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Parallel & Perpendicular Lines
The student is able to (I can):
• Use slopes to identify parallel and perpendicular lines.
• Write equations of line parallel or perpendicular to a given
line through a given point.
Parallel LinesParallel LinesParallel LinesParallel Lines TheoremTheoremTheoremTheorem – in a coordinate plane, two
nonvertical lines are parallel if and only if they have
the same slope.
Any two vertical lines are parallel
x
y
ms = mt ⇒ s t
s t
1 3 4
2
2 0 2
sm
− − −
= = =
− − −
3 1 4
2
1 1 2
tm
− − −
= = =
− − −
Perpendicular LinesPerpendicular LinesPerpendicular LinesPerpendicular Lines TheoremTheoremTheoremTheorem – in a coordinate plane, two
nonvertical lines are perpendicular if and only if the
product of their slopes is –1 (negative reciprocals).
Vertical and horizontal lines are perpendicular.
x
y
p
q
3 1 4
2
1 1 2
tm
− − −
= = =
− − −
0 1 1 1
3 0 3 3
qm
− −
= = =
− − −
1p qm m = − ⇒ ⊥i p q
Practice
Given A(–3, –1), B(3, 3), C(–4, 4), and D(0, –2), is AB parallel
or perpendicular to CD?
Practice
Given A(–3, –1), B(3, 3), C(–4, 4), and D(0, –2), is AB parallel
or perpendicular to CD?
The two slopes are not equal, so the lines are not parallel.
The product of the slopes is –1, so the lines are
perpendicularperpendicularperpendicularperpendicular.
3 ( 1) 4 2
:
3 ( 3) 6 3
AB m
− −
= = =
− −
2 4 6 3
:
0 ( 4) 4 2
CD m
− − −
= = = −
− −
Pairs of Lines
Two lines will do one of three things:
• Not intersect (parallel)
– inconsistent
• Intersect at one point
– consistent and independent
• Intersect at all points (coincide)
– consistent and dependent
• To determine which of these possibilities is true, look at
the slope and y-intercept:
• To compare slopes and y-intercepts, put both equations in
slope-intercept form (y=mx+b). If we do that to the last
equation, we can see why the two coincide:
y – 5 = 3(x – 1)
y = 3x – 3 + 5
y = 3x + 2
Parallel LinesParallel LinesParallel LinesParallel Lines Intersecting LinesIntersecting LinesIntersecting LinesIntersecting Lines Coinciding LinesCoinciding LinesCoinciding LinesCoinciding Lines
y = 2x – 9
y = 2x + 7
y = 3x + 5
y = –4x – 1
y = 3x + 2
y – 5 = 3(x – 1)
same slope,
different
intercept
different slopes
same slope, same
intercept
To write the equation of a line that is
parallel (or perpendicular) to a given line
through a given point:
• Determine the slope of the given line
• Determine the slope of the new line
– Parallel lines have the same slope
– Perpendicular lines have slopes that
are the negative reciprocal
• Write the new equation in point-slope
form
• Solve for y if necessary
Example: Write the equation of the line
that is parallel to x − 3y = 15 through the
point (−3, 2).
Example: Write the equation of the line
that is parallel to x − 3y = 15 through the
point (−3, 2) in slope-intercept form.
So, our slope is .
3 15
3 15
1
5
3
x y
y x
y x
− =
− = − +
= −
1
3
( )
1
2 3
3
1
1 2
3
1
3
3
− = +
= + +
= +
y x
y x
y x
Example: Write an equation of the line that
is perpendicular to that goes
through the point (8, −3), in point-slope
form.
4 3y x= −
Example: Write an equation of the line that
is perpendicular to that goes
through the point (8, −3), in point-slope
form.
orig. slope = ⊥ slope =
4 3y x= −
1
4
−
4
1
( )
1
3 8
4
+ = − −y x

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1.4.4 Parallel and Perpendicular Line Equations

  • 1. Parallel & Perpendicular Lines The student is able to (I can): • Use slopes to identify parallel and perpendicular lines. • Write equations of line parallel or perpendicular to a given line through a given point.
  • 2. Parallel LinesParallel LinesParallel LinesParallel Lines TheoremTheoremTheoremTheorem – in a coordinate plane, two nonvertical lines are parallel if and only if they have the same slope. Any two vertical lines are parallel x y ms = mt ⇒ s t s t 1 3 4 2 2 0 2 sm − − − = = = − − − 3 1 4 2 1 1 2 tm − − − = = = − − −
  • 3. Perpendicular LinesPerpendicular LinesPerpendicular LinesPerpendicular Lines TheoremTheoremTheoremTheorem – in a coordinate plane, two nonvertical lines are perpendicular if and only if the product of their slopes is –1 (negative reciprocals). Vertical and horizontal lines are perpendicular. x y p q 3 1 4 2 1 1 2 tm − − − = = = − − − 0 1 1 1 3 0 3 3 qm − − = = = − − − 1p qm m = − ⇒ ⊥i p q
  • 4. Practice Given A(–3, –1), B(3, 3), C(–4, 4), and D(0, –2), is AB parallel or perpendicular to CD?
  • 5. Practice Given A(–3, –1), B(3, 3), C(–4, 4), and D(0, –2), is AB parallel or perpendicular to CD? The two slopes are not equal, so the lines are not parallel. The product of the slopes is –1, so the lines are perpendicularperpendicularperpendicularperpendicular. 3 ( 1) 4 2 : 3 ( 3) 6 3 AB m − − = = = − − 2 4 6 3 : 0 ( 4) 4 2 CD m − − − = = = − − −
  • 6. Pairs of Lines Two lines will do one of three things: • Not intersect (parallel) – inconsistent • Intersect at one point – consistent and independent • Intersect at all points (coincide) – consistent and dependent
  • 7. • To determine which of these possibilities is true, look at the slope and y-intercept: • To compare slopes and y-intercepts, put both equations in slope-intercept form (y=mx+b). If we do that to the last equation, we can see why the two coincide: y – 5 = 3(x – 1) y = 3x – 3 + 5 y = 3x + 2 Parallel LinesParallel LinesParallel LinesParallel Lines Intersecting LinesIntersecting LinesIntersecting LinesIntersecting Lines Coinciding LinesCoinciding LinesCoinciding LinesCoinciding Lines y = 2x – 9 y = 2x + 7 y = 3x + 5 y = –4x – 1 y = 3x + 2 y – 5 = 3(x – 1) same slope, different intercept different slopes same slope, same intercept
  • 8. To write the equation of a line that is parallel (or perpendicular) to a given line through a given point: • Determine the slope of the given line • Determine the slope of the new line – Parallel lines have the same slope – Perpendicular lines have slopes that are the negative reciprocal • Write the new equation in point-slope form • Solve for y if necessary
  • 9. Example: Write the equation of the line that is parallel to x − 3y = 15 through the point (−3, 2).
  • 10. Example: Write the equation of the line that is parallel to x − 3y = 15 through the point (−3, 2) in slope-intercept form. So, our slope is . 3 15 3 15 1 5 3 x y y x y x − = − = − + = − 1 3 ( ) 1 2 3 3 1 1 2 3 1 3 3 − = + = + + = + y x y x y x
  • 11. Example: Write an equation of the line that is perpendicular to that goes through the point (8, −3), in point-slope form. 4 3y x= −
  • 12. Example: Write an equation of the line that is perpendicular to that goes through the point (8, −3), in point-slope form. orig. slope = ⊥ slope = 4 3y x= − 1 4 − 4 1 ( ) 1 3 8 4 + = − −y x