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SOLID
FIGURESVolume Computation
Solid Figures
• Solid Figures are geometric figures with
length, height, and width.
• Also called as Three Dimension Figures.
Kinds of Solid Figures
• Prisms
• Pyramids and Cones
• Sphere
Prisms
• Prisms are solid figures with parallel
edges and uniform cross-sections.
• Right prisms are prisms with edges
perpendicular to the base.
Prisms
Examples of Prisms
• Cube
• Rectangular prism
• Triangular Prism
Prisms
• Right prisms with circular bases are referred to as
cylinders.
Pyramids and Cones
Pyramid
• A pyramid is a solid figure having a polygonal
base and triangular sides which meet in a point
called apex or vertex.
Pyramids and Cones
Cone
• A cone is a solid figure with a circle as a base.
Its lateral side is generated by a line through a
fixed point called vertex and a fixed curve plane
called the base.
Sphere
• A sphere is a solid figure with a set of points which
are equidistant from the center.
Volume Computation: Prisms
Prisms
• V=Bh , where ‘B’ as the area of the base.
Example 1:
Find the volume of a rectangular prism whose base is 12 ft by 4 ft
and 15 ft high.
Solution:
Area of the Base= lxw
=12 ft x 4 ft
= 48 ft2
Volume=Bxh
=48 ft2 x 15 ft
V=720 ft3
Volume Computation: Prisms
Example 2:
Find the volume of a cylinder with 6 inches in diameter and 12.5
inches long.
Solution:
B=r2
= 3.1416 x 32
=28.2744 sq.in.
V=Bxh
=28.2744 sq.in. x 12.5 in.
V=353.43 cu.in.
Volume Computation: Pyramids and Cones
Pyramids and Cones
• V=1/3Bh
Example 1:
Find the volume of a pyramid 18 1/2 inches high, the base of
which is rectangle 8 inches by 15 inches.
Solution:
B=lxw
=(15 in.)(8in.)
=120 sq.in.
V=1/3 Bh
=1/3(120 sq.in.)(18.5 in)
V=740 cu.in.
Volume Computation : Pyramids and Cones
Example 2:
Find the volume of the cone 12 in. high whose base is 6
in. diameter.
Solution:
B=3.1416 x (32)
=28.2744 sq. in.
V=1/3 B x h
=1/3 (28.2744sq.in.)(8 in.)
V=113.0976 cu.in.
Volume Computation: Sphere
Sphere
• V=4/3 πr3
Example:
Find the volume of an 8 cm. sphere.
Solution:
d=8cm
r=4cm.
V=4/3(3.1416)(43 )
V=268.0832 cu.in.
Assignment:
1. Define frustums
2. Draw example of frustums
Reference: Basic Mathematics( Second Edition)
Prepared by:
ARNEL B. MANCO

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Solid figures

  • 2. Solid Figures • Solid Figures are geometric figures with length, height, and width. • Also called as Three Dimension Figures.
  • 3. Kinds of Solid Figures • Prisms • Pyramids and Cones • Sphere
  • 4. Prisms • Prisms are solid figures with parallel edges and uniform cross-sections. • Right prisms are prisms with edges perpendicular to the base.
  • 5. Prisms Examples of Prisms • Cube • Rectangular prism • Triangular Prism
  • 6. Prisms • Right prisms with circular bases are referred to as cylinders.
  • 7. Pyramids and Cones Pyramid • A pyramid is a solid figure having a polygonal base and triangular sides which meet in a point called apex or vertex.
  • 8. Pyramids and Cones Cone • A cone is a solid figure with a circle as a base. Its lateral side is generated by a line through a fixed point called vertex and a fixed curve plane called the base.
  • 9. Sphere • A sphere is a solid figure with a set of points which are equidistant from the center.
  • 10. Volume Computation: Prisms Prisms • V=Bh , where ‘B’ as the area of the base. Example 1: Find the volume of a rectangular prism whose base is 12 ft by 4 ft and 15 ft high. Solution: Area of the Base= lxw =12 ft x 4 ft = 48 ft2 Volume=Bxh =48 ft2 x 15 ft V=720 ft3
  • 11. Volume Computation: Prisms Example 2: Find the volume of a cylinder with 6 inches in diameter and 12.5 inches long. Solution: B=r2 = 3.1416 x 32 =28.2744 sq.in. V=Bxh =28.2744 sq.in. x 12.5 in. V=353.43 cu.in.
  • 12. Volume Computation: Pyramids and Cones Pyramids and Cones • V=1/3Bh Example 1: Find the volume of a pyramid 18 1/2 inches high, the base of which is rectangle 8 inches by 15 inches. Solution: B=lxw =(15 in.)(8in.) =120 sq.in. V=1/3 Bh =1/3(120 sq.in.)(18.5 in) V=740 cu.in.
  • 13. Volume Computation : Pyramids and Cones Example 2: Find the volume of the cone 12 in. high whose base is 6 in. diameter. Solution: B=3.1416 x (32) =28.2744 sq. in. V=1/3 B x h =1/3 (28.2744sq.in.)(8 in.) V=113.0976 cu.in.
  • 14. Volume Computation: Sphere Sphere • V=4/3 πr3 Example: Find the volume of an 8 cm. sphere. Solution: d=8cm r=4cm. V=4/3(3.1416)(43 ) V=268.0832 cu.in.
  • 15. Assignment: 1. Define frustums 2. Draw example of frustums Reference: Basic Mathematics( Second Edition)