Chapter 5 HW Answers

O R C U T T A C A D E M Y H I G H S C H O O L
C O R E C O N N E C T I O N S A L G E B R A 1
Chapter 5
Sequences

5-6 to 5-16
5-6. See below:
a. 108, 324
b. 12, 48
5-7. See graphs below:
a. (1, 2)
b. (−3, 2)
5-8. See below:
a. −6
b. −2
c.
d. undefined
e. x = 2.25
5-9.
5-10. See below:
a. x
b. y7
c.
d. 64x6
5-11. See below:
a. Sample answers: (3, 0) and (3, 1);
x = 3
b. y = −1
c. x = 0
5-12. See below:
a. curved
b. See table and graph below.

5-6 to 5-16
5-13. See below:
a. 52
= 25
b. 351
c. 1
d. 1.6 x 1011
5-14. Jackie squared the binomials incorrectly.
It should be: x2
+ 8x + 16 − 2x − 5 = x2
− 2x + 1,
6x + 11 = −2x + 1, 8x = −10, and x = −1.25.
5-15. See below:
a. m = 5
b.
5-16. See below:
a. y = −2x + 7
b.

5-22 to 5-27
5-22 See below:−1, −2)
a) (3, 1)
5-23. See below:
a) b = t − an
b) y = 3(b + a)
c) y = mx
5-24. See below:
a) 2xy2
b) −m3n3
c) 4 x 10−6
5-25. See below:
a) domain: all numbers, range: y ≤ 1
b) domain: all numbers, range: y ≥ −1
c) domain: all numbers, range: y ≤ 0
d) domain: all numbers, range: y ≥ −1
5-26. There is no association between
number of pets and age.
5-27. See below:
a)
b) 12.5 inches

5-34 to 5-39
5-34. See below:
a. Answers vary but should be close to 0.83.
b. Approximately 228 cm. Since DeShawna
measured to the nearest centimeter,
a prediction rounded to the nearest centimeter
would be reasonable.
c. Approximately 72 cm.
d. Approximately 166 meters.
e. Approximately 138 meters,
approximately 114 meters.
5-35. See below:
a. 10(0.555) = 5.55 feet
b. 10(0.555)(0.555) = 3.08 feet
c. 10(0.555)5
= 0.527 feet
5-36. See graph below:
a. (1, 1)
5-36. See graph below:
a. (1, 1)
b. (−1, 3)

5-34 to 5-39
5-37. See below:
a. 144, 156, 168, 180
b. 264 stamps.
c. t(n) = 12n + 120
d. n = 31.67; She will not be able
to fill her book exactly, because 500
is not a multiple of 12 more than 120.
The book will be filled after 32 months.
5-38. They are not on the same line;
, ,
5-39. See below:
a. y = −3x + 7
b.

5-44 to 5-55
 5-44. See below:
a. m = 3
b. m = 6
c. m = −5
d. m = 1.5
a. −3
b. y = −3x − 5
 5-46. 43 ounces
a. 15 cm
b. 15 ≈ 21.21 cm
 5-48. See graph below:
a. One possible answer is that their growth grows linearly.
b. Answers vary. Sample: The sequence of differences between terms
turns out to be almost the same as the sequence itself.
a. Exponential, because the ratio of one rebound to the next is roughly
constant ≈ 0.6
b. Roughly geometric, because it has a multiplier (though students may
say it is neither because the multiplier is not exact).

5-44 to 5-55
a. 1
b. 5
c. ≈ 3.16
d. undefined
e.
a. 1.03y
b. 0.8z
c. 1.002x
a. 500 liters
b. 31.25 liters
a. (−1, −7)
b. ( , 2)
 5-54. y = −10x + 170
a. 500 liters
b. 31.25 liters
a. (−1, −7)
b. ( , 2)
 5-54. y = −10x + 170
a. 47
b. 1
c.
d.
e. 1.28 × 104
f. 8 × 10-3

5-65 to 5-70
a. Yes, the 90th
term or t(90) = 447
b. No
c. Yes, the 152nd
term or t(152) = 447
d. No
e. No, n = −64 is not in the domain.
 5-66. Justifications vary.
a. m = 3, t(n) = 3n + 1
b. m = 5, t(n) = 5n − 2
c. m = −5, t(n) = −5n + 29
d. m = 2.5, t(n) = 2.5n + 4.5
a. Descriptions vary, but students may say they are multiplying by 1.1
or growing by 10% each year.
b. $88.58
 5-69. m = 13, b = 17
 5-70. 5b + 3h = 339, b = h + 15; 48 bouquets and 33 hearts

5-76 to 5-81
a. −3.5, 1, 5.5, 10
b. Evaluate the equation for n = 15.
 5-77. t(n) = 3n + 2. t(n + 1) = t(n) + 3; t(1) = 5
 5-78.
a. 16x2
− 25
b. 16x2
+40x + 25
 5-80. Let x = number of months; 2x + 105 = −3x + 130; 5 months
a. No solution
b. (7, 2)

5-85 to 5-90
a. exponential, multiply by 12
b. linear, add 5
c. other (quadratic)
d. exponential, multiply by 1.5
 5-86. (2, −4)
a. −3, 6, −12, 24, −48
b. 8, 3, −2, −7, −12
c. 2, , 2, , 2
 5-88. Moderate negative linear association with no outliers. The data appear to be in two clusters,
probably indicating two classes of vehicles.
a. (4x + 1)(4x + 1) = 16x2
+ 8x + 1
b. (4x + 5)(2y − 3) = 8xy – 12x + 10y − 15
a. y = 2x − 3
b. y = −3x − 1
c.
d.

5-105 to 5-110
a. y = 2 · 4x
b. y = 5 · (1.2)x
a. 1.03
b. 0.75
c. 0.87
d. 1.0208
 5-103. Technically, Mathias can never leave, either because he will never
reach the door or because he cannot avoid breaking the rules. The
equation for this situation is y = 100(0.5)x
, where x is the number of
minutes that have passed and y is the distance (in meters) from the door.
a. 8m5
b. 2y3
c.
d. −8x6
a. #1 is arithmetic, #2 is neither, #3 is geometric
b. #1 the generator is to add −3, #3 the generator is to multiply by 1/2

5-105 to 5-110
a. −3, −1, 1, 3, 5
b. 3, −6, 12, −24, 48
a.
b. no solution
c. x = −4 or 5
d. x = 2
a. 12, 7, 2, −3, −8; t(n) = 17 − 5n
b.
 5-109. B
a. y = x + 2
b. 28 grams

5-117 to 5-123
 5-117. No; the 5th
term is 160, and the 6th
term is 320. Justifications vary.
 5-118. Yes, x ≈ 5.322.
a. Sequence 1: 10, 14, 18, 22, add 4, t(n) = 4n − 2; Sequence 2: 0,
−12,−24 ,−36, subtract 12, t(n) = −12n + 36; Sequence 3: 9, 13, 17,
21, add 4, t(n) = 4n − 3
b. Yes, Sequence 1: 18, 54, 162, 486, multiply by 3, ; Sequence 2: 6, 3,
1.5, 0.75, multiply by ½ ; Sequence 3: 25, 125, 625, 125,
multiply by 5,
c. Answers vary, but the point is to have students create their own
equation and write terms that correspond to it.

5-117 to 5-123
a. −4
b. 6
c. 8
d. 1040
e. x = −3, 0, 2
f. x3
− 5x − 3
a. y = 23500(0.85)x
, worth $2052.82
b. y = 14365112(1.12)x
, population 138,570,081
 5-122. t(n) = −188n + 2560; 1620
a. all numbers
b. 1, 2, 3, ...
c. x ≠ 0
d. 1, 2, 3, 4, ...

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