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We will talk about
static and dynamic
performance.
We will answer questions such as:
How fast?
How high?
How far?
How long can an aircraft fly?
Coverage Airplane Performance
Static Performance
(zero acceleration)
Dynamic Performance
(finite acceleration)
Thrust Required
Thrust Available
Maximum
Velocity
Power Required
Power Available
Maximum Velocity
Rate of Climb
Takeoff
Landing
Equations of Motions
V-n Diagram
Turning Flight
Range and Endurance
Time to Climb
Maximum Altitude
Gliding Flight
Service Ceiling
Absolute Ceiling
Drag Polar
A Prerequisite
Performance analysis hinges
on knowledge of the airplane
drag polar.
What is a drag polar?
It is a term coined by Eiffel.
The same monsieur of Eiffel tower fame.
The same guy who designed Quiapo bridge
(a.k.a. Quezon bridge)
It is a graph or an equation that accounts for all types of drag
in an airplane and how it relates to lift.
Quezon bridge: FEATI’s vantage point
Gustav’s Tower
What types of drag are included then? Let’s
enumerate.
Bullets would come in handy for
this sort of job.
What are the different types of drag?
▪ Skin friction drag
▪ Pressure drag
▪ Profile drag
▪ Interference drag
▪ Parasite drag
▪ Induced drag
▪ Zero-lift drag
▪ Drag due to lift
▪ Wave drag
Drag Types
Skin-friction drag. Drag due to frictional shear
stress integrated over the surface.
Pressure drag due to flow separation (form drag):
The drag due to the pressure imbalance in the
drag direction caused by separated flow.
Drag Types
Profile drag. The sum of skin friction drag and
form drag. (The term profile drag is usually used
in conjunction with two-dimensional airfoils; it is
sometimes called section drag.)
Drag Types
Interference drag. An additional pressure drag
caused by the mutual interaction of the flow
fields around each component of the airplane.
The total drag of the combined body is usually
greater than that of the sum of its individual
parts; the difference is the interference drag.
Drag Types
Parasite drag. The term used for the profile drag
for a complete airplane. It is that portion of the
total drag associated with skin friction and
pressure drag due to flow separation, integrated
over the complete airplane surface. It includes
interference drag.
Drag Types
Induced drag. A pressure drag due to the
pressure imbalance in the drag direction
caused by the induced flow (downwash)
associated with the vortices created at the tips
of finite wings.
Drag Types
Zero-lift drag. (Usually used in conjunction
with a complete airplane configuration.) The
parasite drag that exists when the airplane is
at its zero-lift angle of attack, that is, when the
lift of the airplane is zero.
Drag Types
Drag due to lift. (Usually used in conjunction with a
complete airplane.) That portion of the total airplane
drag measured above the zero-lift drag. It consists of
the change in parasite drag when the airplane is at an
angle of attack different from the zero-lift angle, plus
the induced drag from the wings and other lifting
components of the airplane.
Drag Types
Wave drag. The pressure drag associated with
transonic and supersonic flow (or shock waves,
hence the name). It can be expressed as the
sum the zero-lift wave drag and wave drag
due to lift.
Drag Types
Total Drag
Skin Friction Drag Pressure Drag
Induced Drag Wave Drag
Note : Profile Drag = Skin Friction Drag + Form Drag
Total Drag
Form Drag (Drag due to flow separation)
drag
induced
drag
profile
drag
total +
=
Drag Polar
eAR
π
C
C
C L
d
D
2
+
=
eAR
C
C
C L
D
D

2
0
, +
=
A wing or airfoil have its own drag polar
An airplane have its own drag polar
profile drag
zero-lift drag
Drag Polar
eAR
C
C
C L
e
D
D

2
, +
=
parasite drag coefficient
-profile drag of wing
-friction and pressure drag of:
tail surfaces
fuselage
engine nacelles
landing gear
other components exposed to the flow
-a function of angle of attack
lift span
efficiency factor
induced drag coefficient
Drag Polar
2
0
,
, L
D
e
D rC
C
C +
=
2
0
, )
1
( L
D
D C
eAR
r
C
C

+
+
=
eAR
π
C
C
C L
e
D
D
2
, +
=
eAR
π
C
C
C L
D
D
2
0
, +
=
Drag polar of a complete airplane
i
D
D
L
D
D C
C
eAR
C
C
C ,
0
,
2
0
, +
=
+
=

induced drag
coefficient
parasite drag
coefficient at
zero lift
Oswald’s
efficiency
factor
Drag polar of a complete airplane
eAR
C
C
C L
D
D

2
0
, +
=
Drag Polar
Drag Polar
Lockheed C-141A
Drag Polar
eAR
π
C
C
C
C drag
L
L
D
D
2
min
,
)
( min
−
+
=
Why is it called drag polar?
Equations of Motion
Equations of Motion
For level, unaccelerated flight,
If thrust line is aligned with flight path,
Equations of Motion
If thrust line is
aligned with flight
path,
Level, unaccelerated flight
Equations of Motion
Thrust Required
Thrust required for steady level flight at
given speed.
D
TR =
NOTE:
Thrust Required is a
function of velocity.
It has two
components.
It has a minimum.
Thrust Required for Level, Unaccelerated Flight
at a given velocity
Thrust Required for Level, Unaccelerated Flight
D
TR =
)
(
2
1
)
(
2
1
2
1
2
2
2
2
eAR
C
C
S
V
C
C
S
V
SC
V
D
T L
D
D
D
D
R o
i
o



 +
=
+
=
=
= 





)
)
2
/
1
(
(
2
1
2
2
2
eAR
S
V
L
C
S
V
T o
D
R











+
= 



)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R






 +
=
)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R






 +
=
zero-lift
thrust required
lift-induced
thrust required
Thrust Required for Level, Unaccelerated Flight
Applying a first and a second derivative test to this function
will confirm the existence of a minimum. This minimum will
exist at velocity,
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


)
(
)
1
)(
2
1
(
2
1
2
2
2




 =
+
= V
f
eAR
S
V
W
C
S
V
T o
D
R



Thrust Required for Level, Unaccelerated Flight
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


Thrust Required for Level, Unaccelerated Flight
Thrust Required: Alternative Approach
D
TR =
L
D
R
C
C
W
T
W
L
=
=
Since
D
L
R
C
C
W
T
/
=
Since we have already established the existence of a minimum
thrust required, this equation implies the existence of a
maximum lift-to-drag ratio.
Thrust Required: Alternative Approach
Indeed there is a
maximum L/D ratio
exhibited by every
aircraft.
You will see how this
ratio is an indicator of
performance
(aerodynamic efficiency)
of an aircraft.
Thrust Required: Alternative Approach
D
L
W
C
C
W
T
D
L
R
/
/
=
=
Different
points on TR
curve
correspond to
different
angles of
attack.








+
=
=
=
=
=





eAR
C
C
S
q
SC
q
D
SC
q
SC
V
W
L
L
D
D
L
L


2
0
,
2
2
1
At a:
Large q∞
Small CL and a
D large
At b:
Small q∞
Large CL (or CL
2) and a to support W
D large
Thrust Required: Alternative Approach
Thrust Required Computation
TR is thrust required
to fly at a given
velocity in level,
unaccelerated flight
1. Select a flight speed,V∞ and calculate CL.
S
V
W
CL
2
2
1


=

eAR
C
C
C L
D
D

2
0
, +
=
2. Calculate CD.
3. Calculate CL/CD and calculateTR.






=
D
L
R
C
C
W
T
CP-1: A light, single-engine, propeller-driven, private airplane,
approximately modelled after the Cessna Skylane, having the following
characteristics:
Wingspan = 35.8 ft
Wing area = 174 ft2
Normal gross weight = 2950 lb
Fuel capacity: 65 gal of aviation gasoline
Power plant: one-piston engine, 230 hp (SL)
Specific fuel consumption= 0.45 lb/(hp)(h)
Parasite drag coefficient CD,o = 0.025
Oswald efficiency factor, e = 0.8
Propeller efficiency = 0.8
Example
Example
Cessna Skylane
Example
357
.
0
)
174
(
)
200
)(
002377
.
0
(
2
1
2950
2
1 2
2
=
=
=

 S
V
W
CL

AtV=200 ft/s = 136.4 mi/h
37
.
7
174
)
8
.
35
( 2
2
=
=
=
S
b
AR
0319
.
0
)
37
.
7
)(
8
.
0
(
)
357
.
0
(
025
.
0
2
2
0
, =
+
=
+
=

eAR
C
C
C L
D
D
lb
263
2
.
11
2950
/
=
=
=
D
L
W
TR
2
.
11
0319
.
0
357
.
0
=
=
=
D
L
C
C
D
L
1
2
3
Example
At other velocities…
1 2 3
CJ-1: A jet-powered executive aircraft, approximately modelled after
the Cessna Citation 3, having the following characteristics:
Wingspan = 53.3 ft
Wing area = 318 ft2
Normal gross weight = 19,815 lb
Fuel capacity: 1119 gal of kerosene
Power plant: two turbofan engines of 3650-lb thrust each at sea level
Specific fuel consumption = 0.6 lb of fuel/(lb thrust)(h)
Parasite drag coefficient CD,o = 0.02
Oswald efficiency factor e = 0.81
Example
Example
Cessna Citation III
Example
210
.
0
)
318
(
)
500
)(
002377
.
0
(
2
1
19815
2
1 2
2
=
=
=

 S
V
W
CL

AtV=500 ft/s = 341 mi/h
93
.
8
318
)
3
.
53
( 2
2
=
=
=
S
b
AR
022
.
0
)
93
.
8
)(
81
.
0
(
)
21
.
0
(
02
.
0
2
2
0
, =
+
=
+
=

eAR
C
C
C L
D
D
lb
2075
55
.
9
19815
/
=
=
=
D
L
W
TR
55
.
9
022
.
0
21
.
0
=
=
=
D
L
C
C
D
L
1
2
3
Example
At other velocities…
1 2 3
How do we compute for (L/D)max?
At TRmin we found (by differentiating TR with
respect to V and equating to zero),
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


i
D
L
D C
eAR
C
C ,
2
0
, =
=

From this formula for V at TRmin, the following
relationship (which has already been revealed in
the graph) can be derived:
0
,
0
,
0
, 4
/
2
/
/ D
D
D
D
L C
eAR
C
eAR
C
C
C 
 =
=
Thus,
and this is a maximum
because an (L/D)max is simultaneous with a TRmin.
i
D
L
D C
eAR
C
C ,
2
0
, =
=

How do we compute for (L/D)max?
0
,
max
4
/ D
D
L C
eAR
C
C 
=






At TRmin
Thus,
How do we compute for TRmin?
You can substitute
Or you can substitute
0
,
max 4
/
)
/
( D
D
L C
eAR
C
C 
=
)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R






 +
=






=
D
L
R
C
C
W
T
to to
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


Effects of compressibility onTR
Effects of altitude onTR
)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R


 +
=
Note that the minimum thrust required is independent of altitude.
2
/
1
1
2
min
,








=
S
W
eAR
C
V
o
R
D
Lower
T


2
/
1
1
2
min
,








=
S
W
eAR
C
V
o
R
D
Higher
T


max
min
,






=
D
L
R
C
C
W
T
Propeller-Piston Engine
Jet Engine
Thrust Available
Maximum Velocity: Graphical
The intersection of the
TA and TR curve gives
Vmax at a certain
altitude.
Example
Calculate the maximum velocity for the sample jet plane.
Vmax = 975 ft/s
= 665 mi/h
Intersection of TR
curve and maximum
TA defines maximum
flight speed of airplane.
Example
Some remarks. Computation of TR
curve assumed constant CD,o
At this speed, drag
divergence effects are
significant, and adds to
the CD,o
Maximum Velocity: Analytical








+
=
=
= 

eAR
C
C
S
q
SC
q
T
D L
D
D

2
0
,
S
q
W
CL

=
eAR
S
q
W
SC
q
eAR
S
q
W
C
S
q
T D
D

 


 +
=








+
=
2
0
,
2
2
2
0
,
0
2
0
,
2
=
+
− 

eAR
S
W
T
q
SC
q D

Steady, level flight:T = D
Steady, level flight: L =W
Substitute into
drag equation
Turn this equation into a
quadratic
equation (by multiplying by q∞)
and rearranging.
Maximum Velocity: Analytical
2
1
0
,
0
,
2
max
max
max
4














−












+












=
 D
D
A
A
C
eAR
C
W
T
S
W
S
W
W
T
V


Solving the quadratic equation and setting thrust, T, to
maximum available thrust, TA,max results in,
Maximum Velocity: Design Considerations
2
1
0
,
0
,
2
max
max
max
4














−












+












=
 D
D
A
A
C
eAR
C
W
T
S
W
S
W
W
T
V


• TA,max does not appear alone, but only in ratio: (TA/W)max
• S does not appear alone, but only in ratio: (W/S)
• Vmax does not depend on thrust alone or weight alone, but rather on
ratios
• (TA/W)max: maximum thrust-to-weight ratio
• W/S: wing loading
Maximum Velocity: Design Considerations
• Vmax also depends on density (altitude), CD,0, eAR
• Increase Vmax by
• Increase maximum thrust-to-weight ratio, (TA/W)max
• Increasing wing loading, (W/S)
• Decreasing zero-lift drag coefficient, CD,0
2
1
0
,
0
,
2
max
max
max
4














−












+












=
 D
D
A
A
C
eAR
C
W
T
S
W
S
W
W
T
V


Example
CalculateVmax for the CP-1.
2
lb/ft
95
.
16
174
2950
=
=
S
W
Wingspan = 35.8 ft
Wing area = 174 ft2
Normal gross weight = 2950 lb
Fuel capacity: 65 gal of aviation gasoline
Power plant: one-piston engine, 230 hp (SL)
Specific fuel consumption= 0.45 lb/(hp)(h)
Parasite drag coefficient CD,o = 0.025
Oswald efficiency factor, e = 0.8
Propeller efficiency = 0.8
3
-
2
0
,
10
x
4066
.
5
]
174
/
)
8
.
35
)[(
8
.
0
(
)
025
.
0
(
4
4
=
=

eAR
CD
3
5
0
,
slug/ft
10
x
9425
.
5
)
025
.
0
(
002377
.
0
−

=
=
D
C

2
1
0
,
0
,
2
max
max
max
4














−












+












=
 D
D
A
A
C
eAR
C
W
T
S
W
S
W
W
T
V


Example
CalculateVmax for the CP-1.
lb)/s
(ft
10
x
012
.
1
)
550
)(
230
(
8
.
0 5

=
=
=
=
 P
P
V
T A
A 
( )
max
max
V
P
TA

=
For maxTA and PA,V∞ =Vmax
max
max
max
305
.
34
1
V
V
W
P
W
TA
=
=





 
?
max
=






W
TA
2
1
0
,
0
,
2
max
max
max
4














−












+












=
 D
D
A
A
C
eAR
C
W
T
S
W
S
W
W
T
V


Example
CalculateVmax for the CP-1.
2
/
1
3
2
max
max
max
max
max 10
x
4066
.
5
305
.
34
305
.
34
97
.
558








−








+








= −
V
V
V
Solve this by trial and error.
Jets Engines are usually rated inThrust
Thrust is a Force with units (N = kg m/s2)
For example, the PW4000-112 is rated at 98,000 lb of thrust
Piston-Driven Engines are usually rated in terms of Power
Power is a precise term and can be expressed as:
Energy /Time with units (kg m2/s2) / s = kg m2/s3 = Watts
Note that Energy is expressed in Joules = kg m2/s2
Force *Velocity with units (kg m/s2) * (m/s) = kg m2/s3 =Watts
Usually rated in terms of horsepower (1 hp = 550 ft lb/s = 746W)
Why is there a need for a new parameter?
PR vs. V∞ curve qualitatively
resembles TR vs. V∞ curve.
Power Required
PR = TRV∞
Power Required
NOTE:
Power Required is
a function of
velocity.
It has two
components.
It has a minimum.
Power Required
)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R






 +
=
)
1
)(
2
1
(
2
1 2
3
eAR
S
V
W
C
S
V
P o
D
R




 +
=
zero-lift power required lift-induced power required

= V
T
P R
R

V
zero-lift PR ~V3
lift-induced PR ~ 1/V
Power Required, Minimum
)
(
)
1
)(
2
1
(
2
1 2
3


 =
+
= V
f
eAR
S
V
W
C
S
V
P o
D
R



Get f’(V∞).
Equate to zero.
Solve forV∞ in f’(V∞)=0 to getVPR,min.
Substitute V∞ in f(V∞) to get PR,min.
The results are…
Power Required, Minimum
2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


The results are…
At PRmin ,
i
D
D C
C =
0
,
3
and
Power Required
2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


i
D
D C
C =
0
,
3
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


min
,
min
,
4
1
3
1
R
R T
P V
V 





=

 =
= V
C
C
W
V
T
P
D
L
R
R
Power Required: Alternative Approach
L
SC
V
W
L
2
2
1


=
= 
L
SC
W
V

 =

2
L
D
L
R
R
SC
W
C
C
W
V
T
P

 =
=

2
C
1
2
2
/
3
L
3
2
3
D
L
D
R
C
SC
C
W
P a

= x
C
1
2
max
D
2
3
L
3
min
,








=
 C
S
W
PR

2
3
2
3
L
D
R
SC
C
W
P

=

Power Required: Alternative Approach
Example

= V
T
P R
R
Calculate the power required curve for (a) the CP-1 at sea level and
(b) the CJ-1 at an altitude of 22,000 ft.
Example
Example

= V
T
P R
R
3
slug/ft
001184
.
0
=


At an altitude of 22,000 ft
Thrust required is re-computed using this density.
Example
How do we compute for (L3/2/D)max?
eAR
C
C
C L
D
D i

2
0
,
3 =
=
( ) 4
3
3
1
0
,
0
,
4
3
0
,
max
2
3
3
4
1
4
3








=
=








D
D
D
D
L
C
eAR
C
eAR
C
C
C 

eAR
C
C D
L 
0
,
3
=
i
D
D C
C =
0
,
3
How do we compute for (L3/2/D)max?
At PRmin
Thus,
4
3
3
1
0
,
max
2
3
3
4
1








=








D
D
L
C
eAR
C
C 
(L/D)max VS (L3/2/D)max
Locating (L/D)max in the PR curve
How do we compute for PR,min?
You can substitute
Or you can substitute
to to
2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


)
1
)(
2
1
(
2
1 2
3
eAR
S
V
W
C
S
V
P o
D
R




 +
=
4
3
3
1
0
,
max
2
3
3
4
1








=








D
D
L
C
eAR
C
C 
C
1
2
D
2
3
L
3








=
 C
S
ρ
W
PR
Effects of altitude on PR
2
1
0
0
,
,
2
1
0
0








=








=




R
ALT
R
ALT
P
P
V
V
C
1
2
D
2
3
L
3








=
 C
S
W
PR

2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


Effects of altitude on PR
2
1
0
0
,
,
2
1
0
0








=








=




R
ALT
R
ALT
P
P
V
V
Effects of altitude on PR
2
1
0
0
,
,
2
1
0
0








=








=




R
ALT
R
ALT
P
P
V
V
SUMMARY
thrust required
power required
)
1
)(
2
1
(
2
1 2
3
eAR
S
V
W
C
S
V
P o
D
R




 +
=
C
1
2
D
2
3
L
3








=
 C
S
W
PR

)
1
)(
2
1
(
2
1
2
2
2
eAR
S
V
W
C
S
V
T o
D
R






 +
=
D
L
R
C
C
W
T
/
=
SUMMARY
At minimum thrust required At minimum power required
i
D
D C
C ,
0
, =
0
,
max
4
/ D
D
L C
eAR
C
C 
=






i
D
D C
C =
0
,
3
2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


( ) 4
3
3
1
0
,
0
,
4
3
0
,
max
2
3
3
4
1
4
3








=
=








D
D
D
D
L
C
eAR
C
eAR
C
C
C 

Power Available
Power Available
Power Available VS Thrust Available
Maximum Velocity: Graphical
Maximum Velocity: Graphical
Effects of Altitude on Maximum Velocity
Effects of Altitude on Maximum Velocity
Minimum Velocity
Sometimes
minimum or
stall velocity
is dictated by
powerplant
considerations.
It is true,
Chuck Norris’
legendary
kick can also
cause a stall,
but…
Rate of Climb


cos
sin
W
L
W
D
T
=
+
=
Rate of Climb

sin


 +
= WV
DV
TV

sin
W
D
T +
=

sin
/ 
=V
C
R

sin



=
−
V
W
DV
TV
W
DV
TV
C
R 
 −
=
/
Rate of Climb
W
DV
TV
C
R 
 −
=
/
Power Available ~ Power Required
(for small Ѳ)

sin
W
D
T +
=

 −
= DV
TV
power
excess
W
C
R
power
excess
/ =
Rate of Climb
W
C
R
power
excess
maximum
)
/
( max =
Rate of Climb VS Altitude
Example
Calculate the rate of climb vs velocity at sea level for (a) the CP-1
and (b) the CJ-1.
ft/min
1398
ft/s
3
.
23
2950
32600
-
10120
2950
P
P
power
excess
)
/
( R
A
=
=
=
−
=
=
W
C
R
AtV = 150 ft/s PR = 32,600 ft-lb/s and PA = 10,120 ft-lb/s. Hence,
Example max
Example
ft/min
7914
ft/s
132
19815
1884
-
6636
550
19815
P
P
power
excess
)
/
( R
A
=
=
=
−
=
=
W
C
R
AtV = 500 ft/s PR = 1884 hp and PA = 6636 hp. Hence,
Example
max
R/Cmax: Analytical
( ) ( )2
max
2
max /
/
3
1
1
W
T
D
L
Z +
+
=
( ) ( )
( ) ( ) 





−
−














=
 Z
D
L
W
T
Z
W
T
C
Z
S
W
C
R
D
2
max
2
max
2
/
3
max
2
/
1
0
,
max
/
/
2
3
6
1
3
/
/

( )
( ) 2
/
3
max
0
,
max
max
/
1
/
8776
.
0
/
D
L
C
S
W
W
P
C
R
D

−






=


For a piston-propeller aircraft:
For a jet aircraft:
Where:
Absolute Ceiling
0
/ =
C
R
Service Ceiling
min
/
100
)
/
( max ft
C
R =
Example
Calculate the absolute and service ceilings for (a) the CP-1 and (b) the CJ-
1.
W
C
R
power
excess
maximum
)
/
( max =
Example
Calculate the absolute and service ceilings for (a) the CP-1 and (b) the CJ-
1. (a) the CP-1 (b) the CJ-1
service ceilings = 25,000 ft
absolute ceilings = 27,000 ft
service ceilings = 48,000 ft
absolute ceilings = 49,000 ft
Time to Climb
dt
dh
C
R =
/
C
R
dh
dt
/
=

=
2
1
h
h
dt
t

=
2
1
/
h
h
C
R
dh
t
Time to Climb: Graphical

=
2
1
/
h
h
C
R
dh
t
Time to Climb
b
mx
y +
=
0
max
0
max,
0
)
/
(
)
/
(
H
C
R
C
R
H
H +
−
=
0
H
0
max,
)
/
( C
R

=
H
C
R
dh
t
0 max
)
/
(
)
(
)
/
(
)
/
( 0
0
0
max,
max H
H
H
C
R
C
R −
=
 −
=
H
H
H
dh
C
R
H
t
0 0
0
max,
0
)
/
(








−
=
H
H
H
C
R
H
t
0
0
0
max,
0
ln
)
/
(
Altitude,
H
Maximum Rate of Climb, (R/C)max
Gliding Flight
D
L
L
D
1
tan
cos
sin
=
=





cos
sin
0
W
L
W
D
T
=
=
=
Gliding Flight
D
L
1
tan =

D
L
1
tan 1
−
=

max
1
min
1
tan






= −
D
L

Gliding Flight
D
L
1
tan 1
−
=

D
L
h
h
R =
=

tan
max
max )
(
tan D
L
h
h
R =
=

How do we compute for (L/D)max?
At TRmin we found (by differentiating TR with
respect to V and equating to zero),
2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


i
D
L
D C
eAR
C
C ,
2
0
, =
=

From this formula for V at TRmin, the following
relationship (which has already been revealed in
the graph) can be derived:
0
,
0
,
0
, 4
/
2
/
/ D
D
D
D
L C
eAR
C
eAR
C
C
C 
 =
=
Thus,
and this is a maximum
because an (L/D)max is simultaneous with a TRmin.
Gliding Flight
To maximize range, glide at smallest  (at (L/D)max )
A modern sailplane may have a glide ratio as high as 60:1
So  = tan-1(1/60) ~ 1°

Example
Calculate the minimum glide angle and the maximum range measured
along the ground covered by the CP-1 and the CJ-1 in a power-off glide
that starts at an altitude of 10,000 ft.
10,000 ft
CP-1: A light, single-engine, propeller-driven, private airplane,
approximately modelled after the Cessna Skylane, having the following
characteristics:
Example
Aspect Ratio = 7.37
Parasite drag coefficient CD,o = 0.025
Oswald efficiency factor, e = 0.8
Example
Calculate the minimum glide angle and the maximum range measured
along the ground covered by the CP-1 in a power-off glide that starts at
an altitude of 10,000 ft.
( )

=
=
= −
2
.
4
61
.
13
1
1
tan
max
1
min
D
L

ft
136,000
)
61
.
13
(
10000
)
( max
max
=
=
=
D
L
h
R
10,000 ft
CJ-1: A jet-powered executive aircraft, approximately modelled after
the Cessna Citation 3, having the following characteristics:
Example
Aspect Ratio = 8.93
Parasite drag coefficient CD,o = 0.02
Oswald efficiency factor e = 0.81
( )
9
.
16
)
02
.
0
(
4
/
)
93
.
8
)(
81
.
0
(
4
/ 0
,
max
=
=
=

 D
C
eAR
D
L
Example
Calculate the minimum glide angle and the maximum range measured
along the ground covered by the CJ-1 in a power-off glide that starts at
an altitude of 10,000 ft.
( )

=
=
= −
39
.
3
9
.
16
1
1
tan
max
1
min
D
L

ft
169,000
)
9
.
136
(
10000
)
( max
max
=
=
=
D
L
h
R
10,000 ft
Example
For the CP-1, calculate the equilibrium glide velocities at altitudes of
10,000 ft and 2,000 ft, each corresponding to the minimum glide angle.
L
SC
V
W
L
2
2
1
cos 

=
= 

S
W
C
V
L

 =


cos
2
i
D
L
D C
eAR
C
C ,
2
0
, =
=

CL corresponding to
(L/D)max
At
(L/D)max
eAR
C
C D
L 
0
,
=
634
.
0
)
37
.
7
)(
8
.
0
(
)
025
.
0
(
=
=
L
L
C
C 
Example
For the CP-1, calculate the equilibrium glide velocities at altitudes of
10,000 ft and 2,000 ft, each corresponding to the minimum glide angle.
S
W
C
V
L

 =


cos
2
2
lb/ft
95
.
16
174
2950
=
=
S
W

= 2
.
4
min

)
634
.
0
(
0017556
.
0
)
95
.
16
)(
2
.
4
cos
2
( 
=

V
ft
10,000
h
at
ft/s
3
.
174 =
=

V
)
634
.
0
(
0022409
.
0
)
95
.
16
)(
2
.
4
cos
2
( 
=

V
ft
2,000
h
at
ft/s
3
.
154 =
=

V
f
W
W
W +
= 1
dt
dW
dt
dW f
=
Weight Equation
W –Weight of the airplane at any instant during flight.
W0 – Gross weight of the airplane, including everything: full fuel
load, payload, crew, structures, etc.
Wf – Weight of fuel: this is an instantaneous value, and it
changes as fuel is consumed during flight.
W1 –Weight of the airplane when the fuel tanks are empty.
f
W
W 
 =
( )( )
hour
BHP
fuel
of
lb
SFC =
SFC VS TSFC
( )( )
hour
thrust
of
lb
fuel
of
lb
TSFC =
P
dt
dW
P
W
c
f
f
−
=
−
=

T
dt
dW
T
W
c
f
f
t −
=
−
=

pr
t
V
c
c


=
Range: Piston-Propeller
( )( )

=
=
V
mile
(HP)
fuel
of
lb
hour
HP
fuel
of
lb
SFC
( )
( )
R
T
SFC)
(
V
HP
SFC
mile
fuel
of
lb



To cover longest distance use minimum pounds of fuel per mile.
To cover longest distance fly at minimum thrust required.
Range: Piston-Propeller
dt
V
ds
dt
ds
V 
 =

=
T
c
dW
dt
T
dt
dW
c
t
f
f
t −
=

−
=








−
= 
T
c
dW
V
ds
t
f
f
W
W 
 =








−
= 
T
c
dW
V
ds
t
W
W
T
c
dW
V
ds
t








−
= 
W
dW
D
L
c
V
W
L
D
c
dW
V
ds
t
t

 −
=








−
=
Range: Piston-Propeller
W
dW
D
L
c
V
ds
t

−
=

 
−
=
=
1
0
0
W
W t
R
W
dW
D
L
c
V
ds
R

 
−
=
=
1
0
0
W
W
t
R
W
dW
D
L
c
V
ds
R
Assumptions made: level,
unaccelerated flight with
constantTSFC and L/D.
1
0
ln
W
W
D
L
c
V
R
t

=
BREGUET RANGE
EQUATION
1
0
ln
W
W
D
L
c
R
pr

=
pr
t
V
c
c


=
Range: Piston-Propeller
1
0
ln
W
W
D
L
c
R
pr

=
To maximize range:
Fly at largest propeller efficiency
Lowest possible SFC
Highest ratio of W0 toW1 (fly with the largest fuel weight)
Fly at maximum L/D (minimumTR)
propulsion
aerodynamics
structures
and materials
Example
Estimate the maximum range for the CP-1.
Normal gross weight = 2950 lb
Fuel capacity: 65 gal of aviation gasoline
Specific fuel consumption= 0.45 lb/(hp)(h)
Parasite drag coefficient CD,o = 0.025
Oswald efficiency factor, e = 0.8
Propeller efficiency = 0.8
1
0
max
max ln
W
W
D
L
c
R
pr






=

Example
Estimate the maximum range for the CP-1.
( ) 61
.
13
4
/ 0
,
max =
= D
C
eAR
D
L 
1
-
7
ft
10
x
27
.
2
s
3600
h
1
lb/s
-
ft
550
hp
1
(hp)(h)
lb
45
.
0 −
=
=
c
lb
367
)
64
.
5
(
65 =
=
f
W
Since aviation gasoline weighs 5.64 lb/gal,
lb
2583
367
2950
1 =
−
=
W
mi
1207
ft
10
x
38
.
6
2583
2950
ln
)
62
.
13
(
10
x
27
.
2
8
.
0
ln 6
7
1
0
max
max =
=






=






= −
W
W
D
L
c
R
pr

Range: Jet Aircraft
( ) 

V
T
TSFC A
)
(
mile
fuel
of
lb
To cover longest distance use minimum pounds of fuel per mile.
To cover longest distance fly at maximum L1/2/D.
( )( ) ( )

=
=
V
miles
thrust
of
lb
fuel
of
lb
hour
thrust
of
lb
fuel
of
lb
TSFC
D
L
D
L
R
C
C
C
SC
W
S
V
T
2
1
1
2
2
1

=


 

Range: Jet Aircraft
 
−
=
1
0
W
W t W
dW
D
L
c
V
R
L
SC
W
V 
 = 
2
 
−
=
1
0
2
1
2
1
2
W
W t
D
L
W
dW
c
C
C
S
R

)
(
2
2 2
1
1
2
1
0
2
1
W
W
C
C
S
c
R
D
L
t
−
=


Assumptions made: level,
unaccelerated flight with
constantTSFC and L1/2/D.
Range: Jet Aircraft
To maximize range:
Fly at minimumTSFC
Maximum fuel weight
Maximum L1/2/D
Fly at high altitudes (low density)
)
(
2
2 2
1
1
2
1
0
2
1
W
W
C
C
S
c
R
D
L
t
−
=


How is (L1/2/D)max computed?
)
(
2
0
,
2
/
1
2
/
1
L
L
D
L
D
L
C
f
KC
C
C
C
C
=
+
=
( )
( )
0
)
2
(
)
2
/
1
(
)
(
' 2
2
0
,
2
/
1
2
/
1
2
0
,
=
+
−
+
=
−
L
D
L
L
L
L
D
L
KC
C
KC
C
C
KC
C
C
f
( ) 0
)
2
(
)
2
/
1
(
2
/
1
2
/
1
2
0
, =
−
+
−
L
L
L
L
D KC
C
C
KC
C
i
D
L
D C
KC
C ,
2
0
, 3
3 =
=
πeAR
K /
1
Where =
How is (L1/2/D)max computed?
K
C
C
KC
C D
L
L
D 3
3 0
,
2
0
, =

=
0
,
0
,
0
, )
3
/
4
(
)
3
/
1
( D
D
D
D C
C
C
C =
+
=
0
,
,
,
0
, )
3
/
1
(
3 D
i
D
i
D
D C
C
C
C =

=
( ) 4
/
1
3
0
,
0
,
2
/
1
0
,
max
2
/
1
)
(
1
256
27
)
3
/
4
(
3








=
=








D
D
D
D
L
C
K
C
K
C
C
C
Summary
4
/
1
3
0
,
max
2
/
1
)
(
1
256
27








=








D
D
L
C
K
C
C
( ) )
4
/(
1 0
,
max D
D
L KC
C
C =
4
3
3
1
0
,
max
2
3
3
4
1








=








D
D
L
KC
C
C
πeAR
K /
1
Where =
i
D
D C
C ,
0
, 3
=
i
D
D C
C ,
0
, =
i
D
D C
C ,
0
,
3 =
Example
Estimate the maximum range for the CJ-1.
)
(
2
2 2
1
1
2
1
0
max
2
1
max W
W
C
C
S
c
R
D
L
t
−








=


Normal gross weight = 19,815 lb
Fuel capacity: 1119 gal of kerosene
Specific fuel consumption = 0.6 lb of fuel/(lb thrust)(h)
Parasite drag coefficient CD,o = 0.02
Oswald efficiency factor e = 0.81
Example
Estimate the maximum range for the CJ-1.
1
-
4
s
10
x
667
.
1
s
3600
h
1
(lb)(h)
lb
6
.
0 −
=
=
t
c
lb
7463
)
67
.
6
(
1119 =
=
f
W
Since kerosene weighs 6.67 lb/gal,
lb
12352
7463
19815
1 =
−
=
W
4
.
23
)
02
.
0
(
)
93
.
8
)(
81
.
0
(
256
27
)
(
1
256
27
4
/
1
3
4
/
1
3
0
,
max
2
/
1
=








=








=







 
D
D
L
C
K
C
C
Example
Estimate the maximum range for the CJ-1.
)
(
2
2 2
1
1
2
1
0
max
2
1
max W
W
C
C
S
c
R
D
L
t
−








=


)
12352
19815
)(
4
.
23
(
)
318
(
001184
.
0
2
10
x
667
.
1
2 2
1
2
1
4
max −
= −
R
miles
3630
ft
10
x
2
.
19 6
max =
=
R
Endurance: Piston-Propeller
( )( )
hour
HP
fuel
of
lb
SFC =
To stay in the air for the longest time,
fly at minimum pounds of fuel per hour.
For maximum endurance, fly at minimum power required.
( )
)
(SFC)(P
hour
fuel
of
lb
R
a
Endurance: Piston-Propeller

/

= DV
P
cP
dW
dt
P
dt
dW
c −
=

−
=
1
 
 
=
=
=
0
1
0
1
0
W
W
W
W
E
DV
dW
c
cP
dW
dt
E

L
SC
W
V 
 = 
2
 
=
0
1
2
3
2
W
W
L
D
L
W
dW
SC
C
C
c
E


W
dW
DV
L
c
E
W
W
 
=
0
1

( ) ( )
2
1
0
2
1
1
2
1
2
3
2
−
−
 −
= W
W
S
C
C
c
E
D
L


Assumptions made: level, unaccelerated
flight with constant SFC, η and L3/2/D.
Endurance: Piston-Propeller
( ) ( )
2
1
0
2
1
1
2
1
2
3
2
−
−
 −
= W
W
S
C
C
c
E
D
L


To maximize endurance, fly at:
Largest propeller efficiency, η
Lowest possible SFC
Largest fuel weight
Fly at maximum CL
3/2/CD
Flight at sea level
How do we compute for (L3/2/D)max?
eAR
C
C
C L
D
D i

2
0
,
3 =
=
( ) 4
3
3
1
0
,
0
,
4
3
0
,
max
2
3
3
4
1
4
3








=
=








D
D
D
D
L
C
eAR
C
eAR
C
C
C 

eAR
C
C D
L 
0
,
3
=
i
D
D C
C =
0
,
3
How do we compute for (L3/2/D)max?
At PRmin
Thus,
4
3
3
1
0
,
max
2
3
3
4
1








=








D
D
L
C
eAR
C
C 
(L/D)max VS (L3/2/D)max
Locating (L/D)max in the PR curve
SUMMARY
At minimum thrust required At minimum power required
i
D
D C
C ,
0
, =
0
,
max
4
/ D
D
L C
eAR
C
C 
=






i
D
D C
C =
0
,
3
2
1
0
,
,
3
1
2
min
, 







=


S
W
eAR
C
V
D
PR


2
/
1
1
2
min
,








=
 S
W
eAR
C
V
o
R
D
T


( ) 4
3
3
1
0
,
0
,
4
3
0
,
max
2
3
3
4
1
4
3








=
=








D
D
D
D
L
C
eAR
C
eAR
C
C
C 

CP-1: A light, single-engine, propeller-driven, private airplane,
approximately modelled after the Cessna Skylane, having the following
characteristics:
Example
Aspect Ratio = 7.37
Parasite drag coefficient CD,o = 0.025
Oswald efficiency factor, e = 0.8
Example
Estimate the maximum endurance for the CP-1.
81
.
12
3
4
1
4
3
3
1
0
,
max
2
3
=








=








D
D
L
C
eAR
C
C 
( ) ( )
2
1
0
2
1
1
2
1
max
2
3
max 2
−
−
 −








= W
W
S
C
C
c
E
D
L


  





−
= − 2
/
1
2
/
1
2
1
7
2950
1
2583
1
)
174
)(
002377
.
0
(
2
)
81
.
12
(
10
x
7
.
2
8
.
0
E
h
4
.
14
s
10
x
19
.
5 4
=
=
E
Endurance: Jet Aircraft
( )( )
hour
thrust
of
lb
fuel
of
lb
TSFC =
To stay in the air for the longest time,
fly at minimum pounds of fuel per hour.
For maximum endurance, fly at minimum thrust required.
( )
)
(TSFC)(T
)
(TSFC)(T
hour
fuel
of
lb
R
A a
a
Endurance: Jet Aircraft
A
t
A
t
T
c
dW
dt
T
dt
dW
c −
=

−
=
1

 −
=
=
1
0
0
W
W A
t
E
T
c
dW
dt
E

−
=
1
0
1
W
W t W
dW
D
L
c
E
1
0
ln
1
W
W
C
C
c
E
D
L
t
=
Assumptions made:
level, unaccelerated
flight with constant
TSFC and L/D.
Endurance: Jet Aircraft
1
0
ln
1
W
W
C
C
c
E
D
L
t
=
To maximize endurance, fly at:
MinimumTSFC
Maximum fuel weight
Maximum L/D
Example
Estimate the maximum endurance for the CJ-1.
h
3
.
13
s
10
x
79
.
4 4
=
=
E
1
0
max
max ln
1
W
W
C
C
c
E
D
L
t








=
12352
19815
ln
)
9
.
16
(
10
x
667
.
1
1
4
max −
=
E
Graphical Summary
Coverage Airplane Performance
Static Performance
(zero acceleration)
Dynamic Performance
(finite acceleration)
Thrust Required
Thrust Available
Maximum
Velocity
Power Required
Power Available
Maximum Velocity
Rate of Climb
Takeoff
Landing
Equations of Motions
V-n Diagram
Turning Flight
Range and Endurance
Time to Climb
Maximum Altitude
Gliding Flight
Service Ceiling
Absolute Ceiling
Ground Roll (Liftoff Distance)
Preliminary (purely kinematic) considerations
dt
dV
m
ma
F =
=
dt
m
F
dV =
t
m
F
dt
m
F
dV
V
t
V
=
=
= 
 '
'
0
0
tdt
m
F
Vdt
ds =
=
2
'
'
'
2
0
0
t
m
F
dt
t
m
F
ds
s
t
s
=
=
= 

F
m
V
F
Vm
m
F
s
2
2
1 2
2
=






=
Ground Roll (Liftoff Distance)
Rolling resistance
mr = 0.02 relatively smooth paved surface
mr = 0.10 grass field
( )
dt
dV
m
L
W
D
T
R
D
T
F r =
−
−
−
=
−
−
= m
Forces in an aircraft during takeoff ground roll
Coefficient of Rolling Friction
Ground Roll
F
m
V
s
2
2
=
Is the assumption of a
constant force
reasonable?
( )
L
W
D
T
F r −
−
−
= m
Ground Roll
L
SC
V
L
2
2
1


= 
Is the assumption of a
constant force
reasonable?








+
= 

eAR
C
C
S
V
D L
D



2
2
0
2
1
( )
( )2
2
16
1
16
b
h
b
h
+
=

Ground Effect
( )
( )2
2
16
1
16
b
h
b
h
+
=

Reduction of induced drag
by a factor Φ≤1.








+
= 

eAR
C
C
S
V
D L
D



2
2
0
2
1
Ground Effect
Ground Roll
Is the assumption of a
constant force
reasonable?
T is approximately constant
(especially for a jet)
The difference between the
drag and friction combined
and the thrust is also
approximately constant
( ) constant?
=
−
−
−
= L
W
D
T
F r
m
Ground Roll
AssumeT is constant.
Assume an average value
ofT-[D+μR(W-L)].
( ) ave
r
eff L
W
D
T
F ]
[ −
−
−
= m
Shevell suggests computing
this average atV=0.7VLO.
eff
LO
LO
F
g
W
V
s
2
)
(
2
=
Ground Roll
max
,
2
2
.
1
2
.
1
L
stall
LO
SC
W
V
V

=
=

}
)]
(
[
{
44
.
1
max
,
2
ave
R
L
LO
L
W
D
T
SC
g
W
s
−
+
−
=
 m

T
SC
g
W
s
L
LO
max
,
2
44
.
1

=

Ground Roll
}
)]
(
[
{
44
.
1
max
,
2
ave
R
L
LO
L
W
D
T
SC
g
W
s
−
+
−
=
 m
 T
SC
g
W
s
L
LO
max
,
2
44
.
1

=

Lift-off distance:
Is very sensitive to weight; varies asW2
Depends on ambient density
May be decreased by:
Increasing wing area, S
Increasing CL,max
Increasing thrust,T
Example
Estimate the liftoff distance for the CJ-1 at sea level. Assume a paved
runway; hence, μr = 0.02. Also, during the ground roll, the angle of
attack of the airplane is restricted by the requirement that the tail not
drag the ground; therefore, assume that CL,max during ground roll is
limited to 1.0. Also, when the airplane is on the ground, the wings are 6
ft above the ground.
( )
( )
764
.
0
16
1
16
2
2
=
+
=
b
h
b
h

Example
ft/s
230
)
0
.
1
)(
318
(
002377
.
0
)
19815
(
2
2
.
1
2
2
.
1
2
.
1
max
,
=
=
=
=
 L
stall
LO
SC
W
V
V

ft/s
3
.
160
7
.
0 =
LO
V
lb
9712
)
0
.
1
)(
318
(
)
3
.
160
)(
002377
.
0
)(
2
/
1
(
2
1 2
2
=
=
= 
 L
SC
V
L 
lb
7
.
520
)
93
.
8
)(
81
.
0
(
0
.
1
764
.
0
02
.
0
)
318
(
)
3
.
160
)(
002377
.
0
(
2
1
2
1
2
2
2
2
0
=






+
=








+
= 





eAR
C
C
S
V
D L
D
Example
}
)]
(
[
{
44
.
1
max
,
2
ave
R
L
LO
L
W
D
T
SC
g
W
s
−
+
−
=
 m

)]}
9712
19815
)(
02
.
0
(
7
.
520
[
7300
){
0
.
1
)(
318
)(
002377
.
0
(
2
.
32
)
19815
(
44
.
1 2
−
+
−
=
LO
s
ft
3532
=
LO
s
Total Takeoff Distance
Total takeoff distance as per FAR
35 ft (jet-powered civilian transport)
50 ft (all other airplanes)
ground roll
Takeoff Segments
Balanced Field Length
A + B
Distance up toV1
Additional distance travelled =
Distance required to clear an obstacle
= Distance required for a full stop
Distance to clear obstacle

sin
R
sa =
Where,
g
V
R stall
2
)
(
96
.
6
=
)
1
(
cos 1
R
h
−
= −

h is the obstacle height.
Analysis is based on pull up maneuver
Landing Roll
 
=
0
0
'
'
L
s
t
dt
t
m
F
ds
2
2
t
m
F
sL −
=
F
m
V
sL
2
2
−
=
Can we assume a
constant landing
force just as we did
in takeoff
performance?
Landing Roll
( )
dt
dV
m
L
W
D
R
D
F r =
−
+
−
=
+
−
= ]
[
)
( m
( )
dt
dV
m
L
W
D
T
R
D
T
F r =
−
−
−
=
−
−
= m
0 0
Landing Roll
( )
dt
dV
m
L
W
D
F r =
−
+
−
= ]
[ m
Assume a constant
effective force,
( ) ave
r
eff L
W
D
F ]
[ −
+
−
= m
Compute this average by
evaluating the quantity at
0.7VT , where VT is the
touchdown velocity.
Landing Roll
F
m
V
sL
2
2
−
=
T
V
R
T
L
L
W
D
g
W
V
s
7
.
0
2
)]
(
[
2
)
/
(
−
+
−
=
m
max
,
2
3
.
1
3
.
1
L
stall
T
SC
W
V
V

=
=

T
V
R
L
L
L
W
D
SC
g
W
s
7
.
0
max
,
2
)]
(
[
69
.
1
−
+
−
=
 m

μR = 0.4 for paved surface
Landing Roll
T
V
R
R
L
L
L
W
D
T
SC
g
W
s
7
.
0
max
,
2
)]
(
[
69
.
1
−
+
+
−
=
 m

with reverse thrust
0
with spoilers
Example
Estimate the landing ground roll distance at sea level for the CJ-1. No
thrust reversal is used; however, spoilers are employed such that L = 0.The
spoilers increase the zero-lift, drag coefficient by 10 percent.The fuel
tanks are essentially empty, so neglect the weight of any fuel carried by
the airplane.The maximum lift coefficient, with flaps fully employed at
touchdown, is 2.5.
ft/s
6
.
148
)
5
.
2
)(
318
(
002377
.
0
)
12353
(
2
3
.
1
2
3
.
1
3
.
1
max
,
=
=
=
=
 L
stall
T
SC
W
V
V

ft/s
104
7
.
0 =
T
V
022
.
0
)
02
.
0
(
1
.
0
02
.
0
0
, =
+
=
D
C
Example
0
0 =

= L
CL
lb
9
.
89
)
022
.
0
)(
318
(
)
104
)(
002377
.
90
2
1
2
1 2
2
0
=
=
= 
 D
SC
V
D 
T
V
R
L
L
W
D
SC
g
W
s
7
.
0
max
,
2
)
(
69
.
1
m
 +
−
=

ft
842
)]
12352
(
4
.
0
9
.
89
)[
5
.
2
)(
318
)(
002377
.
0
(
2
.
32
)
12353
(
69
.
1 2
=
+
−
=
L
s
Total Landing Distance


Approach Distance

cos
W
L =

sin
W
T
D +
=
W
T
D
L
W
T
W
D
−

−
=
1
sin

cos
R
R
hf −
=
g
V
R
f
2
.
0
2
=

tan
50 f
a
h
s
−
=
from pull up maneuver analysis
Flare Distance

sin
R
sf =

W
L =

cos
Load Factor
Turn Radius
Turn Rate
Level Turn

 −
=
=

V
n
g
R
V
dt
d 1
2


2
2
W
L
Fr −
=
W
L
n 
1
2
−
= n
W
Fr
R
V
m
Fr
2

=
1
2
2
−
= 
n
g
V
R
Constraints on n and V∞
At any given velocity the maximum possible load factor for a
sustained level turn is constrained by the maximum thrust
available.
2
/
1
0
,
2
max
2
max
/
2
1
)
/
(
2
1
















−






= 



S
W
C
V
W
T
S
W
K
V
n D


eAR
K

1
=
Constraints on n and V∞
2
/
1
0
,
2
max
2
max
/
2
1
)
/
(
2
1
















−






= 



S
W
C
V
W
T
S
W
K
V
n D


max
max 





=
W
T
D
L
n
n is also constrained by
CLmax
S
W
C
V
n L
/
2
1 max
,
2
max 

= 
max
max
1
cos
n
=

Constraints on n and V∞
V∞ is constrained by stall.
max
,
2
L
stall
C
n
S
W
ρ
V

=
n is also constrained by regulation. Example:
category)
(utility
4
.
4
=
n
Minimum Turn Radius
Minimum R occurs at the right combination of n and V∞.
)
/
(
)
/
(
4
)
( min
W
T
S
W
K
V R

 =

2
0
,
)
/
(
4
2
min
W
T
KC
n D
R −
=
2
0
,
min
)
/
/(
4
1
)
/
(
)
/
(
4
W
T
KC
W
T
g
S
W
K
R
D
−
=


1
2
2
−
= 
n
g
V
R
Maximum Turn Rate
Maximum ω occurs at the right combination of n and V∞.
4
/
1
0
,
2
/
1
)
/
(
2
)
( max 













=


D
C
K
S
W
V


2
/
1
0
,
1
/
min








−
=
D
KC
W
T
n
















−
= 

2
/
1
0
,
max
2
/
/ K
C
K
W
T
S
W
q D



−
=
V
n
g 1
2

Pull-Up Maneuver
( )
1
2
−
= 
n
g
V
R

cos
2
W
L
R
V
m −
=

( )

−
=
V
n
g 1

W
L
R
V
m −
=

2
Pull-Down Maneuver
( )
1
2
+
= 
n
g
V
R
( )

+
=
V
n
g 1

W
L
R
V
m +
=

2
For large load factors
gn
V
R
2

=

=
V
gn

R for level turn, pull-up and pull down
ω for level turn, pull-up and pull down
For large load factors
S
W
gC
R
L max
,
min
2

=

)
/
(
2
max
max
,
max
S
W
n
C
g L

=


Minimum R for level turn, pull-up and pull down
Maximum ω for level turn, pull-up and pull down
S
W
C
V
n
W
SC
V
W
L
n
L
L
max
,
2
max
2
2
1
2
1




=
=
=


V-n Diagram
Topics Discussed Airplane Performance
Static Performance
(zero acceleration)
Dynamic Performance
(finite acceleration)
Thrust Required
Thrust Available
Maximum
Velocity
Power Required
Power Available
Maximum Velocity
Rate of Climb
Takeoff
Landing
Equations of Motions
V-n Diagram
Turning Flight
Range and Endurance
Time to Climb
Maximum Altitude
Gliding Flight
Service Ceiling
Absolute Ceiling
• John D. Anderson. Introduction to Flight
• John D. Anderson, Airplane Performance and Design
References

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Performance.pdf

  • 1.
  • 2. We will talk about static and dynamic performance.
  • 3. We will answer questions such as: How fast? How high? How far? How long can an aircraft fly?
  • 4. Coverage Airplane Performance Static Performance (zero acceleration) Dynamic Performance (finite acceleration) Thrust Required Thrust Available Maximum Velocity Power Required Power Available Maximum Velocity Rate of Climb Takeoff Landing Equations of Motions V-n Diagram Turning Flight Range and Endurance Time to Climb Maximum Altitude Gliding Flight Service Ceiling Absolute Ceiling Drag Polar
  • 5.
  • 6. A Prerequisite Performance analysis hinges on knowledge of the airplane drag polar.
  • 7. What is a drag polar? It is a term coined by Eiffel. The same monsieur of Eiffel tower fame. The same guy who designed Quiapo bridge (a.k.a. Quezon bridge) It is a graph or an equation that accounts for all types of drag in an airplane and how it relates to lift.
  • 8. Quezon bridge: FEATI’s vantage point Gustav’s Tower
  • 9. What types of drag are included then? Let’s enumerate. Bullets would come in handy for this sort of job.
  • 10. What are the different types of drag? ▪ Skin friction drag ▪ Pressure drag ▪ Profile drag ▪ Interference drag ▪ Parasite drag ▪ Induced drag ▪ Zero-lift drag ▪ Drag due to lift ▪ Wave drag
  • 11. Drag Types Skin-friction drag. Drag due to frictional shear stress integrated over the surface.
  • 12. Pressure drag due to flow separation (form drag): The drag due to the pressure imbalance in the drag direction caused by separated flow. Drag Types
  • 13. Profile drag. The sum of skin friction drag and form drag. (The term profile drag is usually used in conjunction with two-dimensional airfoils; it is sometimes called section drag.) Drag Types
  • 14. Interference drag. An additional pressure drag caused by the mutual interaction of the flow fields around each component of the airplane. The total drag of the combined body is usually greater than that of the sum of its individual parts; the difference is the interference drag. Drag Types
  • 15. Parasite drag. The term used for the profile drag for a complete airplane. It is that portion of the total drag associated with skin friction and pressure drag due to flow separation, integrated over the complete airplane surface. It includes interference drag. Drag Types
  • 16. Induced drag. A pressure drag due to the pressure imbalance in the drag direction caused by the induced flow (downwash) associated with the vortices created at the tips of finite wings. Drag Types
  • 17. Zero-lift drag. (Usually used in conjunction with a complete airplane configuration.) The parasite drag that exists when the airplane is at its zero-lift angle of attack, that is, when the lift of the airplane is zero. Drag Types
  • 18. Drag due to lift. (Usually used in conjunction with a complete airplane.) That portion of the total airplane drag measured above the zero-lift drag. It consists of the change in parasite drag when the airplane is at an angle of attack different from the zero-lift angle, plus the induced drag from the wings and other lifting components of the airplane. Drag Types
  • 19. Wave drag. The pressure drag associated with transonic and supersonic flow (or shock waves, hence the name). It can be expressed as the sum the zero-lift wave drag and wave drag due to lift. Drag Types
  • 20. Total Drag Skin Friction Drag Pressure Drag Induced Drag Wave Drag Note : Profile Drag = Skin Friction Drag + Form Drag Total Drag Form Drag (Drag due to flow separation) drag induced drag profile drag total + =
  • 21. Drag Polar eAR π C C C L d D 2 + = eAR C C C L D D  2 0 , + = A wing or airfoil have its own drag polar An airplane have its own drag polar profile drag zero-lift drag
  • 22. Drag Polar eAR C C C L e D D  2 , + = parasite drag coefficient -profile drag of wing -friction and pressure drag of: tail surfaces fuselage engine nacelles landing gear other components exposed to the flow -a function of angle of attack lift span efficiency factor induced drag coefficient
  • 23. Drag Polar 2 0 , , L D e D rC C C + = 2 0 , ) 1 ( L D D C eAR r C C  + + = eAR π C C C L e D D 2 , + = eAR π C C C L D D 2 0 , + =
  • 24. Drag polar of a complete airplane i D D L D D C C eAR C C C , 0 , 2 0 , + = + =  induced drag coefficient parasite drag coefficient at zero lift Oswald’s efficiency factor
  • 25. Drag polar of a complete airplane eAR C C C L D D  2 0 , + =
  • 29. Why is it called drag polar?
  • 30.
  • 33. For level, unaccelerated flight, If thrust line is aligned with flight path, Equations of Motion
  • 34. If thrust line is aligned with flight path, Level, unaccelerated flight Equations of Motion
  • 35.
  • 36. Thrust Required Thrust required for steady level flight at given speed.
  • 37. D TR = NOTE: Thrust Required is a function of velocity. It has two components. It has a minimum. Thrust Required for Level, Unaccelerated Flight at a given velocity
  • 38. Thrust Required for Level, Unaccelerated Flight D TR = ) ( 2 1 ) ( 2 1 2 1 2 2 2 2 eAR C C S V C C S V SC V D T L D D D D R o i o     + = + = = =       ) ) 2 / 1 ( ( 2 1 2 2 2 eAR S V L C S V T o D R            + =     ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R        + =
  • 39. ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R        + = zero-lift thrust required lift-induced thrust required Thrust Required for Level, Unaccelerated Flight
  • 40. Applying a first and a second derivative test to this function will confirm the existence of a minimum. This minimum will exist at velocity, 2 / 1 1 2 min ,         =  S W eAR C V o R D T   ) ( ) 1 )( 2 1 ( 2 1 2 2 2      = + = V f eAR S V W C S V T o D R    Thrust Required for Level, Unaccelerated Flight
  • 42. Thrust Required: Alternative Approach D TR = L D R C C W T W L = = Since D L R C C W T / = Since we have already established the existence of a minimum thrust required, this equation implies the existence of a maximum lift-to-drag ratio.
  • 43. Thrust Required: Alternative Approach Indeed there is a maximum L/D ratio exhibited by every aircraft. You will see how this ratio is an indicator of performance (aerodynamic efficiency) of an aircraft.
  • 44. Thrust Required: Alternative Approach D L W C C W T D L R / / = =
  • 45. Different points on TR curve correspond to different angles of attack.         + = = = = =      eAR C C S q SC q D SC q SC V W L L D D L L   2 0 , 2 2 1 At a: Large q∞ Small CL and a D large At b: Small q∞ Large CL (or CL 2) and a to support W D large Thrust Required: Alternative Approach
  • 46. Thrust Required Computation TR is thrust required to fly at a given velocity in level, unaccelerated flight 1. Select a flight speed,V∞ and calculate CL. S V W CL 2 2 1   =  eAR C C C L D D  2 0 , + = 2. Calculate CD. 3. Calculate CL/CD and calculateTR.       = D L R C C W T
  • 47. CP-1: A light, single-engine, propeller-driven, private airplane, approximately modelled after the Cessna Skylane, having the following characteristics: Wingspan = 35.8 ft Wing area = 174 ft2 Normal gross weight = 2950 lb Fuel capacity: 65 gal of aviation gasoline Power plant: one-piston engine, 230 hp (SL) Specific fuel consumption= 0.45 lb/(hp)(h) Parasite drag coefficient CD,o = 0.025 Oswald efficiency factor, e = 0.8 Propeller efficiency = 0.8 Example
  • 49. Example 357 . 0 ) 174 ( ) 200 )( 002377 . 0 ( 2 1 2950 2 1 2 2 = = =   S V W CL  AtV=200 ft/s = 136.4 mi/h 37 . 7 174 ) 8 . 35 ( 2 2 = = = S b AR 0319 . 0 ) 37 . 7 )( 8 . 0 ( ) 357 . 0 ( 025 . 0 2 2 0 , = + = + =  eAR C C C L D D lb 263 2 . 11 2950 / = = = D L W TR 2 . 11 0319 . 0 357 . 0 = = = D L C C D L 1 2 3
  • 51. CJ-1: A jet-powered executive aircraft, approximately modelled after the Cessna Citation 3, having the following characteristics: Wingspan = 53.3 ft Wing area = 318 ft2 Normal gross weight = 19,815 lb Fuel capacity: 1119 gal of kerosene Power plant: two turbofan engines of 3650-lb thrust each at sea level Specific fuel consumption = 0.6 lb of fuel/(lb thrust)(h) Parasite drag coefficient CD,o = 0.02 Oswald efficiency factor e = 0.81 Example
  • 53. Example 210 . 0 ) 318 ( ) 500 )( 002377 . 0 ( 2 1 19815 2 1 2 2 = = =   S V W CL  AtV=500 ft/s = 341 mi/h 93 . 8 318 ) 3 . 53 ( 2 2 = = = S b AR 022 . 0 ) 93 . 8 )( 81 . 0 ( ) 21 . 0 ( 02 . 0 2 2 0 , = + = + =  eAR C C C L D D lb 2075 55 . 9 19815 / = = = D L W TR 55 . 9 022 . 0 21 . 0 = = = D L C C D L 1 2 3
  • 55. How do we compute for (L/D)max? At TRmin we found (by differentiating TR with respect to V and equating to zero), 2 / 1 1 2 min ,         =  S W eAR C V o R D T   i D L D C eAR C C , 2 0 , = =  From this formula for V at TRmin, the following relationship (which has already been revealed in the graph) can be derived: 0 , 0 , 0 , 4 / 2 / / D D D D L C eAR C eAR C C C   = = Thus, and this is a maximum because an (L/D)max is simultaneous with a TRmin.
  • 56. i D L D C eAR C C , 2 0 , = =  How do we compute for (L/D)max? 0 , max 4 / D D L C eAR C C  =       At TRmin Thus,
  • 57. How do we compute for TRmin? You can substitute Or you can substitute 0 , max 4 / ) / ( D D L C eAR C C  = ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R        + =       = D L R C C W T to to 2 / 1 1 2 min ,         =  S W eAR C V o R D T  
  • 59. Effects of altitude onTR ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R    + = Note that the minimum thrust required is independent of altitude. 2 / 1 1 2 min ,         = S W eAR C V o R D Lower T   2 / 1 1 2 min ,         = S W eAR C V o R D Higher T   max min ,       = D L R C C W T
  • 60.
  • 62.
  • 63. Maximum Velocity: Graphical The intersection of the TA and TR curve gives Vmax at a certain altitude.
  • 64. Example Calculate the maximum velocity for the sample jet plane. Vmax = 975 ft/s = 665 mi/h Intersection of TR curve and maximum TA defines maximum flight speed of airplane.
  • 65. Example Some remarks. Computation of TR curve assumed constant CD,o At this speed, drag divergence effects are significant, and adds to the CD,o
  • 66. Maximum Velocity: Analytical         + = = =   eAR C C S q SC q T D L D D  2 0 , S q W CL  = eAR S q W SC q eAR S q W C S q T D D       + =         + = 2 0 , 2 2 2 0 , 0 2 0 , 2 = + −   eAR S W T q SC q D  Steady, level flight:T = D Steady, level flight: L =W Substitute into drag equation Turn this equation into a quadratic equation (by multiplying by q∞) and rearranging.
  • 67. Maximum Velocity: Analytical 2 1 0 , 0 , 2 max max max 4               −             +             =  D D A A C eAR C W T S W S W W T V   Solving the quadratic equation and setting thrust, T, to maximum available thrust, TA,max results in,
  • 68. Maximum Velocity: Design Considerations 2 1 0 , 0 , 2 max max max 4               −             +             =  D D A A C eAR C W T S W S W W T V   • TA,max does not appear alone, but only in ratio: (TA/W)max • S does not appear alone, but only in ratio: (W/S) • Vmax does not depend on thrust alone or weight alone, but rather on ratios • (TA/W)max: maximum thrust-to-weight ratio • W/S: wing loading
  • 69. Maximum Velocity: Design Considerations • Vmax also depends on density (altitude), CD,0, eAR • Increase Vmax by • Increase maximum thrust-to-weight ratio, (TA/W)max • Increasing wing loading, (W/S) • Decreasing zero-lift drag coefficient, CD,0 2 1 0 , 0 , 2 max max max 4               −             +             =  D D A A C eAR C W T S W S W W T V  
  • 70. Example CalculateVmax for the CP-1. 2 lb/ft 95 . 16 174 2950 = = S W Wingspan = 35.8 ft Wing area = 174 ft2 Normal gross weight = 2950 lb Fuel capacity: 65 gal of aviation gasoline Power plant: one-piston engine, 230 hp (SL) Specific fuel consumption= 0.45 lb/(hp)(h) Parasite drag coefficient CD,o = 0.025 Oswald efficiency factor, e = 0.8 Propeller efficiency = 0.8 3 - 2 0 , 10 x 4066 . 5 ] 174 / ) 8 . 35 )[( 8 . 0 ( ) 025 . 0 ( 4 4 = =  eAR CD 3 5 0 , slug/ft 10 x 9425 . 5 ) 025 . 0 ( 002377 . 0 −  = = D C  2 1 0 , 0 , 2 max max max 4               −             +             =  D D A A C eAR C W T S W S W W T V  
  • 71. Example CalculateVmax for the CP-1. lb)/s (ft 10 x 012 . 1 ) 550 )( 230 ( 8 . 0 5  = = = =  P P V T A A  ( ) max max V P TA  = For maxTA and PA,V∞ =Vmax max max max 305 . 34 1 V V W P W TA = =        ? max =       W TA 2 1 0 , 0 , 2 max max max 4               −             +             =  D D A A C eAR C W T S W S W W T V  
  • 72. Example CalculateVmax for the CP-1. 2 / 1 3 2 max max max max max 10 x 4066 . 5 305 . 34 305 . 34 97 . 558         −         +         = − V V V Solve this by trial and error.
  • 73.
  • 74. Jets Engines are usually rated inThrust Thrust is a Force with units (N = kg m/s2) For example, the PW4000-112 is rated at 98,000 lb of thrust Piston-Driven Engines are usually rated in terms of Power Power is a precise term and can be expressed as: Energy /Time with units (kg m2/s2) / s = kg m2/s3 = Watts Note that Energy is expressed in Joules = kg m2/s2 Force *Velocity with units (kg m/s2) * (m/s) = kg m2/s3 =Watts Usually rated in terms of horsepower (1 hp = 550 ft lb/s = 746W) Why is there a need for a new parameter?
  • 75. PR vs. V∞ curve qualitatively resembles TR vs. V∞ curve. Power Required PR = TRV∞
  • 76. Power Required NOTE: Power Required is a function of velocity. It has two components. It has a minimum.
  • 77. Power Required ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R        + = ) 1 )( 2 1 ( 2 1 2 3 eAR S V W C S V P o D R      + = zero-lift power required lift-induced power required  = V T P R R  V zero-lift PR ~V3 lift-induced PR ~ 1/V
  • 78. Power Required, Minimum ) ( ) 1 )( 2 1 ( 2 1 2 3    = + = V f eAR S V W C S V P o D R    Get f’(V∞). Equate to zero. Solve forV∞ in f’(V∞)=0 to getVPR,min. Substitute V∞ in f(V∞) to get PR,min. The results are…
  • 79. Power Required, Minimum 2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR   The results are… At PRmin , i D D C C = 0 , 3 and
  • 80. Power Required 2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR   i D D C C = 0 , 3 2 / 1 1 2 min ,         =  S W eAR C V o R D T   min , min , 4 1 3 1 R R T P V V       =
  • 81.   = = V C C W V T P D L R R Power Required: Alternative Approach L SC V W L 2 2 1   = =  L SC W V   =  2 L D L R R SC W C C W V T P   = =  2 C 1 2 2 / 3 L 3 2 3 D L D R C SC C W P a  = x
  • 83. Example  = V T P R R Calculate the power required curve for (a) the CP-1 at sea level and (b) the CJ-1 at an altitude of 22,000 ft.
  • 85. Example  = V T P R R 3 slug/ft 001184 . 0 =   At an altitude of 22,000 ft Thrust required is re-computed using this density.
  • 87. How do we compute for (L3/2/D)max? eAR C C C L D D i  2 0 , 3 = = ( ) 4 3 3 1 0 , 0 , 4 3 0 , max 2 3 3 4 1 4 3         = =         D D D D L C eAR C eAR C C C   eAR C C D L  0 , 3 =
  • 88. i D D C C = 0 , 3 How do we compute for (L3/2/D)max? At PRmin Thus, 4 3 3 1 0 , max 2 3 3 4 1         =         D D L C eAR C C 
  • 90. Locating (L/D)max in the PR curve
  • 91. How do we compute for PR,min? You can substitute Or you can substitute to to 2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR   ) 1 )( 2 1 ( 2 1 2 3 eAR S V W C S V P o D R      + = 4 3 3 1 0 , max 2 3 3 4 1         =         D D L C eAR C C  C 1 2 D 2 3 L 3         =  C S ρ W PR
  • 92. Effects of altitude on PR 2 1 0 0 , , 2 1 0 0         =         =     R ALT R ALT P P V V C 1 2 D 2 3 L 3         =  C S W PR  2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR  
  • 93. Effects of altitude on PR 2 1 0 0 , , 2 1 0 0         =         =     R ALT R ALT P P V V
  • 94. Effects of altitude on PR 2 1 0 0 , , 2 1 0 0         =         =     R ALT R ALT P P V V
  • 95. SUMMARY thrust required power required ) 1 )( 2 1 ( 2 1 2 3 eAR S V W C S V P o D R      + = C 1 2 D 2 3 L 3         =  C S W PR  ) 1 )( 2 1 ( 2 1 2 2 2 eAR S V W C S V T o D R        + = D L R C C W T / =
  • 96. SUMMARY At minimum thrust required At minimum power required i D D C C , 0 , = 0 , max 4 / D D L C eAR C C  =       i D D C C = 0 , 3 2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR   2 / 1 1 2 min ,         =  S W eAR C V o R D T   ( ) 4 3 3 1 0 , 0 , 4 3 0 , max 2 3 3 4 1 4 3         = =         D D D D L C eAR C eAR C C C  
  • 97.
  • 100. Power Available VS Thrust Available
  • 101.
  • 104. Effects of Altitude on Maximum Velocity
  • 105. Effects of Altitude on Maximum Velocity
  • 106. Minimum Velocity Sometimes minimum or stall velocity is dictated by powerplant considerations. It is true, Chuck Norris’ legendary kick can also cause a stall, but…
  • 107.
  • 109. Rate of Climb  sin    + = WV DV TV  sin W D T + =  sin /  =V C R  sin    = − V W DV TV W DV TV C R   − = /
  • 110. Rate of Climb W DV TV C R   − = / Power Available ~ Power Required (for small Ѳ)  sin W D T + =   − = DV TV power excess W C R power excess / =
  • 112. Rate of Climb VS Altitude
  • 113. Example Calculate the rate of climb vs velocity at sea level for (a) the CP-1 and (b) the CJ-1. ft/min 1398 ft/s 3 . 23 2950 32600 - 10120 2950 P P power excess ) / ( R A = = = − = = W C R AtV = 150 ft/s PR = 32,600 ft-lb/s and PA = 10,120 ft-lb/s. Hence,
  • 117. R/Cmax: Analytical ( ) ( )2 max 2 max / / 3 1 1 W T D L Z + + = ( ) ( ) ( ) ( )       − −               =  Z D L W T Z W T C Z S W C R D 2 max 2 max 2 / 3 max 2 / 1 0 , max / / 2 3 6 1 3 / /  ( ) ( ) 2 / 3 max 0 , max max / 1 / 8776 . 0 / D L C S W W P C R D  −       =   For a piston-propeller aircraft: For a jet aircraft: Where:
  • 118.
  • 121. Example Calculate the absolute and service ceilings for (a) the CP-1 and (b) the CJ- 1. W C R power excess maximum ) / ( max =
  • 122. Example Calculate the absolute and service ceilings for (a) the CP-1 and (b) the CJ- 1. (a) the CP-1 (b) the CJ-1 service ceilings = 25,000 ft absolute ceilings = 27,000 ft service ceilings = 48,000 ft absolute ceilings = 49,000 ft
  • 123.
  • 124. Time to Climb dt dh C R = / C R dh dt / =  = 2 1 h h dt t  = 2 1 / h h C R dh t
  • 125. Time to Climb: Graphical  = 2 1 / h h C R dh t
  • 126. Time to Climb b mx y + = 0 max 0 max, 0 ) / ( ) / ( H C R C R H H + − = 0 H 0 max, ) / ( C R  = H C R dh t 0 max ) / ( ) ( ) / ( ) / ( 0 0 0 max, max H H H C R C R − =  − = H H H dh C R H t 0 0 0 max, 0 ) / (         − = H H H C R H t 0 0 0 max, 0 ln ) / ( Altitude, H Maximum Rate of Climb, (R/C)max
  • 127.
  • 129. Gliding Flight D L 1 tan =  D L 1 tan 1 − =  max 1 min 1 tan       = − D L 
  • 130. Gliding Flight D L 1 tan 1 − =  D L h h R = =  tan max max ) ( tan D L h h R = = 
  • 131. How do we compute for (L/D)max? At TRmin we found (by differentiating TR with respect to V and equating to zero), 2 / 1 1 2 min ,         =  S W eAR C V o R D T   i D L D C eAR C C , 2 0 , = =  From this formula for V at TRmin, the following relationship (which has already been revealed in the graph) can be derived: 0 , 0 , 0 , 4 / 2 / / D D D D L C eAR C eAR C C C   = = Thus, and this is a maximum because an (L/D)max is simultaneous with a TRmin.
  • 132. Gliding Flight To maximize range, glide at smallest  (at (L/D)max ) A modern sailplane may have a glide ratio as high as 60:1 So  = tan-1(1/60) ~ 1° 
  • 133. Example Calculate the minimum glide angle and the maximum range measured along the ground covered by the CP-1 and the CJ-1 in a power-off glide that starts at an altitude of 10,000 ft. 10,000 ft
  • 134. CP-1: A light, single-engine, propeller-driven, private airplane, approximately modelled after the Cessna Skylane, having the following characteristics: Example Aspect Ratio = 7.37 Parasite drag coefficient CD,o = 0.025 Oswald efficiency factor, e = 0.8
  • 135. Example Calculate the minimum glide angle and the maximum range measured along the ground covered by the CP-1 in a power-off glide that starts at an altitude of 10,000 ft. ( )  = = = − 2 . 4 61 . 13 1 1 tan max 1 min D L  ft 136,000 ) 61 . 13 ( 10000 ) ( max max = = = D L h R 10,000 ft
  • 136. CJ-1: A jet-powered executive aircraft, approximately modelled after the Cessna Citation 3, having the following characteristics: Example Aspect Ratio = 8.93 Parasite drag coefficient CD,o = 0.02 Oswald efficiency factor e = 0.81 ( ) 9 . 16 ) 02 . 0 ( 4 / ) 93 . 8 )( 81 . 0 ( 4 / 0 , max = = =   D C eAR D L
  • 137. Example Calculate the minimum glide angle and the maximum range measured along the ground covered by the CJ-1 in a power-off glide that starts at an altitude of 10,000 ft. ( )  = = = − 39 . 3 9 . 16 1 1 tan max 1 min D L  ft 169,000 ) 9 . 136 ( 10000 ) ( max max = = = D L h R 10,000 ft
  • 138. Example For the CP-1, calculate the equilibrium glide velocities at altitudes of 10,000 ft and 2,000 ft, each corresponding to the minimum glide angle. L SC V W L 2 2 1 cos   = =   S W C V L   =   cos 2 i D L D C eAR C C , 2 0 , = =  CL corresponding to (L/D)max At (L/D)max eAR C C D L  0 , = 634 . 0 ) 37 . 7 )( 8 . 0 ( ) 025 . 0 ( = = L L C C 
  • 139. Example For the CP-1, calculate the equilibrium glide velocities at altitudes of 10,000 ft and 2,000 ft, each corresponding to the minimum glide angle. S W C V L   =   cos 2 2 lb/ft 95 . 16 174 2950 = = S W  = 2 . 4 min  ) 634 . 0 ( 0017556 . 0 ) 95 . 16 )( 2 . 4 cos 2 (  =  V ft 10,000 h at ft/s 3 . 174 = =  V ) 634 . 0 ( 0022409 . 0 ) 95 . 16 )( 2 . 4 cos 2 (  =  V ft 2,000 h at ft/s 3 . 154 = =  V
  • 140.
  • 141. f W W W + = 1 dt dW dt dW f = Weight Equation W –Weight of the airplane at any instant during flight. W0 – Gross weight of the airplane, including everything: full fuel load, payload, crew, structures, etc. Wf – Weight of fuel: this is an instantaneous value, and it changes as fuel is consumed during flight. W1 –Weight of the airplane when the fuel tanks are empty. f W W   =
  • 142. ( )( ) hour BHP fuel of lb SFC = SFC VS TSFC ( )( ) hour thrust of lb fuel of lb TSFC = P dt dW P W c f f − = − =  T dt dW T W c f f t − = − =  pr t V c c   =
  • 143. Range: Piston-Propeller ( )( )  = = V mile (HP) fuel of lb hour HP fuel of lb SFC ( ) ( ) R T SFC) ( V HP SFC mile fuel of lb    To cover longest distance use minimum pounds of fuel per mile. To cover longest distance fly at minimum thrust required.
  • 144. Range: Piston-Propeller dt V ds dt ds V   =  = T c dW dt T dt dW c t f f t − =  − =         − =  T c dW V ds t f f W W   =         − =  T c dW V ds t W W T c dW V ds t         − =  W dW D L c V W L D c dW V ds t t   − =         − =
  • 145. Range: Piston-Propeller W dW D L c V ds t  − =    − = = 1 0 0 W W t R W dW D L c V ds R    − = = 1 0 0 W W t R W dW D L c V ds R Assumptions made: level, unaccelerated flight with constantTSFC and L/D. 1 0 ln W W D L c V R t  = BREGUET RANGE EQUATION 1 0 ln W W D L c R pr  = pr t V c c   =
  • 146. Range: Piston-Propeller 1 0 ln W W D L c R pr  = To maximize range: Fly at largest propeller efficiency Lowest possible SFC Highest ratio of W0 toW1 (fly with the largest fuel weight) Fly at maximum L/D (minimumTR) propulsion aerodynamics structures and materials
  • 147. Example Estimate the maximum range for the CP-1. Normal gross weight = 2950 lb Fuel capacity: 65 gal of aviation gasoline Specific fuel consumption= 0.45 lb/(hp)(h) Parasite drag coefficient CD,o = 0.025 Oswald efficiency factor, e = 0.8 Propeller efficiency = 0.8 1 0 max max ln W W D L c R pr       = 
  • 148. Example Estimate the maximum range for the CP-1. ( ) 61 . 13 4 / 0 , max = = D C eAR D L  1 - 7 ft 10 x 27 . 2 s 3600 h 1 lb/s - ft 550 hp 1 (hp)(h) lb 45 . 0 − = = c lb 367 ) 64 . 5 ( 65 = = f W Since aviation gasoline weighs 5.64 lb/gal, lb 2583 367 2950 1 = − = W mi 1207 ft 10 x 38 . 6 2583 2950 ln ) 62 . 13 ( 10 x 27 . 2 8 . 0 ln 6 7 1 0 max max = =       =       = − W W D L c R pr 
  • 149. Range: Jet Aircraft ( )   V T TSFC A ) ( mile fuel of lb To cover longest distance use minimum pounds of fuel per mile. To cover longest distance fly at maximum L1/2/D. ( )( ) ( )  = = V miles thrust of lb fuel of lb hour thrust of lb fuel of lb TSFC D L D L R C C C SC W S V T 2 1 1 2 2 1  =     
  • 150. Range: Jet Aircraft   − = 1 0 W W t W dW D L c V R L SC W V   =  2   − = 1 0 2 1 2 1 2 W W t D L W dW c C C S R  ) ( 2 2 2 1 1 2 1 0 2 1 W W C C S c R D L t − =   Assumptions made: level, unaccelerated flight with constantTSFC and L1/2/D.
  • 151. Range: Jet Aircraft To maximize range: Fly at minimumTSFC Maximum fuel weight Maximum L1/2/D Fly at high altitudes (low density) ) ( 2 2 2 1 1 2 1 0 2 1 W W C C S c R D L t − =  
  • 152. How is (L1/2/D)max computed? ) ( 2 0 , 2 / 1 2 / 1 L L D L D L C f KC C C C C = + = ( ) ( ) 0 ) 2 ( ) 2 / 1 ( ) ( ' 2 2 0 , 2 / 1 2 / 1 2 0 , = + − + = − L D L L L L D L KC C KC C C KC C C f ( ) 0 ) 2 ( ) 2 / 1 ( 2 / 1 2 / 1 2 0 , = − + − L L L L D KC C C KC C i D L D C KC C , 2 0 , 3 3 = = πeAR K / 1 Where =
  • 153. How is (L1/2/D)max computed? K C C KC C D L L D 3 3 0 , 2 0 , =  = 0 , 0 , 0 , ) 3 / 4 ( ) 3 / 1 ( D D D D C C C C = + = 0 , , , 0 , ) 3 / 1 ( 3 D i D i D D C C C C =  = ( ) 4 / 1 3 0 , 0 , 2 / 1 0 , max 2 / 1 ) ( 1 256 27 ) 3 / 4 ( 3         = =         D D D D L C K C K C C C
  • 154. Summary 4 / 1 3 0 , max 2 / 1 ) ( 1 256 27         =         D D L C K C C ( ) ) 4 /( 1 0 , max D D L KC C C = 4 3 3 1 0 , max 2 3 3 4 1         =         D D L KC C C πeAR K / 1 Where = i D D C C , 0 , 3 = i D D C C , 0 , = i D D C C , 0 , 3 =
  • 155. Example Estimate the maximum range for the CJ-1. ) ( 2 2 2 1 1 2 1 0 max 2 1 max W W C C S c R D L t −         =   Normal gross weight = 19,815 lb Fuel capacity: 1119 gal of kerosene Specific fuel consumption = 0.6 lb of fuel/(lb thrust)(h) Parasite drag coefficient CD,o = 0.02 Oswald efficiency factor e = 0.81
  • 156. Example Estimate the maximum range for the CJ-1. 1 - 4 s 10 x 667 . 1 s 3600 h 1 (lb)(h) lb 6 . 0 − = = t c lb 7463 ) 67 . 6 ( 1119 = = f W Since kerosene weighs 6.67 lb/gal, lb 12352 7463 19815 1 = − = W 4 . 23 ) 02 . 0 ( ) 93 . 8 )( 81 . 0 ( 256 27 ) ( 1 256 27 4 / 1 3 4 / 1 3 0 , max 2 / 1 =         =         =          D D L C K C C
  • 157. Example Estimate the maximum range for the CJ-1. ) ( 2 2 2 1 1 2 1 0 max 2 1 max W W C C S c R D L t −         =   ) 12352 19815 )( 4 . 23 ( ) 318 ( 001184 . 0 2 10 x 667 . 1 2 2 1 2 1 4 max − = − R miles 3630 ft 10 x 2 . 19 6 max = = R
  • 158.
  • 159. Endurance: Piston-Propeller ( )( ) hour HP fuel of lb SFC = To stay in the air for the longest time, fly at minimum pounds of fuel per hour. For maximum endurance, fly at minimum power required. ( ) ) (SFC)(P hour fuel of lb R a
  • 160. Endurance: Piston-Propeller  /  = DV P cP dW dt P dt dW c − =  − = 1     = = = 0 1 0 1 0 W W W W E DV dW c cP dW dt E  L SC W V   =  2   = 0 1 2 3 2 W W L D L W dW SC C C c E   W dW DV L c E W W   = 0 1  ( ) ( ) 2 1 0 2 1 1 2 1 2 3 2 − −  − = W W S C C c E D L   Assumptions made: level, unaccelerated flight with constant SFC, η and L3/2/D.
  • 161. Endurance: Piston-Propeller ( ) ( ) 2 1 0 2 1 1 2 1 2 3 2 − −  − = W W S C C c E D L   To maximize endurance, fly at: Largest propeller efficiency, η Lowest possible SFC Largest fuel weight Fly at maximum CL 3/2/CD Flight at sea level
  • 162. How do we compute for (L3/2/D)max? eAR C C C L D D i  2 0 , 3 = = ( ) 4 3 3 1 0 , 0 , 4 3 0 , max 2 3 3 4 1 4 3         = =         D D D D L C eAR C eAR C C C   eAR C C D L  0 , 3 =
  • 163. i D D C C = 0 , 3 How do we compute for (L3/2/D)max? At PRmin Thus, 4 3 3 1 0 , max 2 3 3 4 1         =         D D L C eAR C C 
  • 165. Locating (L/D)max in the PR curve
  • 166. SUMMARY At minimum thrust required At minimum power required i D D C C , 0 , = 0 , max 4 / D D L C eAR C C  =       i D D C C = 0 , 3 2 1 0 , , 3 1 2 min ,         =   S W eAR C V D PR   2 / 1 1 2 min ,         =  S W eAR C V o R D T   ( ) 4 3 3 1 0 , 0 , 4 3 0 , max 2 3 3 4 1 4 3         = =         D D D D L C eAR C eAR C C C  
  • 167. CP-1: A light, single-engine, propeller-driven, private airplane, approximately modelled after the Cessna Skylane, having the following characteristics: Example Aspect Ratio = 7.37 Parasite drag coefficient CD,o = 0.025 Oswald efficiency factor, e = 0.8
  • 168. Example Estimate the maximum endurance for the CP-1. 81 . 12 3 4 1 4 3 3 1 0 , max 2 3 =         =         D D L C eAR C C  ( ) ( ) 2 1 0 2 1 1 2 1 max 2 3 max 2 − −  −         = W W S C C c E D L           − = − 2 / 1 2 / 1 2 1 7 2950 1 2583 1 ) 174 )( 002377 . 0 ( 2 ) 81 . 12 ( 10 x 7 . 2 8 . 0 E h 4 . 14 s 10 x 19 . 5 4 = = E
  • 169. Endurance: Jet Aircraft ( )( ) hour thrust of lb fuel of lb TSFC = To stay in the air for the longest time, fly at minimum pounds of fuel per hour. For maximum endurance, fly at minimum thrust required. ( ) ) (TSFC)(T ) (TSFC)(T hour fuel of lb R A a a
  • 170. Endurance: Jet Aircraft A t A t T c dW dt T dt dW c − =  − = 1   − = = 1 0 0 W W A t E T c dW dt E  − = 1 0 1 W W t W dW D L c E 1 0 ln 1 W W C C c E D L t = Assumptions made: level, unaccelerated flight with constant TSFC and L/D.
  • 171. Endurance: Jet Aircraft 1 0 ln 1 W W C C c E D L t = To maximize endurance, fly at: MinimumTSFC Maximum fuel weight Maximum L/D
  • 172. Example Estimate the maximum endurance for the CJ-1. h 3 . 13 s 10 x 79 . 4 4 = = E 1 0 max max ln 1 W W C C c E D L t         = 12352 19815 ln ) 9 . 16 ( 10 x 667 . 1 1 4 max − = E
  • 174. Coverage Airplane Performance Static Performance (zero acceleration) Dynamic Performance (finite acceleration) Thrust Required Thrust Available Maximum Velocity Power Required Power Available Maximum Velocity Rate of Climb Takeoff Landing Equations of Motions V-n Diagram Turning Flight Range and Endurance Time to Climb Maximum Altitude Gliding Flight Service Ceiling Absolute Ceiling
  • 175.
  • 176. Ground Roll (Liftoff Distance) Preliminary (purely kinematic) considerations dt dV m ma F = = dt m F dV = t m F dt m F dV V t V = = =   ' ' 0 0 tdt m F Vdt ds = = 2 ' ' ' 2 0 0 t m F dt t m F ds s t s = = =   F m V F Vm m F s 2 2 1 2 2 =       =
  • 177. Ground Roll (Liftoff Distance) Rolling resistance mr = 0.02 relatively smooth paved surface mr = 0.10 grass field ( ) dt dV m L W D T R D T F r = − − − = − − = m Forces in an aircraft during takeoff ground roll
  • 179. Ground Roll F m V s 2 2 = Is the assumption of a constant force reasonable? ( ) L W D T F r − − − = m
  • 180. Ground Roll L SC V L 2 2 1   =  Is the assumption of a constant force reasonable?         + =   eAR C C S V D L D    2 2 0 2 1 ( ) ( )2 2 16 1 16 b h b h + = 
  • 181. Ground Effect ( ) ( )2 2 16 1 16 b h b h + =  Reduction of induced drag by a factor Φ≤1.         + =   eAR C C S V D L D    2 2 0 2 1
  • 183. Ground Roll Is the assumption of a constant force reasonable? T is approximately constant (especially for a jet) The difference between the drag and friction combined and the thrust is also approximately constant ( ) constant? = − − − = L W D T F r m
  • 184. Ground Roll AssumeT is constant. Assume an average value ofT-[D+μR(W-L)]. ( ) ave r eff L W D T F ] [ − − − = m Shevell suggests computing this average atV=0.7VLO. eff LO LO F g W V s 2 ) ( 2 =
  • 186. Ground Roll } )] ( [ { 44 . 1 max , 2 ave R L LO L W D T SC g W s − + − =  m  T SC g W s L LO max , 2 44 . 1  =  Lift-off distance: Is very sensitive to weight; varies asW2 Depends on ambient density May be decreased by: Increasing wing area, S Increasing CL,max Increasing thrust,T
  • 187. Example Estimate the liftoff distance for the CJ-1 at sea level. Assume a paved runway; hence, μr = 0.02. Also, during the ground roll, the angle of attack of the airplane is restricted by the requirement that the tail not drag the ground; therefore, assume that CL,max during ground roll is limited to 1.0. Also, when the airplane is on the ground, the wings are 6 ft above the ground. ( ) ( ) 764 . 0 16 1 16 2 2 = + = b h b h 
  • 188. Example ft/s 230 ) 0 . 1 )( 318 ( 002377 . 0 ) 19815 ( 2 2 . 1 2 2 . 1 2 . 1 max , = = = =  L stall LO SC W V V  ft/s 3 . 160 7 . 0 = LO V lb 9712 ) 0 . 1 )( 318 ( ) 3 . 160 )( 002377 . 0 )( 2 / 1 ( 2 1 2 2 = = =   L SC V L  lb 7 . 520 ) 93 . 8 )( 81 . 0 ( 0 . 1 764 . 0 02 . 0 ) 318 ( ) 3 . 160 )( 002377 . 0 ( 2 1 2 1 2 2 2 2 0 =       + =         + =       eAR C C S V D L D
  • 190. Total Takeoff Distance Total takeoff distance as per FAR 35 ft (jet-powered civilian transport) 50 ft (all other airplanes) ground roll
  • 192. Balanced Field Length A + B Distance up toV1 Additional distance travelled = Distance required to clear an obstacle = Distance required for a full stop
  • 193. Distance to clear obstacle  sin R sa = Where, g V R stall 2 ) ( 96 . 6 = ) 1 ( cos 1 R h − = −  h is the obstacle height. Analysis is based on pull up maneuver
  • 194.
  • 195. Landing Roll   = 0 0 ' ' L s t dt t m F ds 2 2 t m F sL − = F m V sL 2 2 − = Can we assume a constant landing force just as we did in takeoff performance?
  • 196. Landing Roll ( ) dt dV m L W D R D F r = − + − = + − = ] [ ) ( m ( ) dt dV m L W D T R D T F r = − − − = − − = m 0 0
  • 197. Landing Roll ( ) dt dV m L W D F r = − + − = ] [ m Assume a constant effective force, ( ) ave r eff L W D F ] [ − + − = m Compute this average by evaluating the quantity at 0.7VT , where VT is the touchdown velocity.
  • 200. Example Estimate the landing ground roll distance at sea level for the CJ-1. No thrust reversal is used; however, spoilers are employed such that L = 0.The spoilers increase the zero-lift, drag coefficient by 10 percent.The fuel tanks are essentially empty, so neglect the weight of any fuel carried by the airplane.The maximum lift coefficient, with flaps fully employed at touchdown, is 2.5. ft/s 6 . 148 ) 5 . 2 )( 318 ( 002377 . 0 ) 12353 ( 2 3 . 1 2 3 . 1 3 . 1 max , = = = =  L stall T SC W V V  ft/s 104 7 . 0 = T V 022 . 0 ) 02 . 0 ( 1 . 0 02 . 0 0 , = + = D C
  • 201. Example 0 0 =  = L CL lb 9 . 89 ) 022 . 0 )( 318 ( ) 104 )( 002377 . 90 2 1 2 1 2 2 0 = = =   D SC V D  T V R L L W D SC g W s 7 . 0 max , 2 ) ( 69 . 1 m  + − =  ft 842 )] 12352 ( 4 . 0 9 . 89 )[ 5 . 2 )( 318 )( 002377 . 0 ( 2 . 32 ) 12353 ( 69 . 1 2 = + − = L s
  • 203.   Approach Distance  cos W L =  sin W T D + = W T D L W T W D −  − = 1 sin  cos R R hf − = g V R f 2 . 0 2 =  tan 50 f a h s − = from pull up maneuver analysis
  • 205.
  • 206. W L =  cos Load Factor Turn Radius Turn Rate Level Turn   − = =  V n g R V dt d 1 2   2 2 W L Fr − = W L n  1 2 − = n W Fr R V m Fr 2  = 1 2 2 − =  n g V R
  • 207. Constraints on n and V∞ At any given velocity the maximum possible load factor for a sustained level turn is constrained by the maximum thrust available. 2 / 1 0 , 2 max 2 max / 2 1 ) / ( 2 1                 −       =     S W C V W T S W K V n D   eAR K  1 =
  • 208. Constraints on n and V∞ 2 / 1 0 , 2 max 2 max / 2 1 ) / ( 2 1                 −       =     S W C V W T S W K V n D   max max       = W T D L n n is also constrained by CLmax S W C V n L / 2 1 max , 2 max   =  max max 1 cos n = 
  • 209. Constraints on n and V∞ V∞ is constrained by stall. max , 2 L stall C n S W ρ V  = n is also constrained by regulation. Example: category) (utility 4 . 4 = n
  • 210. Minimum Turn Radius Minimum R occurs at the right combination of n and V∞. ) / ( ) / ( 4 ) ( min W T S W K V R   =  2 0 , ) / ( 4 2 min W T KC n D R − = 2 0 , min ) / /( 4 1 ) / ( ) / ( 4 W T KC W T g S W K R D − =   1 2 2 − =  n g V R
  • 211. Maximum Turn Rate Maximum ω occurs at the right combination of n and V∞. 4 / 1 0 , 2 / 1 ) / ( 2 ) ( max               =   D C K S W V   2 / 1 0 , 1 / min         − = D KC W T n                 − =   2 / 1 0 , max 2 / / K C K W T S W q D    − = V n g 1 2 
  • 212. Pull-Up Maneuver ( ) 1 2 − =  n g V R  cos 2 W L R V m − =  ( )  − = V n g 1  W L R V m − =  2
  • 213. Pull-Down Maneuver ( ) 1 2 + =  n g V R ( )  + = V n g 1  W L R V m + =  2
  • 214. For large load factors gn V R 2  =  = V gn  R for level turn, pull-up and pull down ω for level turn, pull-up and pull down
  • 215. For large load factors S W gC R L max , min 2  =  ) / ( 2 max max , max S W n C g L  =   Minimum R for level turn, pull-up and pull down Maximum ω for level turn, pull-up and pull down
  • 216.
  • 218. Topics Discussed Airplane Performance Static Performance (zero acceleration) Dynamic Performance (finite acceleration) Thrust Required Thrust Available Maximum Velocity Power Required Power Available Maximum Velocity Rate of Climb Takeoff Landing Equations of Motions V-n Diagram Turning Flight Range and Endurance Time to Climb Maximum Altitude Gliding Flight Service Ceiling Absolute Ceiling
  • 219. • John D. Anderson. Introduction to Flight • John D. Anderson, Airplane Performance and Design References