Physics chpt18
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![Unit 6: Light and Optics ,[object Object],[object Object],[object Object],Chapter 18 Wave Properties of Light](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)
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Physics chpt18
- 1. Unit 6, Chapter 18 CPO Science Foundations of Physics
- 9. 18.1 Speed of Light c = f Wavelength (m) Frequency (Hz) Speed of light 3 x 10 8 m/sec
- 22. 18.2 Grating Formula = d sin dw L distance between grating lines (m) distance between screen and glasses wavelength of light (nm) d= 13,500 lines/inch = ? lines/m distance between 2 first order bright spots
Notas do Editor
- 1) You are asked for the wavelength. 2) You are given the frequency. 3) The speed of light is c = fλ. 4) λ = c ÷ f = (3 x 10 8 m/sec) ÷ (600 x 10 12 Hz) = 5 x 10 -7 m
- Most of the light that you see is unpolarized . That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
- An easy way to think about polarization is to think about shaking a spring back and forth. If the spring is shaken up and down it makes vertical polarization. If the spring is shaken back and forth it makes horizontal polarization. Waves move along the spring in its long direction. The oscillation of the wave (and its polarization) is transverse or perpendicular to the direction the wave travels.
- Most of the light that you see is unpolarized . That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
- Most of the light that you see is unpolarized . That does not mean the light has no polarization. Unpolarized light is actually an equal mixture of all polarizations. We call ordinary light unpolarized because no single polarization dominates the mixture.
- 1) You are asked for energy in joules and gallons of gas 2) You are given the mass, a percent converted to energy, and J/gallon for gasoline. 3) Einstein’s formula: E = mc2 4) The amount of mass converted to energy is: m = 0.007 x 100 kg = 0.7 kg Energy released is: E = (0.7 kg)(3 x 108 m/sec) 2 = 6.3 x 10 16 J To calculate the equivalent in gasoline divide by the energy per gallon: N = 6.3 x 1016 J ÷ 1.3 x 108 J/g = 4.8 x 108 gallons This is 480 million gallons ofgasoline.