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answer asap thanks 8 a) What is the heat of the reaction? b) What is the enthalpy of the reaction? 8) How much energy is needed for the reaction of 142 grams CaO in the reaction\" CaO + 3C ? CaC, + CO ?1hn-+464.6 kJ 9) Determine the enthalpy of reaction 2CH, CH +2H, given: C,H +H CH ?1 136 3 kl Solution Number of moles of CaO = weight of CaO / Molar mass of CaO = 142 g / 56 g mol -1 = 2.54 mol According to the given equation, CaO + 3 C -----> CaC 2 + CO , 1 mol of CaO needs 464.6 kJ So 2.54 mol CaO needs = (2.54 mol x 464.6 kJ) / 1 mol = 1178.1 kJ 142 g CaO needs 1178.1 kJ for the reaction to occur. .

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