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SUBJECT :- V.C.L.A.- 2110015
TOPIC :- Arc Length, Curvature and Torsion
Prepared by: Vaani Pathak
Branch: CE
Division: C1
Enrollment No.: 170120107131
Guided by:
Topics to be Covered
Gandhinagar Institute Of Technology 2
 Arc Length
 Curvature
 Torsion
Arc Length
Gandhinagar Institute Of Technology3
 For plane curves r(t) = f(t) i + g(t) j
 |r’(t) = |𝑓’(t)i + g’(t)j| = [𝑓’(t)]2+[g′(t)]2
 For space curves r(t) = f(t) i + g(t) j + h(t) k
 |r’(t) = |𝑓’(t)i + g’(t)j + h’(t)k|
= [𝑓’(t)]2+[g′(t)]2+[h′(t)]2
Gandhinagar Institute Of Technology4
Example 1: Determine the length of the curve
𝒓 (t)=(2t,3sin(2t),3cos(2t)) on the interval 0≤t≤2𝝅
Solution
We swill first need the tangent vector and its magnitude
𝑟′(t)=(2,6cos(2t),-6sin(2t))
|| 𝑟′ 𝑡 || = 4+36cos2 (2t)+36sin2(2t)
= 4+36 = 2 10
The length is then,
L = 𝑎
𝑏
|| 𝑟′ 𝑡 ||dt
= 0
2𝝅
2 10 dt
= 4 𝝅 10
Curvature
Gandhinagar Institute Of Technology5
 The curvature measures how fast a curve is changing
direction at a given point.
 It is natural to define the curvature of a straight line to be
identically zero.
 Given any curve C and a point P on it,
there is a unique circle or line which most
closely approximates the curve near P,
the osculating circle at P.
 The curvature of C at P is
then defined to be the
curvature of that circle or
line.
 The radius of curvature is
defined as the reciprocal of
the curvature.
Curvature
Gandhinagar Institute Of Technology 6
 The curvature is easier to compute if
it is expressed in terms of the parameter t instead of
s.
 So, we use the Chain Rule to write:
 However, ds/dt = |r’(t)|. So,

𝑑𝑇
𝑑𝑡
=
𝑑𝑇
𝑑𝑠
𝑑𝑠
𝑑𝑡
and k =
𝑑𝑇
𝑑𝑠
=
𝑑𝑇/𝑑𝑡
𝑑𝑠/𝑑𝑡
 k(t)=
𝑇′(𝑡)
𝑟′(𝑡)
Exercise: 1
Gandhinagar Institute Of Technology 7
Determine the curvature for tkittr  2'
)(
In this case the second form of the curvature would probably be easiest.
Here are the first couple of derivatives
𝑟′ 𝑡 = 2𝑡 𝑖 + 𝑘 𝑟′′ = 2 𝑖
Next, we need the cross product.
𝑟′ 𝑡 × 𝑟′′(𝑡) =
𝑖 𝑗 𝑘
2𝑡 0 1
2 0 0
= 2 𝑗′
|| 𝑟′ 𝑡 × 𝑟′′ 𝑡 || = 2 | 𝑟′ 𝑡 | = 4𝑡2 + 2
The magnitudes are,
The curvature at any value of t is then,
𝑘 =
2
4𝑡2 + 1
3
2
Torsion of the curve
Gandhinagar Institute Of Technology 8
 In the elementary differential geometry of
curves in three dimensions, the torsion of
a curve measures how sharply it is twisting out of
the plane of curvature.
Formula of Torsion
Gandhinagar Institute Of Technology 9
 Let r = r(t) be the parametric equation of a space curve.
Assume that this is a regular parameterization and that
the curvature of the curve does not vanish.
Analytically, r(t) is a three times
differentiable function of t with values in R3 and the
vectors are linearly independent.
 Then the torsion can be computed from the following
formula:
 𝜏 =
det(𝑟′,𝑟′′,𝑟′′′)
𝑟′×𝑟′′ 2 =
𝑟′×𝑟′′ .𝑟′′′
𝑟′×𝑟′′ 2
Example
Gandhinagar Institute Of Technology10
THANK YOU

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Arc Length, Curvature and Torsion

  • 1. SUBJECT :- V.C.L.A.- 2110015 TOPIC :- Arc Length, Curvature and Torsion Prepared by: Vaani Pathak Branch: CE Division: C1 Enrollment No.: 170120107131 Guided by:
  • 2. Topics to be Covered Gandhinagar Institute Of Technology 2  Arc Length  Curvature  Torsion
  • 3. Arc Length Gandhinagar Institute Of Technology3  For plane curves r(t) = f(t) i + g(t) j  |r’(t) = |𝑓’(t)i + g’(t)j| = [𝑓’(t)]2+[g′(t)]2  For space curves r(t) = f(t) i + g(t) j + h(t) k  |r’(t) = |𝑓’(t)i + g’(t)j + h’(t)k| = [𝑓’(t)]2+[g′(t)]2+[h′(t)]2
  • 4. Gandhinagar Institute Of Technology4 Example 1: Determine the length of the curve 𝒓 (t)=(2t,3sin(2t),3cos(2t)) on the interval 0≤t≤2𝝅 Solution We swill first need the tangent vector and its magnitude 𝑟′(t)=(2,6cos(2t),-6sin(2t)) || 𝑟′ 𝑡 || = 4+36cos2 (2t)+36sin2(2t) = 4+36 = 2 10 The length is then, L = 𝑎 𝑏 || 𝑟′ 𝑡 ||dt = 0 2𝝅 2 10 dt = 4 𝝅 10
  • 5. Curvature Gandhinagar Institute Of Technology5  The curvature measures how fast a curve is changing direction at a given point.  It is natural to define the curvature of a straight line to be identically zero.  Given any curve C and a point P on it, there is a unique circle or line which most closely approximates the curve near P, the osculating circle at P.  The curvature of C at P is then defined to be the curvature of that circle or line.  The radius of curvature is defined as the reciprocal of the curvature.
  • 6. Curvature Gandhinagar Institute Of Technology 6  The curvature is easier to compute if it is expressed in terms of the parameter t instead of s.  So, we use the Chain Rule to write:  However, ds/dt = |r’(t)|. So,  𝑑𝑇 𝑑𝑡 = 𝑑𝑇 𝑑𝑠 𝑑𝑠 𝑑𝑡 and k = 𝑑𝑇 𝑑𝑠 = 𝑑𝑇/𝑑𝑡 𝑑𝑠/𝑑𝑡  k(t)= 𝑇′(𝑡) 𝑟′(𝑡)
  • 7. Exercise: 1 Gandhinagar Institute Of Technology 7 Determine the curvature for tkittr  2' )( In this case the second form of the curvature would probably be easiest. Here are the first couple of derivatives 𝑟′ 𝑡 = 2𝑡 𝑖 + 𝑘 𝑟′′ = 2 𝑖 Next, we need the cross product. 𝑟′ 𝑡 × 𝑟′′(𝑡) = 𝑖 𝑗 𝑘 2𝑡 0 1 2 0 0 = 2 𝑗′ || 𝑟′ 𝑡 × 𝑟′′ 𝑡 || = 2 | 𝑟′ 𝑡 | = 4𝑡2 + 2 The magnitudes are, The curvature at any value of t is then, 𝑘 = 2 4𝑡2 + 1 3 2
  • 8. Torsion of the curve Gandhinagar Institute Of Technology 8  In the elementary differential geometry of curves in three dimensions, the torsion of a curve measures how sharply it is twisting out of the plane of curvature.
  • 9. Formula of Torsion Gandhinagar Institute Of Technology 9  Let r = r(t) be the parametric equation of a space curve. Assume that this is a regular parameterization and that the curvature of the curve does not vanish. Analytically, r(t) is a three times differentiable function of t with values in R3 and the vectors are linearly independent.  Then the torsion can be computed from the following formula:  𝜏 = det(𝑟′,𝑟′′,𝑟′′′) 𝑟′×𝑟′′ 2 = 𝑟′×𝑟′′ .𝑟′′′ 𝑟′×𝑟′′ 2