A diffraction grating having 570 lines/mm diffracts visible light at 35.0 o ? Part A What is the light\'s wavelength? Express your answer with the appropriate units. ?= 1 Value Units | Submit|Reques Solution Use the following diffration equation d*sin(theta) = m*wavelength where d = spacing = 1/570 lines/mm means 570000 lines per m so d = 1.75438e-6 meter so, wavelength = 1.75438e-6*sin 35 / m wavelength = 1006.27 / m Now visible wavelength range is 400 nm to 700 nm so,, we can put different values of m so that we can get the required wavelength within this range for m = 2. wavelength = 503.135 nm so, answer is 503.135 nm .