uranium 234 alpha emission Solution Ans. During alpha ( 4 a 2 ) decay/emission- I. Atomic number is decreased by 2 units. II. Atomic mass (= n + p) is decreased by 4 unit. Balanced Equation:   1 234 U 92 ---- a-decay ----> 1 230 Th 90 + 1 4 a 2 # The coefficient value of 1 is generally NOT shown in the balanced equation. If there is no coefficient written before a chemical species, it’s understood to be 1. SO, the balanced equation can also be written as- 234 U 92 ---- a-decay ----> 230 Th 90 + 4 a 2 # The element with atomic number 90 is thorium. .

1. uranium 234 alpha emission
Solution
Ans. During alpha ( 4
a 2 ) decay/emission-
I. Atomic number is decreased by 2 units.
II. Atomic mass (= n + p) is decreased by 4 unit.
Balanced Equation:Â Â 1 234
U 92 ---- a-decay ----> 1 230 Th 90 + 1 4
a 2
# The coefficient value of 1 is generally NOT shown in the balanced equation. If there is no
coefficient written before a chemical species, it’s understood to be 1. SO, the balanced
equation can also be written as-
234
U 92 ---- a-decay ----> 230 Th 90 + 4
a 2
# The element with atomic number 90 is thorium.