So for a) I got - Top 10 --- scorers, Is it correct? &any ideas on the other ones Solution Option (a): 1) Function Left returns the given number of characters from left hand side of the string specified. 2) Function Right returns the given number of characters from right hand side of the string specified. 3) Trim function trims the spaces present at both sides of the string. 4) UCase function translates the given string to Upper Case. UCase( Left(o, 1) ) returns T Right(o,5) returns op 10 Trim(p) returns scores Combining all these results in Top 10 --- scores So Content of variable x is Top 10 --- scores _______________________________________________________________________________________________ Option (b): 1) Function Mid returns characters that are in the range of specified numbers. 2) Val function returns the value representation 3) Len function gives the length of the string 4) Str function returns the string representation Val(Mid(o,5,1)) is 1 Len(m & n) is 10 Str(Val(Mid(o,5,1)) + Len(m & n)) results in 11 So Content of variable x is 11 _______________________________________________________________________________________________ Option (c): 1) Function Instr returns an integer specifying the start position of the first occurrence of one string within another string. m & n & o results in string: world cup top 10 Str( InStr( m & n & o, \"10\") ) results in 15 i.e., String 10 is found at 15 position So Content of variable x is 15 .

1. So for a) I got - Top 10 --- scorers, Is it correct? &any ideas on the other ones
Solution
Option (a):
1) Function Left returns the given number of characters from left hand side of the string
specified.
2) Function Right returns the given number of characters from right hand side of the string
specified.
3) Trim function trims the spaces present at both sides of the string.
4) UCase function translates the given string to Upper Case.
UCase( Left(o, 1) ) returns T
Right(o,5) returns op 10
Trim(p) returns scores
Combining all these results in Top 10 --- scores
So Content of variable x is Top 10 --- scores
______________________________________________________________________________
_________________
Option (b):
1) Function Mid returns characters that are in the range of specified numbers.
2) Val function returns the value representation
3) Len function gives the length of the string
4) Str function returns the string representation
Val(Mid(o,5,1)) is 1
Len(m & n) is 10
Str(Val(Mid(o,5,1)) + Len(m & n)) results in 11
So Content of variable x is 11

2. ______________________________________________________________________________
_________________
Option (c):
1) Function Instr returns an integer specifying the start position of the first occurrence of one
string within another string.
m & n & o results in string: world cup top 10
Str( InStr( m & n & o, "10") ) results in 15 i.e., String 10 is found at 15 position
So Content of variable x is 15