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2. This problem requires that you write some very simple code. Keep your code as short as
possible. a. Write the definition for a class M containing one abstract method g(). Then write the
definition of a non-abstract class N with parent class M. Only include what is strictly necessary
for the two classes to compile (no constructor or other methods). b. Repeat part a. but make M an
interface instead of a class.
Solution
Answer:
(a)
Public class M
{
abstract public void g();
}
(b)
Public class M
{
abstract public void g();
}
public class N extends M
{
public void g()
{
System.out.println("My method g implemented");
}
public static void main (String [] args)
{
N obj=new N();
obj.g();
}
}
(c)
public interface M
{
public void M();
}
public class N implements M
{
public void g()
{
System.out.println("Inside method in implemented interface");
}
public static void main (String [] args)
{
N obj=new N();
obj.g();
}
}

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2- This problem requires that you write some very simple code- Keep yo.docx

  • 1. 2. This problem requires that you write some very simple code. Keep your code as short as possible. a. Write the definition for a class M containing one abstract method g(). Then write the definition of a non-abstract class N with parent class M. Only include what is strictly necessary for the two classes to compile (no constructor or other methods). b. Repeat part a. but make M an interface instead of a class. Solution Answer: (a) Public class M { abstract public void g(); } (b) Public class M { abstract public void g(); } public class N extends M { public void g() { System.out.println("My method g implemented"); } public static void main (String [] args) { N obj=new N(); obj.g();
  • 2. } } (c) public interface M { public void M(); } public class N implements M { public void g() { System.out.println("Inside method in implemented interface"); } public static void main (String [] args) { N obj=new N(); obj.g(); } }