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By

Shriket Trivedi
Shortest Path

Is That All ??
TIME

DISTANCE
_________
=
SPEED

SAVINGS AND EARNINGS
 Each stop on the route may have volume to be picked
up as well as delivered

 Multiple vehicles may be used using different capacity
limits to both weight and Volume
 Maximum total driving time allowed before a rest

period must be taken is 8 hours
 Stops may permit pickups/deliveries only at certain
times of day (time windows)
 Drivers must be allowed to take short rests or lunch
breaks at certain times of the day.
ROUTING
METHODS
The Sweep Method of Routing
 Locate all stops including the depot on a map or grid
 Extend a straight line from the depot in any direction
 Rotate the line (clockwise or counterclockwise) until it

intersects a stop
 Will the inserted stop exceed the vehicle’s capacity?
 If not, continue rotating the line until the next stop is

intersected
 Will the cumulative volume exceed the vehicle’s capacity?
 Continue process until vehicle’s capacity would be exceeded

 Sequence the stops to minimize distance
Case Study
 Jai Ganesh Trucking uses vans to deliver packages to

outlaying customers
 Packages are collected from a warehouse which

doubles as a depot for the vans
 Firm’s vans can carry 10,000 units at a time
Sweep Method Example
Pickup Stop Data:
quantities shown in units

E
H

1000

4000

A

F

2000

3000

D
Depot

G
2000

2000

1000
K
2000

3000

3000

I

L

B

C
2000
J
2000
Sweep Method Example
“Sweep” method
solution
E
H

1000

4000

A

F

2000

3000

D

Depot

G
2000

2000

3000

I
1000

L
K
2000

3000

B

C
2000
J
2000
Sweep Method Example
“Sweep” method
solution
E
H

1000

4000
F
3000

Route 1
10,000 units

2000
D

Depot

G
2000

1000
K
2000

3000

B
3000

I

L
2000

A

C
2000
J
2000
Sweep Method Example
“Sweep” method
solution
E
H

1000

4000
F
3000

2000
D

Depot

G

1000
K
2000

3000

B
3000

I

L
2000

A

Route 1
10,000 units

2000

Route 3
8,000 units

Route 2
9,000 units

C
2000

J
2000
The Savings Method of
Routing
 Begin with a dummy vehicle serving each stop and

returning to the depot.

 Gives the maximum distance to be experienced in the

routing problem

 Two stops are then combined together on the same

route

 Eliminates one vehicle and travel distance is reduced

 To determine which stops to combine on a route, the

distance saved is calculated before and after each
combination

 This calculation is repeated for all stop pairs
 The stop pair with the largest savings value is selected to be

combined
The Savings Method of
Routing

Route distance
= d0,A + dA,0 + d0,B + dB,0

d0,A

dA,0

Stop A

Depot (0)
dB,0

d0,B

Stop B
The Savings Method of
Routing
Route distance
= d0,A + dA,B + dB,0
d0,A

Stop A
dA,B

Depot (0)
dB,0

Stop B

Savings value of S
= d0,A + dB,0 - dA,B
The Savings Method of
Routing

Route distance = d0,A(100) + dA,0 (100) + d0,B(85) + dB,0 (85) + d0,C (25) + dC,0 (25) =
420 total miles
d0,A = 100

(A)
dA,0 = 100

(0)
dB,0 = 85
d0,B = 85

(B)

d0,C = 25

(C)
dC,0 = 25
The Savings Method of
Routing

Combining 3 stops on 1 route – Route distance (additional stop added after 1st 2 stops)
= d0,A(100) + dA,B(145) + dB,C(65) + dC,0(25) = 335 miles

d0,A = 100

(A)
dA,B = 145

(0)

(B)
dB,C = 65

dC,0 = 25

(C)
Savings value of S = 45 miles saved

Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
The Savings Method of
Routing

Combining 3 stops on 1 route – Route distance (additional stop added between 1st 2 stops)
= d0,A(100) + dA,C(125) + dC,B(65) + dB,0(85) = 375 miles

d0,A = 100

(A)
dA,C = 125

(0)

(C)
dC,B = 65

dB,0 = 85

(B)
Savings value of S = 5 miles saved
Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
The Savings Method of
Routing

Combining 3 stops on 1 route – Route distance (additional stop added before 1st 2 stops)
= d0,C(25) + dC,A(125) + dA,B(145) + dB,0(85) = 380 miles

d0,C = 25

(C)
dC,A = 125

(0)

(A)
dA,B = 145

dB,0 = 85

(B)
Savings value of S = 0 miles saved
Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
Reduce Fleet Size
Traffic Patters
Order Tracking

Terrain

Vehicle Maintainance Costs
Save Fuel

Scheduling And Prioretisation
Faster Deliveries

Real Time Dynamic Routing
Used By All Large Scale
Companies For Transportation

Operations
REDUCE TARGET INPUTS
Like
Fuel, Number of
Vehicles & Man Power
While Maintaining
Some Routing Software Providers
Logistics Routing

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Logistics Routing

  • 2.
  • 5.
  • 6.  Each stop on the route may have volume to be picked up as well as delivered  Multiple vehicles may be used using different capacity limits to both weight and Volume  Maximum total driving time allowed before a rest period must be taken is 8 hours  Stops may permit pickups/deliveries only at certain times of day (time windows)  Drivers must be allowed to take short rests or lunch breaks at certain times of the day.
  • 8.
  • 9. The Sweep Method of Routing  Locate all stops including the depot on a map or grid  Extend a straight line from the depot in any direction  Rotate the line (clockwise or counterclockwise) until it intersects a stop  Will the inserted stop exceed the vehicle’s capacity?  If not, continue rotating the line until the next stop is intersected  Will the cumulative volume exceed the vehicle’s capacity?  Continue process until vehicle’s capacity would be exceeded  Sequence the stops to minimize distance
  • 10. Case Study  Jai Ganesh Trucking uses vans to deliver packages to outlaying customers  Packages are collected from a warehouse which doubles as a depot for the vans  Firm’s vans can carry 10,000 units at a time
  • 11. Sweep Method Example Pickup Stop Data: quantities shown in units E H 1000 4000 A F 2000 3000 D Depot G 2000 2000 1000 K 2000 3000 3000 I L B C 2000 J 2000
  • 12. Sweep Method Example “Sweep” method solution E H 1000 4000 A F 2000 3000 D Depot G 2000 2000 3000 I 1000 L K 2000 3000 B C 2000 J 2000
  • 13. Sweep Method Example “Sweep” method solution E H 1000 4000 F 3000 Route 1 10,000 units 2000 D Depot G 2000 1000 K 2000 3000 B 3000 I L 2000 A C 2000 J 2000
  • 14. Sweep Method Example “Sweep” method solution E H 1000 4000 F 3000 2000 D Depot G 1000 K 2000 3000 B 3000 I L 2000 A Route 1 10,000 units 2000 Route 3 8,000 units Route 2 9,000 units C 2000 J 2000
  • 15.
  • 16. The Savings Method of Routing  Begin with a dummy vehicle serving each stop and returning to the depot.  Gives the maximum distance to be experienced in the routing problem  Two stops are then combined together on the same route  Eliminates one vehicle and travel distance is reduced  To determine which stops to combine on a route, the distance saved is calculated before and after each combination  This calculation is repeated for all stop pairs  The stop pair with the largest savings value is selected to be combined
  • 17. The Savings Method of Routing Route distance = d0,A + dA,0 + d0,B + dB,0 d0,A dA,0 Stop A Depot (0) dB,0 d0,B Stop B
  • 18. The Savings Method of Routing Route distance = d0,A + dA,B + dB,0 d0,A Stop A dA,B Depot (0) dB,0 Stop B Savings value of S = d0,A + dB,0 - dA,B
  • 19. The Savings Method of Routing Route distance = d0,A(100) + dA,0 (100) + d0,B(85) + dB,0 (85) + d0,C (25) + dC,0 (25) = 420 total miles d0,A = 100 (A) dA,0 = 100 (0) dB,0 = 85 d0,B = 85 (B) d0,C = 25 (C) dC,0 = 25
  • 20. The Savings Method of Routing Combining 3 stops on 1 route – Route distance (additional stop added after 1st 2 stops) = d0,A(100) + dA,B(145) + dB,C(65) + dC,0(25) = 335 miles d0,A = 100 (A) dA,B = 145 (0) (B) dB,C = 65 dC,0 = 25 (C) Savings value of S = 45 miles saved Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
  • 21. The Savings Method of Routing Combining 3 stops on 1 route – Route distance (additional stop added between 1st 2 stops) = d0,A(100) + dA,C(125) + dC,B(65) + dB,0(85) = 375 miles d0,A = 100 (A) dA,C = 125 (0) (C) dC,B = 65 dB,0 = 85 (B) Savings value of S = 5 miles saved Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
  • 22. The Savings Method of Routing Combining 3 stops on 1 route – Route distance (additional stop added before 1st 2 stops) = d0,C(25) + dC,A(125) + dA,B(145) + dB,0(85) = 380 miles d0,C = 25 (C) dC,A = 125 (0) (A) dA,B = 145 dB,0 = 85 (B) Savings value of S = 0 miles saved Earlier O to A to B to O route (330 miles) plus 0 to C to 0 route (50 miles) = 380 miles
  • 23.
  • 24. Reduce Fleet Size Traffic Patters Order Tracking Terrain Vehicle Maintainance Costs Save Fuel Scheduling And Prioretisation Faster Deliveries Real Time Dynamic Routing
  • 25. Used By All Large Scale Companies For Transportation Operations
  • 26. REDUCE TARGET INPUTS Like Fuel, Number of Vehicles & Man Power
  • 28.