For the polynomial below, 2 is a zero. f[x) = x - 8x + 16x - 8 Express f(x) as a product of linear factors. Solve for x , where x is a real number. 3x+10 - x+3=1 Solution x*x (x-2) - 6x(x-2) +4(x-2) === [x*x - 6x + 4] (x-2) take one sqrt on other side and then square both side : 3x + 10 = 1 + x + 3 + 2sqrt[x+3] ...........=== 2x + 6 = 2 sqrt[x+3] ............x=-3 , -2..put this in main eq : both are roots of mai9n eq.

1. For the polynomial below, 2 is a zero. f[x) = x - 8x + 16x - 8 Express f(x) as a product of linear
factors. Solve for x , where x is a real number. 3x+10 - x+3=1
Solution
x*x (x-2) - 6x(x-2) +4(x-2) === [x*x - 6x + 4] (x-2)
take one sqrt on other side and then square both side : 3x + 10 = 1 + x + 3 + 2sqrt[x+3]
...........=== 2x + 6 = 2 sqrt[x+3] ............x=-3 , -2..put this in main eq : both are roots of mai9n
eq