design: The Basics of Prompt Design"
Fet basics-1
1. FET ( Field Effect Transistor)
1. Unipolar device i. e. operation depends on only one type of
charge carriers (h or e)
2. Voltage controlled Device (gate voltage controls drain
current)
3. Very high input impedance (≈109
-1012
Ω)
4. Source and drain are interchangeable in most Low-frequency
applications
5. Low Voltage Low Current Operation is possible (Low-power
consumption)
6. Less Noisy as Compared to BJT
7. No minority carrier storage (Turn off is faster)
8. Self limiting device
9. Very small in size, occupies very small space in ICs
10. Low voltage low current operation is possible in MOSFETS
11. Zero temperature drift of out put is possiblek
Few important advantages of FET over conventional Transistors
2. Types of Field Effect Transistors
(The Classification)
» JFET
MOSFET (IGFET)
n-Channel JFET
p-Channel JFET
n-Channel
EMOSFET
p-Channel
EMOSFET
Enhancement
MOSFET
Depletion
MOSFET
n-Channel
DMOSFET
p-Channel
DMOSFET
FET
6. Figure: The nonconductive depletion region becomes broader with increased reverse bias.
(Note: The two gate regions of each FET are connected to each other.)
Operation of JFET at Various Gate Bias Potentials
7. P P +
-
DC Voltage Source
+
-
+
-
N
N
Operation of a JFET
Gate
Drain
Source
8. Figure: Circuit for drain characteristics of the n-channel JFET and its Drain characteristics.
Non-saturation (Ohmic) Region:
The drain current is given by
−
−=
2
2 2
2
DS
DSPGS
P
DSS
DS
V
VVV
V
I
I
−=
2
2 PGS
P
DSS
DS
VV
V
I
I
2
1and
−=
P
GS
DSSDS V
V
II
Where, IDSS is the short circuit drain current, VP is the pinch off voltage
Output or Drain (VD-ID) Characteristics of n-JFET
Saturation (or Pinchoff) Region:
−<
PGSDS
VVV
−≥
PGSDS
VVV
10. Figure: If vDG exceeds the breakdown voltage VB, drain current increases rapidly.
Break Down Region
N-Channel JFET Characteristics and Breakdown
11. Figure: Typical drain characteristics of an n-channel JFET.
VD-ID Characteristics of EMOS FET
Saturation or Pinch
off Reg.
Locus of pts where ( )PGSDS VVV −=
12. Figure: Transfer (or Mutual) Characteristics of n-Channel JFET
2
1
−=
P
GS
DSSDS V
V
II
IDSS
VGS (off)=VP
Transfer (Mutual) Characteristics of n-Channel JFET
14. Biasing Circuits used for JFET
• Fixed bias circuit
• Self bias circuit
• Potential Divider bias circuit
15. JFET (n-channel) Biasing Circuits
2
1
−=
P
GS
DSSDS V
V
II
0, ===+= GGSGSGGGG IFixedVVRIV
DDSDDDS
P
GS
DSSDS
RIVV
V
V
II
−=
−=
and
1
2
S
GS
DS
SDSGS
R
V
I
RIV
−=∴
=+ 0
For Self Bias Circuit
For Fixed Bias Circuit
Applying KVL to gate circuit we get
and
Where, Vp=VGS-off & IDSS is Short ckt. IDS
17. JFET Self (or Source) Bias Circuit
2
1and
−=
P
GS
DSSDS V
V
II
S
GS
P
GS
DSS R
V
V
V
I −=
−∴
2
1
021
2
=+
+−
S
GS
P
GS
P
GS
DSS R
V
V
V
V
V
I
This quadratic equation can be solved for VGS & IDS
18. The Potential (Voltage) Divider Bias
01
2
=
−
−
−∴
S
GSG
P
GS
DSS R
VV
V
V
I
DSGS
IVgivesequationquadraticthisSolving and
19. A Simple CS Amplifier and Variation in IDS with Vgs
20. FET Mid-frequency Analysis:
g
s
rd
gmvπ
vi = vπ
ii
io
vo
d
s
+ +
_ _
mid-frequency CE amplifier circuit
RD RLRThvs
+
_
is
' 'o o i
vi m L L d D L vs vi
i s s i
i
i Th Th 1 2
i
Analysis of the CS mid-frequency circuit above yields:
v v Z
A = = -g R , where R = r R R A = = A
v v R + Z
v
Z = = R , where R = R R
i
L
o i
I vi
i L
o o
o d D P vi I
o iseen by R
i Z
A = = A
i R
v p
Z = = r R A = = A A
i p
A common source (CS) amplifier is shown
to the right.
Rs
Ci
RL
Co
CSS
vi
vo
+
+
vs
+
_
_
_
io
ii
D
S
G
VDD VDD
R1
RSS
RD
R2
The mid-frequency circuit is drawn as follows:
• the coupling capacitors (Ci and Co) and the
bypass capacitor (CSS) are short circuits
• short the DC supply voltage (superposition)
• replace the FET with the hybrid-π model
The resulting mid-frequency circuit is shown below.
21. FET Mid-frequency Analysis:
g
s
rd
gmvπ
vi = vπ
ii
io
vo
d
s
+ +
_ _
mid-frequency CE amplifier circuit
RD RLRThvs
+
_
is
' 'o o i
vi m L L d D L vs vi
i s s i
i
i Th Th 1 2
i
Analysis of the CS mid-frequency circuit above yields:
v v Z
A = = -g R , where R = r R R A = = A
v v R + Z
v
Z = = R , where R = R R
i
L
o i
I vi
i L
o o
o d D P vi I
o iseen by R
i Z
A = = A
i R
v p
Z = = r R A = = A A
i p
A common source (CS) amplifier is shown
to the right.
Rs
Ci
RL
Co
CSS
vi
vo
+
+
vs
+
_
_
_
io
ii
D
S
G
VDD VDD
R1
RSS
RD
R2
The mid-frequency circuit is drawn as follows:
• the coupling capacitors (Ci and Co) and the
bypass capacitor (CSS) are short circuits
• short the DC supply voltage (superposition)
• replace the FET with the hybrid-π model
The resulting mid-frequency circuit is shown below.
22. Procedure: Analysis of an FET amplifier at mid-frequency:
1) Find the DC Q-point. This will insure that the FET is operating in the saturation
region and these values are needed for the next step.
2) Find gm. If gm is not specified, calculate it using the DC values of VGS as follows:
3) Calculate the required values (typically Avi, Avs, AI, AP, Zi, and Zo. Use the formulas for
the appropriate amplifier configuration (CS, CG, CD, etc).
( )
( )
DSSD
m GS P2
GS P
D
m GS T
GS
GS
2II
g = = V - V (for JFET's and DM MOSFET's)
V V
I
g = = V - V (for EM MOSFET's)
V
(Note: Uses DC value of V )
K
∂
∂
∂
∂
23. PE-Electrical Review Course - Class 4 (Transistors)
Example 7:
Find the mid-frequency values for Avi, Avs, AI, AP, Zi,
and Zo for the amplifier shown below. Assume that
Ci, Co, and CSS are large.
Note that this is the same biasing circuit used in Ex.
2, so VGS = -0.178 V.
The JFET has the following specifications:
ΙDSS = 4 mA, VP = -1.46 V, rd = 50 k
10 k
Ci
8 k
Co
CSS
vi
vo
+
+
vs
+
_
_
_
io
ii
D
S
G
18 V 18 V
800 k
2 k
500
400 k
24. FET Amplifier Configurations and
Relationships:
'
' ' m L
vi m L m L '
m L
'
L d D L d D L SS L
i Th SS Th
m
o d D d D SS
m
i i i
vs vi vi vi
s i s i s i
i i i
I vi vi vi
L L L
P vi I vi I
CS CG CD
g R
A -g R g R
1 g R
R r R R r R R R R
1
Z R R R
g
1
Z r R r R R
g
Z Z Z
A A A A
R + Z R + Z R + Z
Z Z Z
A A A A
R R R
A A A A A
+
vi I
Th 1 2
A A
where R = R R
VCC
RD
S
R2
RSS
Rs
Ci
RL
Co
C2
vi
vo
+
+
vs
+
_
__
io
ii
Common Gate (CG) Amplifier
R1
D
G
Note: The biasing circuit is the same for each amp.
Rs
Ci
RL
Co
CSS
vi
vo
+
+
vs
+
_ _
_
io
ii
D
S
G
VDD VDD
R1
RSS
RD
R2
Common Source (CS) Amplifier
Rs
Ci
vi
+
vs
+
_
_
ii G
VDD VDD
R1
RSS
R2
Common Drain (CD) Amplifier (also called “source follower”)
RL
Co
vo
+
_
io
D
S
27. Figure: For vGS < Vto the pn junction between drain and body is reverse biased and iD=0.
28. Figure: For vGS >Vto a channel of n-type material is induced in the region under the gate.
As vGS increases, the channel becomes thicker. For small values of vDS ,iD is proportional to vDS.
The device behaves as a resistor whose value depends on vGS.
29. Figure: As vDS increases, the channel pinches down at the drain end and iD increases more slowly.
Finally for vDS> vGS -Vto, iD becomes constant.
45. For drawing an a c equivalent circuit of Amp.
•Assume all Capacitors C1, C2, Cs as short
circuit elements for ac signal
•Short circuit the d c supply
•Replace the FET by its small signal model
46. Analysis of CS Amplifier
LgsmLoo
gs
o
v
RvgRiv
v
v
A
−==∴
=gain,Voltage
dDLLm
gs
o
v
rRRRg
v
v
A =−==∴ ,
Dd
Dd
Ddo Rr
Rr
RrZ
+
==imp.,putOut
21
imp.,Input RRRZ
Gin
==
A C Equivalent Circuit
Simplified A C Equivalent Circuit
47. Analysis of CS Amplifier with Potential Divider Bias
)R||(rgAv Ddm−=
D
R10rD,m
d
RgAv ≥−≅
)R||(rgAv Ddm−=
This is a CS amplifier configuration therefore the
input is on the gate and the output is on the drain. 21 R||RZi =
Dd R||rZo =
Dd
D
10Rr
RZo
≥
≅
48. Figure vo(t) and vin(t) versus time for the common-source amplifier of Figure 5.28.
62. Figure p-Channel FET circuit symbols. These are the same as the circuit symbols for n-channel devices,
except for the directions of the arrowheads.
63. Figure Drain current versus vGS for several types of FETs. iD is referenced into the drain terminal
for n-channel devices and out of the drain for p-channel devices.