1. The “A” Team
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2. Vroom Vroom
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3. The Description of the Game
Roll two six-sided dice to find a sum. The sum
will be between 2-12. Each sum has a prize
that will be awarded, a car. Each car has a
price value. To play the game, you must pay
$50.
Click on each box to see the prize for each sum.
2 3 4 5 6 7
8 9 10 11 12
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4. A sum of 7…
You will receive nothing.
This has a value of $0.
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Description

5. A sum of 6…
You will receive an Aston
Martin DBS (in red).
JUST
This has a value of $5. KIDDING!
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Description

6. A sum of 8…
You will receive a Power
wheels Barbie Jammin’
Jeep.
*not to scale.
This has a value of $5.
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Description

7. A sum of 5…
You will receive Fred
Flintstone’s car.
This has a value of $25.
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Description

8. A sum of 9…
You will receive
Cinderella’s carriage.
This has a value of $25.
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Description

9. A sum of 4…
You will receive The
Mystery Machine.
This has a value of $75.
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Description

10. Sum of 10
You will receive the
Weasley’s Ford Anglia
flying car.
*It does fly.
This has a value of $75.
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Description

11. A sum of 3…
You will receive Lightning
McQueen.
This has a value $130.
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Description

12. A sum of 11…
You will receive Luke
Skywalker’s X-34
Landspeeder.
This has a value of $130.
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Description

13. A sum of 2…
You will receive Doc
Brown’s 1981 DeLorean
DMC-12.
*Includes flux capacitor.
This has a value of $200.
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Description

14. A sum of 12…
You will receive the Wayne
Industries 2009 Tumbler
(in black).
AKA THE
BATMOBILE!!!!
*Batman not included.
This has a value of $200.
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Description

15. Expected Value and Standard Deviation
x 0 5 25 75 130 200
P(x) 6/36 10/36 8/36 6/36 4/36 2/36
µ= 0(6/360)+5(10/36)+25(8/36)+75(6/36)+130(4/36)+200(2/36)=45
σ²= 6/36(0-45)²+10/36(5-45)²+8/36(25-45)²+6/36(75-45)²+4/36(130-45)²+2/36(200-
45)²=3158.333
σ=56.199
The expected value of this games is $45. The expected standard deviation is
$56.20.
Using the randInt function on the calculator, we were able to perform 50 trials.
We performed a simulation with a range of 1-6 and 50 trials for the first die
and put it into List 1. Then we performed a second simulation with a range of
1-6 and 50 trials and put the numbers into List 2. Finally, we added the two
lists together find the sums of the 50 trials into List 3.
Through the simulation, the average found was $47 and the standard deviation
was $59.67.
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16. Results
Sum Amount This table shows the outcomes of our simulation.
(Value in $)
2 ($200) 1 The expected value, 45, and the mean found through
the simulation, 47, were relatively close to each other.
3($130) 3 Also, the theoretical standard deviation, 56.199, and
4($75) 1 the standard deviation found in simulation, 59.67,
5($25) 7 were relatively close to each other.
6($5) 10
There were no surprises found throughout the
7($0) 9 simulation and the casino makes an expected profit of
8($5) 0 $5 for each game that a person plays.
9($25) 9
The only improvements that the casino could make, in
10($75) 5
our perspective, is for them to charge more money to
11($130) 2 play the game. Therefore, the profit would be greater.
12($200) 3