Determine Ll is constant throughout the beam points) 9 m Solution Using conjugate beam method Calculate reaction at B Rb xl =(1/EI) [0.5 (Wab/l) a (2a/3) + 0.5 (Wab/l) b x (a+b/3)] l = 12m a = 9m b = 3m W = 8Kn Rb x9 =(1/EI) [0.5 (8x9x3/12) 9(2x9/3) + 0.5 (8x9x3/12) 3 x (9+3/3)] Rbx 9 = (1/EI) [ 756] Rb = 84/EI Now reaction at A Ra = (1/Ei) 12(8x9x3/12) - Rb = (1/Ei) l(wab/l) -rb Ra = (1/EI) (216-84) Ra = 132/EI Bending moemnt at C Mc = Rb x b - (1/EI) (0.5 x [Wab/l] x b x b/3] Mc = (84/EI)x3 - (1/EI) (0.5x9x8x3x3x3/36] Mc = 225/EI So deflection Yc = Mc = 225/EI.