Calculate the t value for the following hypothesis, given the sample outcomes indicated a) null hypotheis:11, alt hypothesis : <>11, x=12.2, std deviation= 8.9 , n=40 b)null hypotheis:11, alt hypothesis : <>11, x=14.0 std deviation= 8.9 , n=40 c)null hypotheis:11, alt hypothesis : <>11, x=13.7, std deviation= 8.9 , n=40 Determine the probablity of t in each example above, and decide if you accept or reject the null hypothesis. Solution a) u=11 x=12.2 s=8.9 n=40 t = (x-u) / (s/sqrt(n)) t = 0.8527 P-value = 0.40 b) u=11 x=14 s=8.9 n=40 t = (x-u) / (s/sqrt(n)) t = 2.1318 P-value = 0.04 c) u=11 x=13.7 s=8.9 n=40 t = (x-u) / (s/sqrt(n)) t = 1.9186 P-value = 0.06 We reject H0 when p-value is less than 0.05 in case b) only we reject null hypothesis in other cases we fail to reject null hypothesis.