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Suppose you get 16 certain fuses from Target, and suppose that the life of each fuse follows a normal distribution with mean 3 years and standard deviation 0.2 years. Find the chance that the average life of those 16 fuses is greater than 3.3 years. Solution The probability is P(xbar>3.3) =P((xbar-mean)/(s/vn) >(3.3-3)/(0.2/4)) =P(Z>6) =0 (From standard normal table).

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Suppose you get 16 certain fuses from Target, and suppose that the life of each fuse follows a normal distribution with mean 3 years and standard deviation 0.2 years. Find the chance that the average life of those 16 fuses is greater than 3.3 years. Solution The probability is P(xbar>3.3) =P((xbar-mean)/(s/vn) >(3.3-3)/(0.2/4)) =P(Z>6) =0 (From standard normal table).

- 1. Suppose you get 16 certain fuses from Target, and suppose that the life of each fuse follows a normal distribution with mean 3 years and standard deviation 0.2 years. Find the chance that the average life of those 16 fuses is greater than 3.3 years. Solution The probability is P(xbar>3.3) =P((xbar-mean)/(s/vn) >(3.3-3)/(0.2/4)) =P(Z>6) =0 (From standard normal table)