A cube of ice is taken from the freezer at -9.3°C and placed in a 105 g aluminum calorimeter filled with 315 g of water at room temperature of 20°C. The final situation is observed to be all water at 17°C. What was the mass of the ice cube? Solution here, mass of alumunium , m1 = 105 g = 0.105 kg mass of water , m2 = 315 g = 0.315 kg let the mass of ice cube be m3 using conservation of heat energy m3 * ( Ci * ( 0 - (- 9.3)) + Lf * Cw * ( 17 - 0)) = m1 * Ca * ( 20 - 17) + m2 * Cw * ( 20 - 17) m3 * ( 2150 * ( 0 - (- 9.3)) + 333400 + 4186 * ( 17 - 0)) = 0.105 * 900 * ( 20 - 17) + 0.315 * 4186 * ( 20 - 17) solving for m3 m3 = 0.00998 kg = 9.98 * 10^-3 kg the mass of ice is 9.98 * 10^-3 kg .