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Module 4 Measures of Central Tendency and Dispersion
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Measures Of Central Tendency And Dispersion
[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Measures Of Central Tendency And Dispersion
Measures of Location or Central Tendency  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Properties of a Measure ,[object Object],[object Object],[object Object],[object Object],[object Object]
Mean  ,[object Object],[object Object],[object Object],[object Object]
Arithmetic Mean  Ungrouped (Raw) Data  ns Observatio of Number  ns Observatio of Sum  x n xi  
Illustration 4.1 Table 4.1 : Equity Holdings of 20 Indian Billionaires  ( Rs. in Millions) 2717 2796 3098 3144 3527 3534 3862 4186 4310 4506 4745 4784 4923 5034 5071 5424 5561 6505 6707 6874
Illustration 4.1 For the above data, the A.M. is   2717 + 2796 +……  4645+….. + 5424 + ….+ 6874  =  --------------------------------------------------------------------------   20   =  Rs.  4565.4  Millions   x
Arithmetic Mean  Grouped Data     i i f f i x x
Illustration 4.2 The calculation is illustrated with the data relating to equity holdings of the group of 20 billionaires given in Table 3.1 Class Interval ( 1 ) Frequency ( f i  ) ( 2 ) Mid Value of  Class Interval ( x i  ) ( 3 ) f i x i Col.(4) = Col.(2) x Col.(3) 2000 –  3000 2 2500 5000 3000 –  4000 5 3500 17500 4000 –  5000 6 4500 27000 5000 –  6000 4 5500 22000 6000 –  7000 3 6500 19500         Sum    f i  = 20      f i x i =  91000
Illustration 4.2 values of    f i  and    f i x i  , in formula  =  9100 ÷ 20 =  4550    i i f f i x x
Weighted Arithmetic Mean  if the values x 1 , x 2  x 3 , …. x i , ….x n  have weights w 1 , w 2  w 3 , …. w i , ….,w n  then the weighted mean of x is given as     i i i w x w x
Illustration 4.3 Item Monthly Consumption   Weight (w i ) Rise in Price (Percentage) (p i )   w i p i Sugar 5 5 20 100 Rice 20 20 10 200
Illustration 4.3 Therefore, the average price rise could be evaluated as    =  =  =    =  = 12.  Thus the average price rise is 12 % .  20 5 200 100   25 300   i i i w p w p
Geometric Mean  The Geometric Mean ( G. M.) of a series of observations with x 1 , x 2 , x 3 ,  ……..,x n  is defined as the n th  root of the product of these values . Mathematically  G.M.  =  { ( x 1  )( x 2  )( x 3  )…………….(x n  ) }  (1/ n )   It may be noted that the G.M. cannot be defined if any value of x is  zero  as the whole product of various values becomes zero.
Illustration 4.5  For the data with values, 2,4, and 8,     G.M.  =  (2 x 4 x 8 )  (1/3)     =  (64)  1/3   =  4
Average Rate of Growth of Production/Business or Increase in Prices  If  P 1  is the production in the first year and P n  is the production in the nth year, then the average rate of growth is given by ( G – 100) % where, G  =  100 (P n  / P 1  ) 1/(n-1)     or  log G  =  log 100 + { 1/(n–1) } (log P n  – log P 1 )
Example 4.4 The wholesale price index in the year 2000-01 was 145.3. It increased to 195.5 in the year 2005-06. What has been the average rate of increase in the index during the last 5 years.   Solution: By using the formula ( 4.8), we have  log G =  2 +{ (1/5) ( log 195.5 – log145.3 ) }    = 2.02578 Therefore,   G = Anti log (2.02578) = 106.11 Thus the average rate of increase = 106.11    100 = 6.11%
Combined G.M. of Two Sets of Data    If G 1  & G 2  are the Geometric means of two sets of data, then the combined Geometric mean, say G, of the combined data is given by :   n 1  log G 1  + n 2  log G 2 log G  = -------------------------------   n 1  + n 2
Combined G.M. of Two Sets of Data ,[object Object]
Combined G.M. of Two Sets of Data 5 log 120  +  5 log 115  5 x 2.07918 + 5 x 2.06070 log G =  ------------------------------- =  ----------------------------------   5  +  5   10 20.6994 =  ------------  = 2.06994 10 Therefore,    G  =  antilog  2.06994  =  117.47   Thus the combined average rate of growth for the period of 10 years is 17.47%.
Weighted Geometric Mean  Just like weighted arithmetic mean, we also have weighted Geometric mean If x 1 , x 2 ,….,x i, ….,x n  are n observations with weights w 1 , w 2 , …w i ,.., w n , then their G.M. is defined as:        w i  log x i G.M. =  ----------------------       w i
Harmonic Mean  The harmonic mean (H.M.) is defined as the reciprocal of the arithmetic mean of the reciprocals of the observations.  For example, if x 1  and x 2  are two observations, then the arithmetic means of their reciprocals viz 1/x 1  and 1/ x 2  is      {(1 / x 1 )   + (1 / x 2 )} / 2 = (x 2  + x 1 ) / 2 x 1  x 2 The reciprocal of this arithmetic mean is 2 x 1  x 2  / (x 2  + x 1 ). This is called the harmonic mean.   Thus the harmonic mean of two observations x 1  and x 2  is  2 x 1  x 2 ----------------- x 1  + x 2
Relationship Among A.M.  G.M. and H.M.  The relationships among the magnitudes of the three types of Means calculated from the same data are as follows:   (i) H.M.  ≤  G.M.  ≤ A.M.    i.e. the arithmetic mean is greater than or equal to the geometric which is  greater than or equal to the harmonic mean.  ( ii )  G.M.  =  i.e. geometric mean is the square root of the product of arithmetic mean and  harmonic mean. ( iii)  H.M. =  ( G.M.)  2  / A .M.   . . . M H M A 
Median  ,[object Object],[object Object],[object Object]
Median - Ungrouped Data  First the data is arranged in ascending/descending order.    In the earlier example relating to equity holdings data of 20 billionaires given in Table 4.1, the data is arranged as per ascending order as follows   2717 2796 3098 3144 3527 3534 3862 4187 4310 4506 4745 4784 4923 5034 5071 5424 5561 6505 6707 6874 Here, the number of observations is 20, and therefore there is no middle observation.  However, the two middle most observations are 10 th  and 11 th .  The values are 4506 and 4745.  Therefore, the median is their average.   4506 + 4745  9251  Median  =  -----------------  =  -----------    2  2   =  4625.5   Thus, the median equity holdings of the 20 billionaires is Rs.4625.5 Millions.
Median - Grouped ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Illustration 4.2 Class Interval Frequency Cumulative frequency 2000-3000 2 2 3000-4000 5 7 4000-5000 6 13 5000-6000 4 17 6000-70000 3 20
Illustration 4.2 Here,  n = 20, the median class interval is from 4000 to 5000 as the 10 th  observation lies in this interval. Further,  L m   =  4000   f m   =  6   f c   =  7   w m   =  1000 Therefore,   20/2 –7 x 1000 Median  =  4000 +  -------------------------   6 =  4000 + 3/6 x 1000 =  4000 + 500 =  4500
Median ,[object Object],[object Object]
Graphical Method of Finding the Median   ,[object Object]
Quartiles  ,[object Object],[object Object],[object Object],[object Object]
Quartiles
Quartiles data Q 1  and Q 3  are defined as values corresponding to an observation given below :    Ungrouped Data   Grouped Data (arranged in ascending  or descending order)   Lower Quartile Q 1   {( n + 1 ) / 4 } th   ( n / 4 ) th      Median Q 2     { ( n + 1 ) / 2 } th     ( n / 2 ) th    Upper Quartile Q 3   {3 ( n + 1 ) / 4 }  th   (3 n / 4 ) th
Quartiles 1 1 1 ) 4 / ( 1 Q Q c Q w f f n L Q     3 3 3 ) 4 / 3 ( 3 Q Q c Q w f f n L Q    
Equity Holding Data Class Interval Frequency Cumulative frequency 2000-3000 2 2 3000-4000 5 7 4000-5000 6 13 5000-6000 4 17 6000-70000 3 20
  ( (20/4) – 2   ) Q 1   =  3000 + ---------------    1000   5       ( 5 – 2   ) =  3000 + --------------------    1000    5       3000 =  3000 + -------------    5    =  3000  +  600    =  3600   The interpretation of this value of Q 1  is that 25 % billionaires have equity holdings less than Rs.
    (15 – 13) Q 3   =  -------------    1000 +5000     4       2 =  -------    1000 +5000   4   =  5500 The interpretation of this value of Q 3  is that 75 % billionaires have equity holdings less than Rs. 5500 Millions.
Percentiles    (95/100)    n –  f c P 95   =  L  P95  +  -------------------  x  w P95   f  P95 where,  L  P95  is the lower point of the class interval containing 95 th  percent of total frequency, f c  is the cumulative frequency up to the 95 th  percentile interval,  f  P95  is the frequency of the 95 th  percentile interval and w P95  is the width of the 95 th  percentile interval.
Deciles  ,[object Object]
Mode        f m  -  f 0 Mode  =  L m   +  -----------------    w m  f m  - f 0   - f 2 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Equity Holding Data ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Equity Holding Data ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Empirical Relationship among Mean, Median and Mode  ,[object Object],[object Object],[object Object],[object Object]
Equity Holding Data 4333 4500 4565 (mode) (median) (mean)
Right Skewed Distribution  Mode  Median     Mean
Symmetrical Mode  Median   Mean
Left Skewed Distribution Mean  Median  Mode
Features of a Good Statistical Average  ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Comparison of Measures of Location  Arithmetic Mean Advantages Disadvantages ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],  (i )  Unduly influenced by extreme values  (ii)  Cannot be calculated  from the data with  open-end class- intervals in grouped data or when values of  all observations are available – all that is known that some  observations are either less than or  greater than some value, in  ungrouped  data
Geometric Mean Advantages Disadvantages (i)  Makes use of full data   (ii) Extreme large values have lesser impacts (ii) Useful for data relating to rations and percentage (iv) Useful for rate of change/growth   (i)       Cannot be calculated if    any observation   has the value zero (ii)  Difficult to calculate  and interpret
Median Advantages Disadvantages (i)  Simple to understand  (ii)  Extreme values do not have any impact (iii) Can be calculated even if values of all observations are not known or data has  open-end class intervals (iv) Used for measuring qualities and factors  which are not quantifiable (v)  Can be approximately determined with the help of a graph (ogives) ,[object Object],[object Object],[object Object],[object Object]

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Module4

  • 1. Module 4 Measures of Central Tendency and Dispersion
  • 2.
  • 3.
  • 4.
  • 5.
  • 6.
  • 7. Arithmetic Mean Ungrouped (Raw) Data ns Observatio of Number ns Observatio of Sum  x n xi  
  • 8. Illustration 4.1 Table 4.1 : Equity Holdings of 20 Indian Billionaires ( Rs. in Millions) 2717 2796 3098 3144 3527 3534 3862 4186 4310 4506 4745 4784 4923 5034 5071 5424 5561 6505 6707 6874
  • 9. Illustration 4.1 For the above data, the A.M. is   2717 + 2796 +…… 4645+….. + 5424 + ….+ 6874 = -------------------------------------------------------------------------- 20   = Rs. 4565.4 Millions x
  • 10. Arithmetic Mean Grouped Data    i i f f i x x
  • 11. Illustration 4.2 The calculation is illustrated with the data relating to equity holdings of the group of 20 billionaires given in Table 3.1 Class Interval ( 1 ) Frequency ( f i ) ( 2 ) Mid Value of Class Interval ( x i ) ( 3 ) f i x i Col.(4) = Col.(2) x Col.(3) 2000 – 3000 2 2500 5000 3000 – 4000 5 3500 17500 4000 – 5000 6 4500 27000 5000 – 6000 4 5500 22000 6000 – 7000 3 6500 19500         Sum  f i = 20    f i x i = 91000
  • 12. Illustration 4.2 values of  f i and  f i x i , in formula = 9100 ÷ 20 = 4550    i i f f i x x
  • 13. Weighted Arithmetic Mean if the values x 1 , x 2 x 3 , …. x i , ….x n have weights w 1 , w 2 w 3 , …. w i , ….,w n then the weighted mean of x is given as    i i i w x w x
  • 14. Illustration 4.3 Item Monthly Consumption   Weight (w i ) Rise in Price (Percentage) (p i )   w i p i Sugar 5 5 20 100 Rice 20 20 10 200
  • 15. Illustration 4.3 Therefore, the average price rise could be evaluated as   = = = = = 12. Thus the average price rise is 12 % . 20 5 200 100   25 300   i i i w p w p
  • 16. Geometric Mean The Geometric Mean ( G. M.) of a series of observations with x 1 , x 2 , x 3 , ……..,x n is defined as the n th root of the product of these values . Mathematically G.M. = { ( x 1 )( x 2 )( x 3 )…………….(x n ) } (1/ n ) It may be noted that the G.M. cannot be defined if any value of x is zero as the whole product of various values becomes zero.
  • 17. Illustration 4.5 For the data with values, 2,4, and 8,   G.M. = (2 x 4 x 8 ) (1/3)   = (64) 1/3 = 4
  • 18. Average Rate of Growth of Production/Business or Increase in Prices If P 1 is the production in the first year and P n is the production in the nth year, then the average rate of growth is given by ( G – 100) % where, G = 100 (P n / P 1 ) 1/(n-1)   or log G = log 100 + { 1/(n–1) } (log P n – log P 1 )
  • 19. Example 4.4 The wholesale price index in the year 2000-01 was 145.3. It increased to 195.5 in the year 2005-06. What has been the average rate of increase in the index during the last 5 years.   Solution: By using the formula ( 4.8), we have log G = 2 +{ (1/5) ( log 195.5 – log145.3 ) } = 2.02578 Therefore, G = Anti log (2.02578) = 106.11 Thus the average rate of increase = 106.11  100 = 6.11%
  • 20. Combined G.M. of Two Sets of Data   If G 1 & G 2 are the Geometric means of two sets of data, then the combined Geometric mean, say G, of the combined data is given by : n 1 log G 1 + n 2 log G 2 log G = ------------------------------- n 1 + n 2
  • 21.
  • 22. Combined G.M. of Two Sets of Data 5 log 120 + 5 log 115 5 x 2.07918 + 5 x 2.06070 log G = ------------------------------- = ---------------------------------- 5 + 5 10 20.6994 = ------------ = 2.06994 10 Therefore,   G = antilog 2.06994 = 117.47 Thus the combined average rate of growth for the period of 10 years is 17.47%.
  • 23. Weighted Geometric Mean Just like weighted arithmetic mean, we also have weighted Geometric mean If x 1 , x 2 ,….,x i, ….,x n are n observations with weights w 1 , w 2 , …w i ,.., w n , then their G.M. is defined as:    w i log x i G.M. = ----------------------  w i
  • 24. Harmonic Mean The harmonic mean (H.M.) is defined as the reciprocal of the arithmetic mean of the reciprocals of the observations.  For example, if x 1 and x 2 are two observations, then the arithmetic means of their reciprocals viz 1/x 1 and 1/ x 2 is   {(1 / x 1 ) + (1 / x 2 )} / 2 = (x 2 + x 1 ) / 2 x 1 x 2 The reciprocal of this arithmetic mean is 2 x 1 x 2 / (x 2 + x 1 ). This is called the harmonic mean.   Thus the harmonic mean of two observations x 1 and x 2 is 2 x 1 x 2 ----------------- x 1 + x 2
  • 25. Relationship Among A.M. G.M. and H.M. The relationships among the magnitudes of the three types of Means calculated from the same data are as follows:   (i) H.M. ≤ G.M. ≤ A.M.   i.e. the arithmetic mean is greater than or equal to the geometric which is greater than or equal to the harmonic mean. ( ii ) G.M. = i.e. geometric mean is the square root of the product of arithmetic mean and harmonic mean. ( iii) H.M. = ( G.M.) 2 / A .M. . . . M H M A 
  • 26.
  • 27. Median - Ungrouped Data First the data is arranged in ascending/descending order.   In the earlier example relating to equity holdings data of 20 billionaires given in Table 4.1, the data is arranged as per ascending order as follows   2717 2796 3098 3144 3527 3534 3862 4187 4310 4506 4745 4784 4923 5034 5071 5424 5561 6505 6707 6874 Here, the number of observations is 20, and therefore there is no middle observation. However, the two middle most observations are 10 th and 11 th . The values are 4506 and 4745. Therefore, the median is their average.   4506 + 4745 9251 Median = ----------------- = ----------- 2 2   = 4625.5   Thus, the median equity holdings of the 20 billionaires is Rs.4625.5 Millions.
  • 28.
  • 29. Illustration 4.2 Class Interval Frequency Cumulative frequency 2000-3000 2 2 3000-4000 5 7 4000-5000 6 13 5000-6000 4 17 6000-70000 3 20
  • 30. Illustration 4.2 Here, n = 20, the median class interval is from 4000 to 5000 as the 10 th observation lies in this interval. Further,  L m = 4000   f m = 6   f c = 7   w m = 1000 Therefore, 20/2 –7 x 1000 Median = 4000 + ------------------------- 6 = 4000 + 3/6 x 1000 = 4000 + 500 = 4500
  • 31.
  • 32.
  • 33.
  • 35. Quartiles data Q 1 and Q 3 are defined as values corresponding to an observation given below :   Ungrouped Data Grouped Data (arranged in ascending or descending order)   Lower Quartile Q 1 {( n + 1 ) / 4 } th ( n / 4 ) th      Median Q 2 { ( n + 1 ) / 2 } th ( n / 2 ) th    Upper Quartile Q 3 {3 ( n + 1 ) / 4 } th (3 n / 4 ) th
  • 36. Quartiles 1 1 1 ) 4 / ( 1 Q Q c Q w f f n L Q     3 3 3 ) 4 / 3 ( 3 Q Q c Q w f f n L Q    
  • 37. Equity Holding Data Class Interval Frequency Cumulative frequency 2000-3000 2 2 3000-4000 5 7 4000-5000 6 13 5000-6000 4 17 6000-70000 3 20
  • 38. ( (20/4) – 2 ) Q 1 = 3000 + ---------------  1000 5   ( 5 – 2 ) = 3000 + --------------------  1000 5   3000 = 3000 + ------------- 5   = 3000 + 600   = 3600   The interpretation of this value of Q 1 is that 25 % billionaires have equity holdings less than Rs.
  • 39.   (15 – 13) Q 3 = -------------  1000 +5000 4   2 = -------  1000 +5000 4   = 5500 The interpretation of this value of Q 3 is that 75 % billionaires have equity holdings less than Rs. 5500 Millions.
  • 40. Percentiles (95/100)  n – f c P 95 = L P95 + ------------------- x w P95 f P95 where, L P95 is the lower point of the class interval containing 95 th percent of total frequency, f c is the cumulative frequency up to the 95 th percentile interval, f P95 is the frequency of the 95 th percentile interval and w P95 is the width of the 95 th percentile interval.
  • 41.
  • 42.
  • 43.
  • 44.
  • 45.
  • 46. Equity Holding Data 4333 4500 4565 (mode) (median) (mean)
  • 47. Right Skewed Distribution Mode Median Mean
  • 48. Symmetrical Mode Median Mean
  • 49. Left Skewed Distribution Mean Median Mode
  • 50.
  • 51.
  • 52. Geometric Mean Advantages Disadvantages (i) Makes use of full data   (ii) Extreme large values have lesser impacts (ii) Useful for data relating to rations and percentage (iv) Useful for rate of change/growth   (i)       Cannot be calculated if any observation has the value zero (ii) Difficult to calculate and interpret
  • 53.