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Holt McDougal Geometry
Angles of Elevation and Depression
Angles of Elevation
and Depression
Holt Geometry
Warm Up
Lesson Presentation
Lesson Quiz
Holt McDougal Geometry
Holt McDougal Geometry
Angles of Elevation and Depression
Warm Up
1. Identify the pairs of alternate
interior angles.
2. Use your calculator to find tan 30° to the
nearest hundredth.
3. Solve . Round to the nearest
hundredth.
2 and 7; 3 and 6
0.58
1816.36
Holt McDougal Geometry
Angles of Elevation and Depression
Solve problems involving angles of
elevation and angles of depression.
Objective
Holt McDougal Geometry
Angles of Elevation and Depression
angle of elevation
angle of depression
Vocabulary
Holt McDougal Geometry
Angles of Elevation and Depression
An angle of elevation is the angle formed by a
horizontal line and a line of sight to a point above
the line. In the diagram, 1 is the angle of elevation
from the tower T to the plane P.
An angle of depression is the angle formed by a
horizontal line and a line of sight to a point below
the line. 2 is the angle of depression from the
plane to the tower.
Holt McDougal Geometry
Angles of Elevation and Depression
Since horizontal lines are parallel, 1  2 by the
Alternate Interior Angles Theorem. Therefore the
angle of elevation from one point is congruent
to the angle of depression from the other point.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 1A: Classifying Angles of Elevation and
Depression
Classify each angle as an
angle of elevation or an
angle of depression.
1
1 is formed by a horizontal line and a line of
sight to a point below the line. It is an angle of
depression.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 1B: Classifying Angles of Elevation and
Depression
Classify each angle as an
angle of elevation or an
angle of depression.
4
4 is formed by a horizontal line and a line of sight
to a point above the line. It is an angle of elevation.
Holt McDougal Geometry
Angles of Elevation and Depression
Check It Out! Example 1
Use the diagram above to
classify each angle as an angle
of elevation or angle of
depression.
1a. 5
1b. 6
6 is formed by a horizontal line and a line of sight
to a point above the line. It is an angle of elevation.
5 is formed by a horizontal line and a line of
sight to a point below the line. It is an angle of
depression.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 2: Finding Distance by Using Angle of
Elevation
The Seattle Space Needle casts a 67-
meter shadow. If the angle of
elevation from the tip of the shadow
to the top of the Space Needle is
70º, how tall is the Space Needle?
Round to the nearest meter.
Draw a sketch to represent the
given information. Let A
represent the tip of the shadow,
and let B represent the top of
the Space Needle. Let y be the
height of the Space Needle.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 2 Continued
You are given the side adjacent to
A, and y is the side opposite A.
So write a tangent ratio.
y = 67 tan 70° Multiply both sides by 67.
y  184 m Simplify the expression.
Holt McDougal Geometry
Angles of Elevation and Depression
Check It Out! Example 2
What if…? Suppose the plane is at an altitude of
3500 ft and the angle of elevation from the airport to
the plane is 29°. What is the horizontal distance
between the plane and the airport? Round to the
nearest foot.
3500 ft
29°
You are given the side opposite
A, and x is the side adjacent to
A. So write a tangent ratio.
Multiply both sides by x and
divide by tan 29°.
x  6314 ft Simplify the expression.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 3: Finding Distance by Using Angle of
Depression
An ice climber stands at the edge of a
crevasse that is 115 ft wide. The angle of
depression from the edge where she stands to
the bottom of the opposite side is 52º. How
deep is the crevasse at this point? Round to
the nearest foot.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 3 Continued
Draw a sketch to represent
the given information. Let C
represent the ice climber and
let B represent the bottom of
the opposite side of the
crevasse. Let y be the depth
of the crevasse.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 3 Continued
By the Alternate Interior Angles Theorem, mB = 52°.
Write a tangent ratio.
y = 115 tan 52° Multiply both sides by 115.
y  147 ft Simplify the expression.
Holt McDougal Geometry
Angles of Elevation and Depression
Check It Out! Example 3
What if…? Suppose the ranger sees another fire
and the angle of depression to the fire is 3°. What
is the horizontal distance to this fire? Round to the
nearest foot.
By the Alternate Interior Angles Theorem, mF = 3°.
Write a tangent ratio.
Multiply both sides by x and
divide by tan 3°.
x  1717 ft Simplify the expression.
3°
Holt McDougal Geometry
Angles of Elevation and Depression
Example 4: Shipping Application
An observer in a lighthouse is 69 ft above the
water. He sights two boats in the water directly
in front of him. The angle of depression to the
nearest boat is 48º. The angle of depression to
the other boat is 22º. What is the distance
between the two boats? Round to the nearest
foot.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 4 Application
Step 1 Draw a sketch.
Let L represent the
observer in the
lighthouse and let A
and B represent the
two boats. Let x be the
distance between the
two boats.
Holt McDougal Geometry
Angles of Elevation and Depression
Example 4 Continued
Step 2 Find y.
By the Alternate Interior Angles Theorem,
mCAL = 58°.
.
In ∆ALC,
So
Holt McDougal Geometry
Angles of Elevation and Depression
Step 3 Find z.
By the Alternate Interior Angles Theorem,
mCBL = 22°.
Example 4 Continued
In ∆BLC,
So
Holt McDougal Geometry
Angles of Elevation and Depression
Step 4 Find x.
So the two boats are about 109 ft apart.
Example 4 Continued
x = z – y
x  170.8 – 62.1  109 ft
Holt McDougal Geometry
Angles of Elevation and Depression
Check It Out! Example 4
A pilot flying at an altitude of 12,000 ft sights
two airports directly in front of him. The angle
of depression to one airport is 78°, and the
angle of depression to the second airport is
19°. What is the distance between the two
airports? Round to the nearest foot.
Holt McDougal Geometry
Angles of Elevation and Depression
Step 1 Draw a sketch. Let
P represent the pilot and
let A and B represent the
two airports. Let x be the
distance between the two
airports.
Check It Out! Example 4 Continued
78°
19°
78° 19°
12,000 ft
Holt McDougal Geometry
Angles of Elevation and Depression
Step 2 Find y.
By the Alternate Interior Angles Theorem,
mCAP = 78°.
Check It Out! Example 4 Continued
In ∆APC,
So
Holt McDougal Geometry
Angles of Elevation and Depression
Step 3 Find z.
By the Alternate Interior Angles Theorem,
mCBP = 19°.
Check It Out! Example 4 Continued
In ∆BPC,
So
Holt McDougal Geometry
Angles of Elevation and Depression
Step 4 Find x.
So the two airports are about 32,300 ft apart.
Check It Out! Example 4 Continued
x = z – y
x  34,851 – 2551  32,300 ft
Holt McDougal Geometry
Angles of Elevation and Depression
Lesson Quiz: Part I
Classify each angle as an angle of elevation
or angle of depression.
1. 6
2. 9
angle of depression
angle of elevation
Holt McDougal Geometry
Angles of Elevation and Depression
Lesson Quiz: Part II
3. A plane is flying at an altitude of 14,500 ft.
The angle of depression from the plane to a
control tower is 15°. What is the horizontal
distance from the plane to the tower? Round to
the nearest foot.
4. A woman is standing 12 ft from a sculpture.
The angle of elevation from her eye to the top
of the sculpture is 30°, and the angle of
depression to its base is 22°. How tall is the
sculpture to the nearest foot?
54,115 ft
12 ft

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Holt Geometry Angles of Elevation and Depression

  • 1. Holt McDougal Geometry Angles of Elevation and Depression Angles of Elevation and Depression Holt Geometry Warm Up Lesson Presentation Lesson Quiz Holt McDougal Geometry
  • 2. Holt McDougal Geometry Angles of Elevation and Depression Warm Up 1. Identify the pairs of alternate interior angles. 2. Use your calculator to find tan 30° to the nearest hundredth. 3. Solve . Round to the nearest hundredth. 2 and 7; 3 and 6 0.58 1816.36
  • 3. Holt McDougal Geometry Angles of Elevation and Depression Solve problems involving angles of elevation and angles of depression. Objective
  • 4. Holt McDougal Geometry Angles of Elevation and Depression angle of elevation angle of depression Vocabulary
  • 5. Holt McDougal Geometry Angles of Elevation and Depression An angle of elevation is the angle formed by a horizontal line and a line of sight to a point above the line. In the diagram, 1 is the angle of elevation from the tower T to the plane P. An angle of depression is the angle formed by a horizontal line and a line of sight to a point below the line. 2 is the angle of depression from the plane to the tower.
  • 6. Holt McDougal Geometry Angles of Elevation and Depression Since horizontal lines are parallel, 1  2 by the Alternate Interior Angles Theorem. Therefore the angle of elevation from one point is congruent to the angle of depression from the other point.
  • 7. Holt McDougal Geometry Angles of Elevation and Depression Example 1A: Classifying Angles of Elevation and Depression Classify each angle as an angle of elevation or an angle of depression. 1 1 is formed by a horizontal line and a line of sight to a point below the line. It is an angle of depression.
  • 8. Holt McDougal Geometry Angles of Elevation and Depression Example 1B: Classifying Angles of Elevation and Depression Classify each angle as an angle of elevation or an angle of depression. 4 4 is formed by a horizontal line and a line of sight to a point above the line. It is an angle of elevation.
  • 9. Holt McDougal Geometry Angles of Elevation and Depression Check It Out! Example 1 Use the diagram above to classify each angle as an angle of elevation or angle of depression. 1a. 5 1b. 6 6 is formed by a horizontal line and a line of sight to a point above the line. It is an angle of elevation. 5 is formed by a horizontal line and a line of sight to a point below the line. It is an angle of depression.
  • 10. Holt McDougal Geometry Angles of Elevation and Depression Example 2: Finding Distance by Using Angle of Elevation The Seattle Space Needle casts a 67- meter shadow. If the angle of elevation from the tip of the shadow to the top of the Space Needle is 70º, how tall is the Space Needle? Round to the nearest meter. Draw a sketch to represent the given information. Let A represent the tip of the shadow, and let B represent the top of the Space Needle. Let y be the height of the Space Needle.
  • 11. Holt McDougal Geometry Angles of Elevation and Depression Example 2 Continued You are given the side adjacent to A, and y is the side opposite A. So write a tangent ratio. y = 67 tan 70° Multiply both sides by 67. y  184 m Simplify the expression.
  • 12. Holt McDougal Geometry Angles of Elevation and Depression Check It Out! Example 2 What if…? Suppose the plane is at an altitude of 3500 ft and the angle of elevation from the airport to the plane is 29°. What is the horizontal distance between the plane and the airport? Round to the nearest foot. 3500 ft 29° You are given the side opposite A, and x is the side adjacent to A. So write a tangent ratio. Multiply both sides by x and divide by tan 29°. x  6314 ft Simplify the expression.
  • 13. Holt McDougal Geometry Angles of Elevation and Depression Example 3: Finding Distance by Using Angle of Depression An ice climber stands at the edge of a crevasse that is 115 ft wide. The angle of depression from the edge where she stands to the bottom of the opposite side is 52º. How deep is the crevasse at this point? Round to the nearest foot.
  • 14. Holt McDougal Geometry Angles of Elevation and Depression Example 3 Continued Draw a sketch to represent the given information. Let C represent the ice climber and let B represent the bottom of the opposite side of the crevasse. Let y be the depth of the crevasse.
  • 15. Holt McDougal Geometry Angles of Elevation and Depression Example 3 Continued By the Alternate Interior Angles Theorem, mB = 52°. Write a tangent ratio. y = 115 tan 52° Multiply both sides by 115. y  147 ft Simplify the expression.
  • 16. Holt McDougal Geometry Angles of Elevation and Depression Check It Out! Example 3 What if…? Suppose the ranger sees another fire and the angle of depression to the fire is 3°. What is the horizontal distance to this fire? Round to the nearest foot. By the Alternate Interior Angles Theorem, mF = 3°. Write a tangent ratio. Multiply both sides by x and divide by tan 3°. x  1717 ft Simplify the expression. 3°
  • 17. Holt McDougal Geometry Angles of Elevation and Depression Example 4: Shipping Application An observer in a lighthouse is 69 ft above the water. He sights two boats in the water directly in front of him. The angle of depression to the nearest boat is 48º. The angle of depression to the other boat is 22º. What is the distance between the two boats? Round to the nearest foot.
  • 18. Holt McDougal Geometry Angles of Elevation and Depression Example 4 Application Step 1 Draw a sketch. Let L represent the observer in the lighthouse and let A and B represent the two boats. Let x be the distance between the two boats.
  • 19. Holt McDougal Geometry Angles of Elevation and Depression Example 4 Continued Step 2 Find y. By the Alternate Interior Angles Theorem, mCAL = 58°. . In ∆ALC, So
  • 20. Holt McDougal Geometry Angles of Elevation and Depression Step 3 Find z. By the Alternate Interior Angles Theorem, mCBL = 22°. Example 4 Continued In ∆BLC, So
  • 21. Holt McDougal Geometry Angles of Elevation and Depression Step 4 Find x. So the two boats are about 109 ft apart. Example 4 Continued x = z – y x  170.8 – 62.1  109 ft
  • 22. Holt McDougal Geometry Angles of Elevation and Depression Check It Out! Example 4 A pilot flying at an altitude of 12,000 ft sights two airports directly in front of him. The angle of depression to one airport is 78°, and the angle of depression to the second airport is 19°. What is the distance between the two airports? Round to the nearest foot.
  • 23. Holt McDougal Geometry Angles of Elevation and Depression Step 1 Draw a sketch. Let P represent the pilot and let A and B represent the two airports. Let x be the distance between the two airports. Check It Out! Example 4 Continued 78° 19° 78° 19° 12,000 ft
  • 24. Holt McDougal Geometry Angles of Elevation and Depression Step 2 Find y. By the Alternate Interior Angles Theorem, mCAP = 78°. Check It Out! Example 4 Continued In ∆APC, So
  • 25. Holt McDougal Geometry Angles of Elevation and Depression Step 3 Find z. By the Alternate Interior Angles Theorem, mCBP = 19°. Check It Out! Example 4 Continued In ∆BPC, So
  • 26. Holt McDougal Geometry Angles of Elevation and Depression Step 4 Find x. So the two airports are about 32,300 ft apart. Check It Out! Example 4 Continued x = z – y x  34,851 – 2551  32,300 ft
  • 27. Holt McDougal Geometry Angles of Elevation and Depression Lesson Quiz: Part I Classify each angle as an angle of elevation or angle of depression. 1. 6 2. 9 angle of depression angle of elevation
  • 28. Holt McDougal Geometry Angles of Elevation and Depression Lesson Quiz: Part II 3. A plane is flying at an altitude of 14,500 ft. The angle of depression from the plane to a control tower is 15°. What is the horizontal distance from the plane to the tower? Round to the nearest foot. 4. A woman is standing 12 ft from a sculpture. The angle of elevation from her eye to the top of the sculpture is 30°, and the angle of depression to its base is 22°. How tall is the sculpture to the nearest foot? 54,115 ft 12 ft