The function of the amount of soft drink in a can is f(x) = 4cx for .pdf

A
amolmobileshop
••
Educação

The function of the amount of soft drink in a can is f(x) = 4cx for 11.5 < X < 12.5 oz. c=1/48 find the following Probabilities: Please show how to find the following A. P( Solution A ) P(mu-s < X < mu + s) = P( -1 < (x-mu) /s < 1) = 0.6826 B ) P(mu-2s < X < mu + 2s) = P( -2 < (x-mu) /s < 2) = 0.9544 C )P(mu-3s < X < mu + 3s) = P( -3 < (x-mu) /s < 3) = 0.9974.

The function of the amount of soft drink in a can is f(x) = 4cx for .pdf

••
A
amolmobileshop
Educação

The function of the amount of soft drink in a can is f(x) = 4cx for 11.5 < X < 12.5 oz. c=1/48 find the following Probabilities: Please show how to find the following A. P( Solution A ) P(mu-s < X < mu + s) = P( -1 < (x-mu) /s < 1) = 0.6826 B ) P(mu-2s < X < mu + 2s) = P( -2 < (x-mu) /s < 2) = 0.9544 C )P(mu-3s < X < mu + 3s) = P( -3 < (x-mu) /s < 3) = 0.9974.

The function of the amount of soft drink in a can is f(x) = 4cx for .pdf

1 de 1
The function of the amount of soft drink in a can is f(x) = 4cx for 11.5 < X < 12.5 oz. c=1/48 find the following Probabilities: Please show how to find the following A. P( Solution A ) P(mu-s < X < mu + s) = P( -1 < (x-mu) /s < 1) = 0.6826 B ) P(mu-2s < X < mu + 2s) = P( -2 < (x-mu) /s < 2) = 0.9544 C )P(mu-3s < X < mu + 3s) = P( -3 < (x-mu) /s < 3) = 0.9974

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The function of the amount of soft drink in a can is f(x) = 4cx for .pdf

  • 1. The function of the amount of soft drink in a can is f(x) = 4cx for 11.5 < X < 12.5 oz. c=1/48 find the following Probabilities: Please show how to find the following A. P( Solution A ) P(mu-s < X < mu + s) = P( -1 < (x-mu) /s < 1) = 0.6826 B ) P(mu-2s < X < mu + 2s) = P( -2 < (x-mu) /s < 2) = 0.9544 C )P(mu-3s < X < mu + 3s) = P( -3 < (x-mu) /s < 3) = 0.9974