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ELE 101 / 102 Dept of E & E Engg, MIT Manipal 1
Mesh Current Method:
Mark different currents in all the independent meshes
of the given network
Current directions are arbitrary
Write KVL equations for these independent meshes
Solve for the currents
Note: Independent Meshes: Meshes having at least one new
element which is not included in the previous meshes selected.
ELE 101 / 102 Dept of E & E Engg, MIT Manipal 2
Mesh Current Method:
For the circuit shown, determine the mesh currents i1 ,i2 and current
through the galvanometer
i2
+ -
G
4 0
2 0
3 0
3 0
1 0
RG=100
1 0 V
A
B
i 1
i 3
M1: 40 (i1) + 100 (i1 - i2) + 20 (i1 – i3) = 0
M2: 30 (i2) + 30 (i2 – i3) + 100 (i2 – i1) = 0
M3: 10 (i3) + 20 (i3 – i1) + 30 (i3 – i2) = 10
Ans: i1 = 0.10197A, i2 = 0.11184A. iG = 9.88 mA
ELE 101 / 102 Dept of E & E Engg, MIT Manipal 3
For the circuit shown, determine the current through the 3 ohm resistor
7 V
7 A
1 Ω
1 Ω
2 Ω
2 Ω
3 Ω
i 1
i 2
i 3
1(i1-i2) + 3(i3-i2) + 1 (i3) = 7
1(i2-i1) + 2 (i2) + 3 (i2-i3) = 0
(i1 – i3 )= 7
Ans: Current through 3 ohm resistor = i2 – i3 = 0.5 A (right to left)
ELE 101 / 102 Dept of E & E Engg, MIT Manipal 4
Mesh Equations - dependent sources
For the circuit shown determine the mesh currents
i1
i2
i3
8 V 3 Ω
2 V a
1 Ω
1 6 i b2 4 V
4 Ω
2 Ω
V a
5 Ω
i b
33 3iV&ii
circuit,theFrom
ab ==










3
2
1
i
i
i










−−
−−
−
214
1182
1226










−8
0
24
=
Ans: i1 = 2.082 A i2 = 2.386 A i3 = 1.357 A

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L9 dc circuits

  • 1. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 1 Mesh Current Method: Mark different currents in all the independent meshes of the given network Current directions are arbitrary Write KVL equations for these independent meshes Solve for the currents Note: Independent Meshes: Meshes having at least one new element which is not included in the previous meshes selected.
  • 2. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 2 Mesh Current Method: For the circuit shown, determine the mesh currents i1 ,i2 and current through the galvanometer i2 + - G 4 0 2 0 3 0 3 0 1 0 RG=100 1 0 V A B i 1 i 3 M1: 40 (i1) + 100 (i1 - i2) + 20 (i1 – i3) = 0 M2: 30 (i2) + 30 (i2 – i3) + 100 (i2 – i1) = 0 M3: 10 (i3) + 20 (i3 – i1) + 30 (i3 – i2) = 10 Ans: i1 = 0.10197A, i2 = 0.11184A. iG = 9.88 mA
  • 3. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 3 For the circuit shown, determine the current through the 3 ohm resistor 7 V 7 A 1 Ω 1 Ω 2 Ω 2 Ω 3 Ω i 1 i 2 i 3 1(i1-i2) + 3(i3-i2) + 1 (i3) = 7 1(i2-i1) + 2 (i2) + 3 (i2-i3) = 0 (i1 – i3 )= 7 Ans: Current through 3 ohm resistor = i2 – i3 = 0.5 A (right to left)
  • 4. ELE 101 / 102 Dept of E & E Engg, MIT Manipal 4 Mesh Equations - dependent sources For the circuit shown determine the mesh currents i1 i2 i3 8 V 3 Ω 2 V a 1 Ω 1 6 i b2 4 V 4 Ω 2 Ω V a 5 Ω i b 33 3iV&ii circuit,theFrom ab ==           3 2 1 i i i           −− −− − 214 1182 1226           −8 0 24 = Ans: i1 = 2.082 A i2 = 2.386 A i3 = 1.357 A