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ENGINEERING GRAPHICS
PLAIN SCALE
DIAGONAL SCALE
Reduced scale:
Dimensions of large
objects must be
reduced to draw on
standard size
drawing sheet.
Example:
Map Of any country
Enlarged scale:
Similarly in case of
tiny small objects
dimensions must be
increased to draw
on drawing sheet.
Example: Drawing
of wrist watch
parts.
Plain scale
A plain scale consists of a line divided into suitable number of
equal units. The first unit is subdivided into smaller parts.
The plain scales give only two dimensions, such as a unit
and it's subunit or it's fraction.
LENGTH OF SCALE = (R.F. ) × (MAX. LENGTH TO BE MEASURED.)
PROBLEM NO.1
Draw a scale 1 cm = 1 meter to read meters and decimeters,
to measure maximum distance of 6 m.
Show on it a distance of 4 m and 6 dm.
SOLUTION:-
 R.F.= 1cm/ 1meter = 1/100
We know that, 1 meter = 10 decimeter = 100 cm
 Length of scale = (R.F.) X max. distance
= 1/100 X 600 cm
= 6 cms
……ANSWER
Take height of scale 5 mm to 10 mm for getting a look of
scale
PROBLEM NO.2
In a map a 36 km distance is shown by a line 45 cms long.
Calculate the R.F. and Construct a plain scale to read kilometers
and hectometers, for measuring maximum 12 km distance.
Show a distance of 8.3 km on it.
CONSTRUCTION:-
Calculate R.F.
R.F.= 45 cm/ 36 km
= 45 cm/ (36 × 1000 × 100)cm
= 1/ 80,000
Length of scale = (R.F.) × max. distance
= (1/ 80000) × 12 km
= (1/ 80000) × (12 × 1000 × 100)cm
= 15 cm
Take height of scale 5 mm to 10 mm for getting a look of scale
……ANSWER
Problem 3:
Construct a plain scale to show kilometers and hectometers when
25 mm is equal to 1 km and long enough to measure up to 6 km.
Find RF and show a distance of 3km and 4 hectometer on the scale.
Problem 4:
Construct a plain scale of R.F. = 1:50 to show meters and
decimeters and long enough up to 8 meter. Indicate 6.7 m
distance on scale
Problem 5:
Construct a plain scale with RF = 1/5 to show decimeters (dm) and
centimeters. The scale should be long enough to measure 1 m. Show the
length of 7.4 dm on it.
6. Construct a Diagonal scale of R.F= 1/500 to read meters and decimeters. It
should be able to read maximum up to 80 meters. Measure a distance of 47.8
meters.
8
7 0 70
Length of scale = (1/500) * (80*100 cm) = 16 cm
10 20
10
decimeter
Meter
40
47.8 meter
30 50 60
meter
1
3
5
10
2
4
6
7
9
1
2
5
7. Construct a Diagonal scale of R.F= 3/100 to read meters, decimeters and
cm. It should be able to read maximum up to 5 meters. Measure a distance of
3.57 meters.
Solution
3 meter 5 decimeter 7 cm
3.57 meter =
cm
Meter
dm

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Plain scale and Diagonal Scale Engineering Graphics

  • 2. Reduced scale: Dimensions of large objects must be reduced to draw on standard size drawing sheet. Example: Map Of any country
  • 3.
  • 4. Enlarged scale: Similarly in case of tiny small objects dimensions must be increased to draw on drawing sheet. Example: Drawing of wrist watch parts.
  • 5. Plain scale A plain scale consists of a line divided into suitable number of equal units. The first unit is subdivided into smaller parts. The plain scales give only two dimensions, such as a unit and it's subunit or it's fraction.
  • 6. LENGTH OF SCALE = (R.F. ) × (MAX. LENGTH TO BE MEASURED.)
  • 7. PROBLEM NO.1 Draw a scale 1 cm = 1 meter to read meters and decimeters, to measure maximum distance of 6 m. Show on it a distance of 4 m and 6 dm.
  • 9.  R.F.= 1cm/ 1meter = 1/100 We know that, 1 meter = 10 decimeter = 100 cm  Length of scale = (R.F.) X max. distance = 1/100 X 600 cm = 6 cms
  • 10. ……ANSWER Take height of scale 5 mm to 10 mm for getting a look of scale
  • 11. PROBLEM NO.2 In a map a 36 km distance is shown by a line 45 cms long. Calculate the R.F. and Construct a plain scale to read kilometers and hectometers, for measuring maximum 12 km distance. Show a distance of 8.3 km on it.
  • 12. CONSTRUCTION:- Calculate R.F. R.F.= 45 cm/ 36 km = 45 cm/ (36 × 1000 × 100)cm = 1/ 80,000
  • 13. Length of scale = (R.F.) × max. distance = (1/ 80000) × 12 km = (1/ 80000) × (12 × 1000 × 100)cm = 15 cm
  • 14. Take height of scale 5 mm to 10 mm for getting a look of scale ……ANSWER
  • 15. Problem 3: Construct a plain scale to show kilometers and hectometers when 25 mm is equal to 1 km and long enough to measure up to 6 km. Find RF and show a distance of 3km and 4 hectometer on the scale.
  • 16.
  • 17.
  • 18. Problem 4: Construct a plain scale of R.F. = 1:50 to show meters and decimeters and long enough up to 8 meter. Indicate 6.7 m distance on scale
  • 19.
  • 20.
  • 21. Problem 5: Construct a plain scale with RF = 1/5 to show decimeters (dm) and centimeters. The scale should be long enough to measure 1 m. Show the length of 7.4 dm on it.
  • 22.
  • 23.
  • 24. 6. Construct a Diagonal scale of R.F= 1/500 to read meters and decimeters. It should be able to read maximum up to 80 meters. Measure a distance of 47.8 meters. 8 7 0 70 Length of scale = (1/500) * (80*100 cm) = 16 cm 10 20 10 decimeter Meter 40 47.8 meter 30 50 60 meter 1 3 5 10 2 4 6 7 9 1 2 5
  • 25. 7. Construct a Diagonal scale of R.F= 3/100 to read meters, decimeters and cm. It should be able to read maximum up to 5 meters. Measure a distance of 3.57 meters. Solution
  • 26. 3 meter 5 decimeter 7 cm 3.57 meter = cm Meter dm