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TYPES OF ORGANIC
CHEMICAL REACTIONS
Categories of Simple Organic
Reactions
• Substitution
• Addition
• Condensation/elimination
• Hydrolysis
• Mild oxidation & strong oxidation
• Combustion
• Acid/base reactions
Substitution Reactions
A substitution reaction occurs whenever one
atom of an organic molecule is replaced
by another.
Substitution reactions often require heat
and/or a catalyst in order to occur.
Example: Substitution of an alkane
H H
H C H + Cl2 H C Cl + HCl
H H
HEAT
 
Substitution of Benzene
FeBr catalyst3..
 
Due to the strong bonding arrangement between the carbon atoms
in a benzene ring, the ring cannot be easily broken during
chemical changes. The hydrogen atoms that are bonded to each
carbon can be substituted for other atoms and groups.
Examples:
+ Br2
+ HBr
BrH
+ HNO3
H SO2 4
  NO2 + H2O
TNT synthesis…
Addition Reactions
• In addition reactions, new atoms or groups are
bonded to the atoms of an organic molecule.
The organic molecule must be unsaturated to
start with (double or triple bonds!)
• New bonds can be made to the carbon atoms
involved in the double or triple bond if the part
of the bond is first broken.

CH2=CH2
breakpibond
 
I’m now ready
to make more
bonds!
C C
H
H
H
H

Some Simple Addition Reactions
C=C
H H
H H
+ H2  H-C-C-H
H H
H H
(a.k.a. “hydrogenation”)
C=C
H H
H H
+ HCl  H-C-C-Cl
H H
H H
C=C
H H
H H
+ H2O  H-C-C-OH
H H
H H
(a.k.a. “hydrolysis”)
Testing for unsaturated
hydrocarbons
• Unsaturated hydrocarbons can be
identified by their reaction with aqueous
bromine, Br2(aq).
Demo!
C=C
H H
H H
+ Br2  Br-C-C-Br
H H
H H
(deep orange)  (colourless)
Completely saturated molecules DO NOT react
in this manner- thus the orange colour remains.
Markovnikov’s Rule
• If the double or triple bond is part of a molecule
with three or more carbon atoms in the chain,
the most likely addition reaction products can be
predicted using a rule first formulated by the
Russian chemist V.V. Markovnikov.
Markovnikov’s Rule
…the more electronegative atom will
predominantly bond to the carbon atom of
the double bond that has fewer hydrogen
atoms.
Markovnikov’s Rule
C=C-CH3
H
H H
+ H2O 
H- C - C- CH3
H
HH
OH
It should be mentioned that the primary
alcohol (1-propanol) is also a possibility, but
it would be produced in a much lower
proportion than the 2-propanol shown
above.
H-C C-CH2-CH3 + 2HCl  H-C C-CH2-CH3-
Cl
Cl
H
H
Most favoured product!
Eg.1
Eg.2
Condensation/Elimination
Reactions
• Organic compounds containing hydroxyl or
carboxyl groups can combine by eliminating a
molecule of water between them.
Example 1- condensation of two alcohols
H-C - C-O-H
H
H
H
H
+ H-O-C - C-H
H
H
H
H
Molecule of H2O is formed
H SO2 4
  H-C - C-O-C–C-H
H
H
H
H
H
H
H
H
+ H2O
An ether is created!
Condensation/elimination
• When an alcohol reacts with a carboxylic acid to
eliminate a molecule of water between them, the
resulting bond creates an ester linkage as
shown below:
H-C - C-O-H
H
H
H
H
H-O-C – CH2-CH3
O
+
CH2-CH2- O- C-CH2-CH3
O
+
H2O
We’ve created an ester
If excess water is
added to an ester, the
reaction will reverse
itself.
Uses of Esters
• Esters often have characteristic flavours and
aromas which allows them to be used in food
products.
• Methanol + butanoic acid  methyl butanoate (apples)
• Octanol + acetic acid  octyl acetate (orange)
• Benzyl alcohol + butanoic acid  phenyl butanoate (flowers)
• Pentanol + acetic acid  pentyl acetate
Demo!
Condensation/elimination
• If a molecule of water is eliminated from within a
single molecule, an unsaturated compound is
formed and the molecule is said to be
“dehydrated.”
H
OH
H SO2 4
 
H
H
H
H
+ H2O
Oxidation Reactions
• In the terminology of organic chemistry, when a
molecule is oxidized, the number bonds to oxygen
atoms increases within the molecule.
• Oxidizing agents are varied: CrO3/H+, KMnO4,
K2Cr2O7
• Often, the oxidizing agent is represented simply
as “O” over the reaction arrow:
O
 
Oxidation Reactions
Mild Oxidation
1o alcohol mild O..
  aldehyde
CH3-C-OH
H
H
mild O..
 
ethanol
CH3-C-H
O
ethanal
Strong Oxidation
1o alcohol strong O..
  Carboxylic acid
CH3-C-OH
H
H
strong O..
  CH3-C-OH
O
Ethanoic acid
Oxidation Reactions
Strong Oxidation cont’d…
• Secondary alcohols require a strong oxidizing
agent and can only be oxidized to ketones.
CH3-C-CH2-CH3
O
butanone
•Tertiary alcohols DO NOT undergo oxidation. Why not?
CH3-C-CH2-CH3
H
OH
2-butanol
strong O..
 
OH
CH3-C-CH3
CH3
2-methyl-2-propanol
strong O..
  NO REACTION
DEMOS!
Combustion
• All organic compounds can be combusted or
burned. Carbon dioxide gas and water vapour
are the products of hydrocarbon combustion.
• Combustion is really a type of very extreme
oxidation reaction where O2(g) is the oxidizing
agent.
2C2H2(g) + 5O2(g)  4CO2(g) + 2H2O(g)
CH3-CH2-OH(l) + 3O2(g)  2CO2(g) + 3H2O(g)
BOOM!
Reactions of Organic Acids
• Like inorganic acids such as HCl(aq), organic
acids react with bases to produce liquid water
and a salt.
Example:
C-O-H
O
Benzoic acid
+ NaOH 
C-O1-Na1+
O
Sodium benzoate
+ H2O
Types of organic_chemical_reactions_1

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Types of organic_chemical_reactions_1

  • 2. Categories of Simple Organic Reactions • Substitution • Addition • Condensation/elimination • Hydrolysis • Mild oxidation & strong oxidation • Combustion • Acid/base reactions
  • 3. Substitution Reactions A substitution reaction occurs whenever one atom of an organic molecule is replaced by another. Substitution reactions often require heat and/or a catalyst in order to occur. Example: Substitution of an alkane H H H C H + Cl2 H C Cl + HCl H H HEAT  
  • 4. Substitution of Benzene FeBr catalyst3..   Due to the strong bonding arrangement between the carbon atoms in a benzene ring, the ring cannot be easily broken during chemical changes. The hydrogen atoms that are bonded to each carbon can be substituted for other atoms and groups. Examples: + Br2 + HBr BrH + HNO3 H SO2 4   NO2 + H2O TNT synthesis…
  • 5. Addition Reactions • In addition reactions, new atoms or groups are bonded to the atoms of an organic molecule. The organic molecule must be unsaturated to start with (double or triple bonds!) • New bonds can be made to the carbon atoms involved in the double or triple bond if the part of the bond is first broken.  CH2=CH2 breakpibond   I’m now ready to make more bonds! C C H H H H 
  • 6. Some Simple Addition Reactions C=C H H H H + H2  H-C-C-H H H H H (a.k.a. “hydrogenation”) C=C H H H H + HCl  H-C-C-Cl H H H H C=C H H H H + H2O  H-C-C-OH H H H H (a.k.a. “hydrolysis”)
  • 7. Testing for unsaturated hydrocarbons • Unsaturated hydrocarbons can be identified by their reaction with aqueous bromine, Br2(aq). Demo! C=C H H H H + Br2  Br-C-C-Br H H H H (deep orange)  (colourless) Completely saturated molecules DO NOT react in this manner- thus the orange colour remains.
  • 8. Markovnikov’s Rule • If the double or triple bond is part of a molecule with three or more carbon atoms in the chain, the most likely addition reaction products can be predicted using a rule first formulated by the Russian chemist V.V. Markovnikov. Markovnikov’s Rule …the more electronegative atom will predominantly bond to the carbon atom of the double bond that has fewer hydrogen atoms.
  • 9. Markovnikov’s Rule C=C-CH3 H H H + H2O  H- C - C- CH3 H HH OH It should be mentioned that the primary alcohol (1-propanol) is also a possibility, but it would be produced in a much lower proportion than the 2-propanol shown above. H-C C-CH2-CH3 + 2HCl  H-C C-CH2-CH3- Cl Cl H H Most favoured product! Eg.1 Eg.2
  • 10. Condensation/Elimination Reactions • Organic compounds containing hydroxyl or carboxyl groups can combine by eliminating a molecule of water between them. Example 1- condensation of two alcohols H-C - C-O-H H H H H + H-O-C - C-H H H H H Molecule of H2O is formed H SO2 4   H-C - C-O-C–C-H H H H H H H H H + H2O An ether is created!
  • 11. Condensation/elimination • When an alcohol reacts with a carboxylic acid to eliminate a molecule of water between them, the resulting bond creates an ester linkage as shown below: H-C - C-O-H H H H H H-O-C – CH2-CH3 O + CH2-CH2- O- C-CH2-CH3 O + H2O We’ve created an ester If excess water is added to an ester, the reaction will reverse itself.
  • 12. Uses of Esters • Esters often have characteristic flavours and aromas which allows them to be used in food products. • Methanol + butanoic acid  methyl butanoate (apples) • Octanol + acetic acid  octyl acetate (orange) • Benzyl alcohol + butanoic acid  phenyl butanoate (flowers) • Pentanol + acetic acid  pentyl acetate Demo!
  • 13. Condensation/elimination • If a molecule of water is eliminated from within a single molecule, an unsaturated compound is formed and the molecule is said to be “dehydrated.” H OH H SO2 4   H H H H + H2O
  • 14. Oxidation Reactions • In the terminology of organic chemistry, when a molecule is oxidized, the number bonds to oxygen atoms increases within the molecule. • Oxidizing agents are varied: CrO3/H+, KMnO4, K2Cr2O7 • Often, the oxidizing agent is represented simply as “O” over the reaction arrow: O  
  • 15. Oxidation Reactions Mild Oxidation 1o alcohol mild O..   aldehyde CH3-C-OH H H mild O..   ethanol CH3-C-H O ethanal Strong Oxidation 1o alcohol strong O..   Carboxylic acid CH3-C-OH H H strong O..   CH3-C-OH O Ethanoic acid
  • 16. Oxidation Reactions Strong Oxidation cont’d… • Secondary alcohols require a strong oxidizing agent and can only be oxidized to ketones. CH3-C-CH2-CH3 O butanone •Tertiary alcohols DO NOT undergo oxidation. Why not? CH3-C-CH2-CH3 H OH 2-butanol strong O..   OH CH3-C-CH3 CH3 2-methyl-2-propanol strong O..   NO REACTION DEMOS!
  • 17. Combustion • All organic compounds can be combusted or burned. Carbon dioxide gas and water vapour are the products of hydrocarbon combustion. • Combustion is really a type of very extreme oxidation reaction where O2(g) is the oxidizing agent. 2C2H2(g) + 5O2(g)  4CO2(g) + 2H2O(g) CH3-CH2-OH(l) + 3O2(g)  2CO2(g) + 3H2O(g) BOOM!
  • 18. Reactions of Organic Acids • Like inorganic acids such as HCl(aq), organic acids react with bases to produce liquid water and a salt. Example: C-O-H O Benzoic acid + NaOH  C-O1-Na1+ O Sodium benzoate + H2O