The answer should be between 0 and 1 What is the approximate probability of exactly three people in a group of ten are born in the same month? Solution \\(10C_{3} * 1 * (1/12) * (1/12) * (11/12)\\) = 55/72 10C3 is the way of selecting any three persons 1 is probability that first guy could be from any mnth 1/12 is the probability for the next guy to born in the same mnth.