1. A projectile is launched at an initial angle of 50o with a speed of vo = 15 m/s from the top of a hill 5 meters above level ground. g) Find the range of the projectile from launch to impact. h) Find the x and y components of the velocity of the projectile as it strikes the ground. i) What is the magnitude of the velocity of the projectile when it strikes the ground? j) Make a sketch of the trajectory labeling the times and positions of the projectile at launch, peak, and impact point. Solution x-component of initial velocity, v xi = 15cos50 = 9.6418 m/s y-component of initial velocity, v y i = 15sin50 = 11.4906 m/s The final component of x will not change. so, v xf = 9.6418 m/s Final component in y-direction v 2 yf = v 2 yi + 2ad v 2 yf = 11.4906 2 - 2(9.8)(-5) v yf = 15.1668 m/s Magnitude of final velocity v = sqrt ( 9.6418 2 + 15.1668 2 ) v = 17.972 m/s Total time in the air t = -15.1668 - 11.4906 / -9.8 t = 2.72 sec Range , x = v xi t = 26.22 m .