A discus thrower accelerates a discus from rest to a speed of 24.8 m/s by whirling it through 1.20 rev. Assume the discus moves on the arc of a circle 1.02 m in radius (a) Calculate the final angular speed of the discus. rad/s (b) Determine the magnitude of the angular acceleration of the discus, assuming it to be constant rad/s? (c) Calculate the time interval required for the discus to accelerate from rest to 24.8 m/s Need Help? ReaditathTath te a Tutor Talk to a Tutor Solution a) omega = v/r = 24.8m/s / 1.02m = 24.31 rad/s b) f omega^2 = i omega^2 + 2(alpha)(theta) alpha = (f omega^2 - i omega^2)/ 2(theta) = (24.31m/s)^2 - 0 / (2)(1.20rev)(2pi rad/rev) = 39.20 rad/s^2 c) t = omega/alpha = 24.31rad/s / 39.2 rad/s^2 = 0.62 s .