Find the Z-scores for which 88 of the distributions area lies betwe.pdf

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Find the Z-scores for which 88% of the distributions area lies between -z and z. The z-scores are? (Use a comma to seperate answers as needed. Round to two decimal places as needed) Solution The area under the entire normal curve is 1. If you want the z scores so that .88 is the area between those points under the curve then this means that 1-.88=.12 is the distribution\'s area not between -z and z. Since half of this area is between -%u221E and -z and half of this area is between z and %u221E you need to divide the area by 2. Now you want to find the z score so that .12/2 = .06 is the area to the right of z. Look at a table of the standard normal distribution. Somewhere in the center section of the table you will find a number very close to .06. My table shows this when z=1.55. Since this is the same area to the left under the curve of z=-1.55 then 88% of the distribution\'s area lies between z=-1.55 and z=1.55.

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