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STANI MEMORIAL COLLEGE OF ENGINEERING & TECHNOLOGY
POWER SYSTEM DESIGN LAB
EXPERIMENT NO. 3

Aim: - Distribution system Design: Design of feeders & distributors. Calculation of voltage
drops in distributors, Calculation of conductor size using Kelvin’s law.

Apparatus Requirements: - Feeder, Conductors, Distributors, Service mains.
Theory: - Distribution system may be divided in to two systems known as High voltage or
Primary distribution system and Low voltage or Secondary distribution system.

Primary Distribution System: - It is that part of A.C. distribution system which operates at
voltages (such as 3.3, 6.6, 11kV or higher than) that of general utility and handle larger block of
power. Primary distribution system is carried out by 3-ϕ, 3-Wire system.
The 33/11 kV secondary substations are usually located in the area having load requirement
5MVA and normally a primary distribution line or a feeder is designed to carry a load of 1-2
MVA. So the number of feeder emanating from a secondary substation of 33/11 kV is 3-4. For
load exceeding 8MVA the secondary transmission is carried out at 66 kV so as to reduce the line
losses and therefore secondary substations is 6-8. The feeders may be radial, parallel, ring or
interconnected.

1) Radial Feeder: - A radial feeder connects between a source and a load point, and it may
supply one or more additional load points between the two. Each load point can be
supplied from one direction only. Radial feeders are most widely used by the Navy
because the circuits are simple, easy to protect, and low in cost. Radial feeder shown in Fig
3.1.

2) Parallel Feeder: - Parallel feeders connect the source and a load or load centre and
provide the capability of supplying power to the load through one or any number of the
parallel feeders. Parallel feeders provide for maintenance of feeders (without interrupting
service to loads) and quick restoration of service when one of the feeders fails. Parallel
feeder shown in Fig. 3.2.
3) Loop Feeder: - A loop feeder has its ends connected to a source (usually a single source),
but its main function is to supply two or more load points in between. Each load point can
be supplied from either direction; so it is possible to remove any section of the loop from
service without causing an outage at other load points. The loop can be operated normally
closed or normally open. Most loop systems are, however, operated normally open at some
point by means of a switch. The operation is very similar to that of two radial feeders.
Loop feeder shown in Fig 3.3.

4) Interconnected Network System: - A distribution system with multiple available power
sources that can loop throughout the network. If one source goes down, a different source
can be activated to maintain service.

Secondary Distribution System: - The secondary distribution system is that portion of the
network between the primary feeders and utilization equipment. The secondary system consists of
step-down transformers and secondary circuits at utilization voltage levels.
Residential secondary systems are predominantly single-phase, but commercial and industrial
systems generally use three-phase power.
1) 3-Φ, 4-Wire Distribution System
2) 1-Φ, 2-Wire Distribution System

Distributors:1. Distributor fed at one end: - In this type of feeding, the distributor is connected to the
supply at one end and loads are taken at different points along the length of the distributor.
Fig.3.4 shows the single line diagram of a D.C. distributor AB fed at the end A (also
known as singly fed distributor) and loads I1 , I2 and I3 tapped off at points C, D and E
respectively.

2. Distributor fed at both ends: - In this type of feeding, the distributor is connected to the
supply mains at both ends and loads are tapped off at different points along the length of
the distributor. The voltage at the feeding points may or may not be equal. Fig.2 shows a
distributor AB fed at the ends A and B and loads of I1, I2 and I3 tapped off at points C, D
and E, respectively. Here, the load voltage goes on decreasing as we move away from one
feeding point say A, reaches minimum value and then again starts rising and reaches
maximum value when we reach the other feeding point. The minimum voltage occurs at
some load point and is never fixed. It is shifted with the variation of load on different
sections of the distributor.
Kelvin’s law:A transmission line can be designed by taking into consideration various factors out of which
economy is the most important factor. The conductor which is to be selected for a give
transmission line must be economical. Most of the part of the total line cost is spent for conductor.
Thus it becomes vital to select most economic size of conductor.
The most economic design of the line is that for which total annual cost is minimum. Total annual
cost is divided into two parts viz. fixed standing charges and running charges.
The fixed charges include the depreciation, the interest on capital cost of conductor and
maintenance cost. The cost electrical energy wasted due to losses during operation constitutes
running charges.
The capital cost and cost of energy wasted in the line is based on size of the conductor. If
conductor size is big then due to its lesser resistance, the running cost (cost of energy due to
losses) will be lower while the conductor may be expensive. For smaller size conductor, its cost is
less but running cost will be more as it will have more resistance and hence greater losses.
The cost of energy loss is inversely proportional to the conductor cross section while the fixed
charges (cost of conductor, interest and depreciation charges) are directly proportional to area of
cross section of the conductor. Mathematically we have,
Annual interest and depreciation cost = S1
S1 α a
a is area of cross section of conductor
S 1 = K1 a
Annual cost of energy loss in line = S2
S2 α

S2 = K2/a
Here K1 and K2 are constants
S = Total annual cost
S = S1 + S2
...

S = K1 a + K2/a

For economical design of line, the cost will be minimum for a particular value of area of crosssection 'a' of the conductor.
Thus for economic design, dS/da = 0
K1 - K2/a2 = 0
...

K1 = K2/a2

...

K1a = K2/a

...

S1 = S2
The most economical conductor size, a = √ (K2/K1)
Thus the most economical conductor size is one for which annual cost of energy loss is equal

to annual interest and depreciation on the capital investment of the conductor material. This is
known as Kelvin's law.

Limitation of Kelvin's Law: - Following are limitations in applying Kelvin's law.

a. The amount of energy loss cannot be determined accurately as the load factors of the
losses and the load are not same. Also the future load conditions and load factors cannot be
predicated exactly.
b. The cost of energy loss cannot be determined exactly. The cost of losses per unit is more
than the generating cost per unit.
c. The cost of conductor and rates of interest are changing continuously.
d. 4. If economical conductor size is selected then voltage drop may be beyond the
acceptable limits.
e. The economical size of conductor may not have the enough mechanical strength.
f. The cost of conductor also includes to some extent cost of insulation which changes with
change in cross section of conductor. The cost of insulation is difficult to express in terms
of cross section of conductor.
g. Due to problem of corona, leakage currents, the economic size of conductor cannot be
used at extra voltages.
h. Due to change in rates of interest and depreciation continuously, even if other parameters
are same, application of Kelvin's law will give economical conductor size different at
different time and in different countries.
Circuit Diagrams:-

Fig 3.1 Radial feeder

Fig 3.2 Parallel Feeder

Fig. 3.4 Distributor fed at one end

Fig. 3.5 Distributor fed at both ends

Fig. 3.6 Kelvin’s Law

Fig 3.3 Loop Feeder
Precautions:1. System design should be proper and reliable
2. System design must be in such a way that fault probability very less.
3. Operating voltage should be taken according to load requirements and losses.

Procedure:-

Observation Table:-

Calculation:-

Result: - We have successfully studied about distribution system design, design of feeders &
distributors. Calculation of voltage drops in distributors, Calculation of conductor size using
Kelvin’s law.
Viva- Voice Questions:Ques. 1 What is the Function of feeder?
Ques.2 How many types of Feeder? And Name of all feeders.
Ques. 3 Discuss any two limitations of Kelvin’s Law.
Ques. 4 Write final Expression of Kelvin’s Law.
Viva- Voice Answers:Ans. 1 Feeders are the conductors which connect the stations to the areas to be fed by those
stations. Generally from feeders no tapping is taken to the consumers, therefore, current loading of
a feeder remains the same along its length. It is designed mainly from the point of view of its
current carrying capacity.
Ans. 2 Mainly 3 types of feeder
Radial Feeder
Parallel Feeder
Loop Feeder

Ans. 3
a. The amount of energy loss cannot be determined accurately as the load factors of the
losses and the load are not same. Also the future load conditions and load factors cannot be
predicated exactly.
b. The cost of energy loss cannot be determined exactly. The cost of losses per unit is more
than the generating cost per unit.

Ans. 4
K1a = K2/a

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Lab manual psd v sem experiment no 3

  • 1. STANI MEMORIAL COLLEGE OF ENGINEERING & TECHNOLOGY POWER SYSTEM DESIGN LAB EXPERIMENT NO. 3 Aim: - Distribution system Design: Design of feeders & distributors. Calculation of voltage drops in distributors, Calculation of conductor size using Kelvin’s law. Apparatus Requirements: - Feeder, Conductors, Distributors, Service mains. Theory: - Distribution system may be divided in to two systems known as High voltage or Primary distribution system and Low voltage or Secondary distribution system. Primary Distribution System: - It is that part of A.C. distribution system which operates at voltages (such as 3.3, 6.6, 11kV or higher than) that of general utility and handle larger block of power. Primary distribution system is carried out by 3-ϕ, 3-Wire system. The 33/11 kV secondary substations are usually located in the area having load requirement 5MVA and normally a primary distribution line or a feeder is designed to carry a load of 1-2 MVA. So the number of feeder emanating from a secondary substation of 33/11 kV is 3-4. For load exceeding 8MVA the secondary transmission is carried out at 66 kV so as to reduce the line losses and therefore secondary substations is 6-8. The feeders may be radial, parallel, ring or interconnected. 1) Radial Feeder: - A radial feeder connects between a source and a load point, and it may supply one or more additional load points between the two. Each load point can be supplied from one direction only. Radial feeders are most widely used by the Navy because the circuits are simple, easy to protect, and low in cost. Radial feeder shown in Fig 3.1. 2) Parallel Feeder: - Parallel feeders connect the source and a load or load centre and provide the capability of supplying power to the load through one or any number of the parallel feeders. Parallel feeders provide for maintenance of feeders (without interrupting service to loads) and quick restoration of service when one of the feeders fails. Parallel feeder shown in Fig. 3.2.
  • 2. 3) Loop Feeder: - A loop feeder has its ends connected to a source (usually a single source), but its main function is to supply two or more load points in between. Each load point can be supplied from either direction; so it is possible to remove any section of the loop from service without causing an outage at other load points. The loop can be operated normally closed or normally open. Most loop systems are, however, operated normally open at some point by means of a switch. The operation is very similar to that of two radial feeders. Loop feeder shown in Fig 3.3. 4) Interconnected Network System: - A distribution system with multiple available power sources that can loop throughout the network. If one source goes down, a different source can be activated to maintain service. Secondary Distribution System: - The secondary distribution system is that portion of the network between the primary feeders and utilization equipment. The secondary system consists of step-down transformers and secondary circuits at utilization voltage levels. Residential secondary systems are predominantly single-phase, but commercial and industrial systems generally use three-phase power. 1) 3-Φ, 4-Wire Distribution System 2) 1-Φ, 2-Wire Distribution System Distributors:1. Distributor fed at one end: - In this type of feeding, the distributor is connected to the supply at one end and loads are taken at different points along the length of the distributor. Fig.3.4 shows the single line diagram of a D.C. distributor AB fed at the end A (also known as singly fed distributor) and loads I1 , I2 and I3 tapped off at points C, D and E respectively. 2. Distributor fed at both ends: - In this type of feeding, the distributor is connected to the supply mains at both ends and loads are tapped off at different points along the length of the distributor. The voltage at the feeding points may or may not be equal. Fig.2 shows a distributor AB fed at the ends A and B and loads of I1, I2 and I3 tapped off at points C, D and E, respectively. Here, the load voltage goes on decreasing as we move away from one feeding point say A, reaches minimum value and then again starts rising and reaches maximum value when we reach the other feeding point. The minimum voltage occurs at some load point and is never fixed. It is shifted with the variation of load on different sections of the distributor.
  • 3. Kelvin’s law:A transmission line can be designed by taking into consideration various factors out of which economy is the most important factor. The conductor which is to be selected for a give transmission line must be economical. Most of the part of the total line cost is spent for conductor. Thus it becomes vital to select most economic size of conductor. The most economic design of the line is that for which total annual cost is minimum. Total annual cost is divided into two parts viz. fixed standing charges and running charges. The fixed charges include the depreciation, the interest on capital cost of conductor and maintenance cost. The cost electrical energy wasted due to losses during operation constitutes running charges. The capital cost and cost of energy wasted in the line is based on size of the conductor. If conductor size is big then due to its lesser resistance, the running cost (cost of energy due to losses) will be lower while the conductor may be expensive. For smaller size conductor, its cost is less but running cost will be more as it will have more resistance and hence greater losses. The cost of energy loss is inversely proportional to the conductor cross section while the fixed charges (cost of conductor, interest and depreciation charges) are directly proportional to area of cross section of the conductor. Mathematically we have, Annual interest and depreciation cost = S1 S1 α a a is area of cross section of conductor S 1 = K1 a Annual cost of energy loss in line = S2 S2 α S2 = K2/a Here K1 and K2 are constants S = Total annual cost S = S1 + S2 ... S = K1 a + K2/a For economical design of line, the cost will be minimum for a particular value of area of crosssection 'a' of the conductor. Thus for economic design, dS/da = 0
  • 4. K1 - K2/a2 = 0 ... K1 = K2/a2 ... K1a = K2/a ... S1 = S2 The most economical conductor size, a = √ (K2/K1) Thus the most economical conductor size is one for which annual cost of energy loss is equal to annual interest and depreciation on the capital investment of the conductor material. This is known as Kelvin's law. Limitation of Kelvin's Law: - Following are limitations in applying Kelvin's law. a. The amount of energy loss cannot be determined accurately as the load factors of the losses and the load are not same. Also the future load conditions and load factors cannot be predicated exactly. b. The cost of energy loss cannot be determined exactly. The cost of losses per unit is more than the generating cost per unit. c. The cost of conductor and rates of interest are changing continuously. d. 4. If economical conductor size is selected then voltage drop may be beyond the acceptable limits. e. The economical size of conductor may not have the enough mechanical strength. f. The cost of conductor also includes to some extent cost of insulation which changes with change in cross section of conductor. The cost of insulation is difficult to express in terms of cross section of conductor. g. Due to problem of corona, leakage currents, the economic size of conductor cannot be used at extra voltages. h. Due to change in rates of interest and depreciation continuously, even if other parameters are same, application of Kelvin's law will give economical conductor size different at different time and in different countries.
  • 5. Circuit Diagrams:- Fig 3.1 Radial feeder Fig 3.2 Parallel Feeder Fig. 3.4 Distributor fed at one end Fig. 3.5 Distributor fed at both ends Fig. 3.6 Kelvin’s Law Fig 3.3 Loop Feeder
  • 6. Precautions:1. System design should be proper and reliable 2. System design must be in such a way that fault probability very less. 3. Operating voltage should be taken according to load requirements and losses. Procedure:- Observation Table:- Calculation:- Result: - We have successfully studied about distribution system design, design of feeders & distributors. Calculation of voltage drops in distributors, Calculation of conductor size using Kelvin’s law.
  • 7. Viva- Voice Questions:Ques. 1 What is the Function of feeder? Ques.2 How many types of Feeder? And Name of all feeders. Ques. 3 Discuss any two limitations of Kelvin’s Law. Ques. 4 Write final Expression of Kelvin’s Law.
  • 8. Viva- Voice Answers:Ans. 1 Feeders are the conductors which connect the stations to the areas to be fed by those stations. Generally from feeders no tapping is taken to the consumers, therefore, current loading of a feeder remains the same along its length. It is designed mainly from the point of view of its current carrying capacity. Ans. 2 Mainly 3 types of feeder Radial Feeder Parallel Feeder Loop Feeder Ans. 3 a. The amount of energy loss cannot be determined accurately as the load factors of the losses and the load are not same. Also the future load conditions and load factors cannot be predicated exactly. b. The cost of energy loss cannot be determined exactly. The cost of losses per unit is more than the generating cost per unit. Ans. 4 K1a = K2/a