2. A homozygous round seed crosses with
a homozygous wrinkled seed. Give the
genotype and the phenotype of the
offspring.
Answer:
Phenotype: 100% Round Seed
Genotype: 100% Heterozygous Dominant
Round Seed
3. A heterozygous brown eyed man marries
a blue eyed woman, give the genotypic
and phenotypic ratio of their offspring.
Answer:
Phenotypic: 50% Brown Eyed
50% Blue Eyed
Genotype: 50% Heterozygous Dominant
Brown Eyed
50% Recessive Blue Eyed
4.
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10.
11.
12.
13.
14. Does this mean
that Mendel’s Laws
of Inheritance are
incorrect?!
Let’s discover with our
next activity!
15. Criteria for Group Activity
Work Content 40%
Creativity 20%
Teamwork 20%
Presentation/ Clarity
of Information
20%
TOTAL 100%
16. In Japan a “Four o’clock
Flower” usually has
allele of a Red Flower
and allele of a White
Flower.
However when crossed,
all the f1 hybrids have
a Pink Flower.
17. In this case, the f1
hybrids have an
appearance
somewhat in
between the
phenotypes of the
two parental
varieties.
18. Setting Up a Punnet Square for this
situation:
Use all capital letters.
Use 2 different letters, one per variation.
The heterozygote will look blended.
Example:
Homozygous Dominant #1 = AA (Red Flower)
Homozygous Dominant #2 = BB (White Flower)
Heterozygous = AB (Pink Flower)
19. Coat colors
in cows usually
appear in two
alleles, White and
Red Coats.
However, when
crossed F1 Hybrid
resulted to Roan
(white with red
patches)
offspring.
20. In this case, both parental varieties appear together
in f1 hybrids.
Setting up a punnet square for this situation:
Use all capital letters.
Use 2 different letters, one per variation.
The heterozygote will show both colors/traits at the
same time, in patches.
Example:
Homozygous Dominant #1 = AA (Red Coat)
Homozygous Dominant #2 = BB (WhiteCoat)
Heterozygous = AB (Roan,White with Red patches)
21. Colorblindness is one
of the recessive
gene traits that are
carried on x-
chromosome.
These are often the
types of traits that
appear to “skip”
generations or
genders, or often
show up more
frequently in males.
Genotypes Phenotypes
1. XX Normal female
2. XXc
Normal
female,carrier of the
gene
3.XcXc Color-blind female
4. XY Normal male
5. XcY Color-blind male
22. Setting up a punnet square
First write the sex chromosomes per the gender of the
individual.
Then figure out the genotype for the trait.
w/o exponent= Normal (dominant)
c= Colorblind (recessive)
Write the allele-letters like exponents on the sex
chromosomes.
“X-Linked” means it’s only on the x chromosome.
“Carrier” refers to a female who is heterozygous. She
“carries” the recessive trait, but doesn’t show it.