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An Illustrated Guide to the
ANALYTIC HIERARCHY PROCESS

Dr. Rainer Haas
Dr. Oliver Meixner
Institute of Marketing & Innovation
University of Natural Resources and Applied Life Sciences, Vienna

http://www.boku.ac.at/mi/
1

Do your decision conferences turn out like this?
TOO BAD!
WE WANT
PROGRAM B !!

WE WANT
PROGRAM A !!

COME ON IN
THE WATER IS
FINE!

sea of indecision

or does this happen?
2

Page 1
1
DO YOUR RECOMMENDATIONS
TURN OUT LIKE THIS?

BUT BOSS...
THAT WAS MY
BEST GUESS!

GUESS AGAIN

MAYBE YOU NEED A
NEW APPROACH
3

... another way of decision making

I THINK I ‘LL TRY THE
ANALYTIC HIERARCHY
PROCESS (AHP) !!!

4

Page 2
2
OKAY TELL US
ABOUT AHP
DR THOMAS L.
SAATY DEVELOPED
THE PROCESS IN
THE EARLY 1970’S
AND...

5

THE PROCESS HAS BEEN USED TO
ASSIST NUMEROUS CORPORATE AND
GOVERNMENT DECISION MAKERS.
Some examples of decision problems:
choosing a telecommunication system
formulating a drug policy
choosing a product marketing strategy
...

6

Page 3
3
Let’s show
how it works

PROBLEMS ARE
DECOMPOSED INTO A
HIERARCHY OF CRITERIA AND
ALTERNATIVES

Problem

Criterion 1

Criterion 1.1

...

Criterion 2

Criterion n

...

...

Alternative 1

Alternative 2

...

Alternative n
7

OKAY, HERE’S A DECISION
PROBLEM WE FACE IN OUR
PERSONAL LIVES

8

Page 4
4
I SEE A NEW CAR
IN YOUR FUTURE

9

AN IMPORTANT PART OF THE
PROCESS IS TO ACCOMPLISH THESE
THREE STEPS

• STATE THE OBJECTIVE:
– SELECT A NEW CAR

• DEFINE THE CRITERIA:
– STYLE, RELIABILITY, FUEL ECONOMY

• PICK THE ALTERNATIVES:
– CIVIC COUPE, SATURN COUPE, FORD ESCORT,
RENAULT CLIO

WHAT ABOUT COST?
(BE QUIET, WE’LL TALK ABOUT THAT LATER)

10

SKEPTIC-GATOR

Page 5
5
THIS INFORMATION IS THEN ARRANGED
IN A HIERARCHICAL TREE
OBJECTIVE
CRITERIA
Select a
new car

Style

ALTERNATIVES

Reliability

Civic
Saturn
Escort
Clio

Civic
Saturn
Escort
Clio

Fuel
Economy
Civic
Saturn
Escort
Clio

11

THE INFORMATION
IS THEN
SYNTHESIZED TO
DETERMINE
RELATIVE
RANKINGS OF
ALTERNATIVES

BOTH QUALITATIVE
AND QUANTITATIVE
CRITERIA CAN BE
COMPARED USING
INFORMED
JUDGMENTS TO
DERIVE WEIGHTS
AND PRIORITIES

12

Page 6
6
HOW DO YOU DETERMINE THE RELATIVE
IMPORTANCE OF THE CRITERIA?
Here’s one way !
STYLE
RELIABILITY
FUEL ECONOMY

13

Hmm, I think reliability is the most
important followed by style and fuel
economy is least importeant so I will
make the following judgements ....

HERE’S ANOTHER WAY

USING JUDGMENTS TO
DETERMINE THE RANKING
OF THE CRITERIA

1. RELIABILITY IS 2 TIMES AS IMPORTANT AS STYLE
2. STYLE IS 3 TIMES AS IMPORTANT AS FUEL ECONOMY
3. RELIABILITY IS 4 TIMES AS IMPORTANT AS FUEL ECONOMY

he’s not very consistent here ... that’s o.k.

14

Page 7
7
A

Pairwise Comparisons

B

USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE
OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED

15

A

Pairwise Comparisons

B

USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE
OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED

1 equal 3 moderate 5 strong 7 very strong 9 extreme
STYLE
STYLE

RELIABILITY

1/1

FUEL ECONOMY

FUEL ECONOMY

3/1

1/1

RELIABILITY

1/2

4/1
1/1

16

Page 8
8
A

Pairwise Comparisons

B

USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE
OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED

1 equal 3 moderate 5 strong 7 very strong 9 extreme
STYLE

RELIABILITY

FUEL ECONOMY

STYLE

1/1

1/2

3/1

RELIABILITY

2/1

1/1

4/1

FUEL ECONOMY

1/3

1/4

1/1

17

How do you turn this MATRIX
into ranking of criteria?

STYLE

RELIABILITY

FUEL ECONOMY

STYLE

1/1

1/2

3/1

RELIABILITY

2/1

1/1

4/1

FUEL ECONOMY

1/3

1/4

1/1

18

Page 9
9
HOW DO YOU GET A RANKING OF PRIORITIES FROM A
PAIRWISE MATRIX?
AND THE
SURVEY SAYS

EIGENVECTOR !!

ACTUALLY...
DR THOMAS L. SAATY, CURRENTLY WITH THE UNIVERSITY OF
PITTSBURGH, DEMONSTRATED MATHEMATICALLY THAT THE
EIGENVECTOR SOLUTION WAS THE BEST APPROACH.
REFERENCE : THE ANALYTIC HIERARCHY PROCESS, 1990, THOMAS L. SAATY
19

HERE’S HOW TO SOLVE FOR THE EIGENVECTOR:
1. A SHORT COMPUTATIONAL WAY TO OBTAIN THIS RANKING
IS TO RAISE THE PAIRWISE MATRIX TO POWERS THAT ARE
SUCCESSIVELY SQUARED EACH TIME.
2. THE ROW SUMS ARE THEN CALCULATED AND NORMALIZED.
3. THE COMPUTER IS INSTRUCTED TO STOP WHEN THE
DIFFERENCE BETWEEN THESE SUMS IN TWO CONSECUTIVE
CALCULATIONS IS SMALLER THAN A PRESCRIBED VALUE.
SAY WHAT!

SHOW ME AN
EXAMPLE

20

Page 10
10
IT’S MATRIX ALGEBRA TIME !!!

STYLE

RELIABILITY

FUEL ECONOMY

STYLE

1/1

1/2

3/1

RELIABILITY

2/1

1/1

4/1

FUEL ECONOMY

1/3

1/4

1/1

FOR NOW, LET’S REMOVE THE NAMES AND
CONVERT THE FRACTIONS TO DECIMALS :

1.0000

0.5000

3.0000

2.0000

1.0000

4.0000

0.3333

0.2500

1.0000
21

STEP 1: SQUARING THE MATRIX
1.0000
2.0000

1.0000

4.0000

0.2500

1.0000

1.0000

0.5000

3.0000

2.0000

1.0000

4.0000

0.3333

THIS

3.0000

0.3333

THIS TIMES

0.5000

0.2500

1.0000

I.E. (1.0000 * 1.0000) + (0.5000 * 2.0000) +(3.0000 * 0.3333) = 3.0000

3.0000
RESULTS
IN THIS

1.7500

8.0000

5.3332

3.0000

14.0000

1.1666

0.6667

3.0000
22

Page 11
11
STEP 2 : NOW, LET’S COMPUTE OUR FIRST EIGENVECTOR
(TO FOUR DECIMAL PLACES)
FIRST, WE SUM THE ROWS

3.0000

+

1.7500

+

8.0000

= 12.7500

0.3194

5.3332

+

3.0000

+

14.0000

= 22.3332

0.5595

1.1666

+

0.6667

+

3.0000

=

4.8333

0.1211

39.9165

1.0000

SECOND, WE SUM THE ROW TOTALS
FINALLY, WE NORMALIZE BY DIVIDING
THE ROW SUM BY THE ROW TOTALS
(I.E. 12.7500 DIVIDED BY 39.9165 EQUALS 0.3194)

0.3194
THE RESULT IS OUR EIGENVECTOR
( A LATER SLIDE WILL EXPLAIN THE
MEANING IN TERMS OF OUR EXAMPLE)

0.5595
0.1211
23

THIS PROCESS MUST BE ITERATED UNTIL THE EIGENVECTOR
SOLUTION DOES NOT CHANGE FROM THE PREVIOUS ITERATION
(REMEMBER TO FOUR DECIMAL PLACES IN OUR EXAMPLE)
CONTINUING OUR EXAMPLE,
AGAIN, STEP 1: WE SQUARE THIS MATRIX
3.0000

1.7500

8.0000

5.3332

3.0000

14.0000

1.1666

0.6667

3.0000

27.6653
WITH THIS RESULT

15.8330

72.4984

48.3311

27.6662

126.6642

10.5547

6.0414

27.6653

24

Page 12
12
AGAIN STEP 2 : COMPUTE THE EIGENVECTOR (TO FOUR DECIMAL PLACES)
27.6653

+

15.8330

+

72.4984

= 115.9967

0.3196

48.3311

+

27.6662

+ 126.6642

= 202.6615

0.5584

10.5547

+

6.0414

+

=

44.2614

0.1220

TOTALS 362.9196
COMPUTE THE DIFFERENCE OF THE
PREVIOUS COMPUTED EIGENVECTOR
TO THIS ONE:
0.3194
= - 0.0002
0.3196

1.0000

27.6653

0.5595

0.5584

=

0.0011

0.1211

0.1220

= - 0.0009

TO FOUR DECIMAL PLACES THERE’S NOT MUCH DIFFERENCE
HOW ABOUT ONE MORE ITERATION?
25

I SURRENDER !!
DON’T MAKE ME COMPUTE
ANOTHER EIGENVECTOR
OKAY,OKAY
ACTUALLY, ONE MORE
ITERATION WOULD
SHOW NO DIFFERENCE
TO FOUR DECIMAL
PLACES

LET’S NOW LOOK AT
THE MEANING OF THE
EIGENVECTOR

26

Page 13
13
HERE’S OUR PAIRWISE
MATRIX WITH THE NAMES
STYLE

RELIABILITY

FUEL ECONOMY

STYLE

1/1

1/2

3/1

RELIABILITY

2/1

1/1

4/1

FUEL ECONOMY

1/3

1/4

1/1

AND THE COMPUTED EIGENVECTOR GIVES US THE RELATIVE
RANKING OF OUR CRITERIA
STYLE

0.3196

THE SECOND MOST IMPORTANT CRITERION

RELIABILITY

0.5584

THE MOST IMPORTANT CRITERION

FUEL ECONOMY

0.1220

THE LEAST IMPORTANT CRITERION

NOW BACK TO THE HIEARCHICAL TREE...
27

HERE’S THE TREE
WITH THE CRITERIA
WEIGHTS
OBJECTIVE
CRITERIA
Select a new
car
1.00

Style
.3196

ALTERNATIVES

Civic
Saturn
Escort
Clio

Reliability
.5584

Civic
Saturn
Escort
Clio

Fuel Economy
.1220

Civic
Saturn
Escort
Clio

WHAT ABOUT THE ALTERNATIVES?

I’M GLAD YOU ASKED...
28

SKEPTIC-GATOR

Page 14
14
IN TERMS OF STYLE, PAIRWISE COMPARISONS
DETERMINES THE PREFERENCE
OF EACH ALTERNATIVE OVER ANOTHER

STYLE
CIVIC SATURN ESCORT CLIO
CIVIC

1/1

1/4

4/1

1/6

SATURN

4/1

1/1

4/1

1/4

ESCORT

1/4

1/4

1/1

1/5

CLIO

6/1

4/1

5/1

1/1

AND...
29

IN TERMS OF RELIABILITY, PAIRWISE
COMPARISONS DETERMINES THE PREFERENCE
OF EACH ALTERNATIVE OVER ANOTHER

RELIABILITY
CIVIC SATURN ESCORT CLIO
CIVIC

1/1

2/1

5/1

1/1

SATURN

1/2

1/1

3/1

2/1

ESCORT

1/5

1/3

1/1

1/4

CLIO

1/1

1/2

4/1

1/1

ITS MATRIX ALGEBRA TIME!!!

30

Page 15
15
COMPUTING THE EIGENVECTOR
DETERMINES THE RELATIVE
RANKING OF ATERNATIVES
UNDER EACH CRITERION

RANKING

STYLE

RELIABILITY

RANKING

3

CIVIC

.1160

1

CIVIC

.3790

2

SATURN

.2470

2

SATURN

.2900

4

ESCORT

.0600

4

ESCORT

.0740

1

CLIO

.5770

3

CLIO

.2570

WHAT ABOUT FUEL ECONOMY?
ANOTHER GOOD QUESTION...
31

SKEPTIC-GATOR

AS STATED EARLIER,
AHP CAN COMBINE BOTH QUALITATIVE
AND QUANITATIVE INFORMATION

FUEL ECONOMY INFORMATION IS OBTAINED FOR EACH
ALTERNATIVE:
FUEL ECONOMY
(MILES/GALLON)
CIVIC

34

34 / 113 =

.3010

SATURN

27

27 / 113 =

.2390

ESCORT

24

24 / 113 =

.2120

CLIO

28

28 / 113 =

.2480

113

1.0000

NORMALIZING THE FUEL ECONOMY INFO
ALLOWS US TO USE IT WITH OTHER RANKINGS
32

Page 16
16
HERE’S THE TREE
WITH ALL THE
WEIGHTS
OBJECTIVE
CRITERIA
Select a new
car
1.00

Style
.3196

ALTERNATIVES

Civic
Saturn
Escort
Clio

Reliability
.5584

.1160
.2470
.0600
.5770

Civic
Saturn
Escort
Clio

Fuel Economy
.1220

.3790
.2900
.0740
.2570

Civic
Saturn
Escort
Clio

.3010
.2390
.2120
.2480

OKAY, NOW WHAT ? I THINK WE’RE READY
FOR THE ANSWER...
33

A LITTLE MORE MATRIX ALGEBRA GIVES US THE SOLUTION:
STYLE

RELIFUEL
ABILITY ECONOMY

CIVIC

.1160

.3790

.3010

SATURN

.2470

.2900

.2390

ESCORT

.0600

.0740

.2120

CLIO

.5770

.2570

.2480

CRITERIA
RANKING
0.3196

0.5584

RELIABILITY

0.1220

*

STYLE

FUEL ECONOMY

I.E. FOR THE CIVIC (.1160 * .3196) + (.3790 * .5584) + (.3010 * .1220) = .3060
Civic

=

.3060

Saturn

.2720

Escort

.0940

Clio

AND THE WINNER IS !!!

.3280

THE CLIO IS THE
HIGHEST RANKED CAR

34

Page 17
17
IN SUMMARY, THE ANALYTIC HIERARCHY
PROCESS PROVIDES A LOGICAL FRAMEWORK
TO DETERMINE THE BENEFITS OF EACH
ALTERNATIVE

1. Clio

.3280

2. Civic

.3060

3. Saturn

.2720

4. Escort

.0940

WHAT ABOUT COSTS?

WELL, I’LL TELL YOU...
SKEPTIC-GATOR

35

ALTHOUGH COSTS COULD HAVE BEEN
INCLUDED, IN MANY COMPLEX DECISIONS,
COSTS SHOULD BE SET ASIDE UNTIL THE
BENEFITS OF THE ALTERNATIVES ARE
EVALUATED

OTHERWISE THIS COULD HAPPEN...

YOUR PROGRAM COST TOO MUCH I
DON’T CARE ABOUT ITS BENEFITS

DISCUSSING COSTS
TOGETHER WITH BENEFITS
CAN SOMETIMES BRING FORTH
MANY POLITICAL AND
EMOTIONAL RESPONSES

36

Page 18
18
WAYS TO HANDLE BENEFITS
AND COSTS INCLUDE THE
FOLLOWING:

1. GRAPHING BENEFITS AND COSTS OF EACH ALTERNATIVE

.
BENEFITS

.
.

.

CHOSE ALTERNATIVE WITH LOWEST
COST AND HIGHEST BENEFIT

COSTS

2. BENEFIT TO COST RATIOS
3. LINEAR PROGRAMMING
4. SEPARATE BENEFIT AND COST HIERARCHICAL TREES
AND THEN COMBINE THE RESULTS

IN OUR EXAMPLE...
37

LET’S USE BENEFIT TO COST RATIOS

NORMALIZED
COSTS
BENEFIT - COST RATIOS
.3333
.3280 / .3333 = .9840

1. CLIO

COST $
18,000

2. CIVIC

12,000

.2222

.3060 / .2222 = 1.3771

3. SATURN

15,000

.2778

.2720 / .2778 =

.9791

4. ESCORT

9,000

.1667

.0940 / .1667 =

.5639

54,000

1.0000
(REMEMBER THE BENEFITS WERE DERIVED
EARLIER FROM THE AHP)

AND...
THE CIVIC IS THE WINNER WITH THE HIGHEST BENEFIT TO COST RATIO
38

Page 19
19
AHP CAN BE USED FOR VERY
COMPLEX DECISIONS

GOAL

MANY LEVELS OF CRITERIA
AND SUBCRITERIA CAN
BE INCLUDED

HERE’S SOME EXAMPLES
39

AHP CAN BE USED FOR A WIDE
VARIETY OF APPLICATIONS

STRATEGIC PLANNING
RESOURCE ALLOCATION
SOURCE SELECTION
BUSINESS/PUBLIC POLICY
PROGAM SELECTION
AND MUCH MUCH MORE...

40

Page 20
20

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Analytics

  • 1. An Illustrated Guide to the ANALYTIC HIERARCHY PROCESS Dr. Rainer Haas Dr. Oliver Meixner Institute of Marketing & Innovation University of Natural Resources and Applied Life Sciences, Vienna http://www.boku.ac.at/mi/ 1 Do your decision conferences turn out like this? TOO BAD! WE WANT PROGRAM B !! WE WANT PROGRAM A !! COME ON IN THE WATER IS FINE! sea of indecision or does this happen? 2 Page 1 1
  • 2. DO YOUR RECOMMENDATIONS TURN OUT LIKE THIS? BUT BOSS... THAT WAS MY BEST GUESS! GUESS AGAIN MAYBE YOU NEED A NEW APPROACH 3 ... another way of decision making I THINK I ‘LL TRY THE ANALYTIC HIERARCHY PROCESS (AHP) !!! 4 Page 2 2
  • 3. OKAY TELL US ABOUT AHP DR THOMAS L. SAATY DEVELOPED THE PROCESS IN THE EARLY 1970’S AND... 5 THE PROCESS HAS BEEN USED TO ASSIST NUMEROUS CORPORATE AND GOVERNMENT DECISION MAKERS. Some examples of decision problems: choosing a telecommunication system formulating a drug policy choosing a product marketing strategy ... 6 Page 3 3
  • 4. Let’s show how it works PROBLEMS ARE DECOMPOSED INTO A HIERARCHY OF CRITERIA AND ALTERNATIVES Problem Criterion 1 Criterion 1.1 ... Criterion 2 Criterion n ... ... Alternative 1 Alternative 2 ... Alternative n 7 OKAY, HERE’S A DECISION PROBLEM WE FACE IN OUR PERSONAL LIVES 8 Page 4 4
  • 5. I SEE A NEW CAR IN YOUR FUTURE 9 AN IMPORTANT PART OF THE PROCESS IS TO ACCOMPLISH THESE THREE STEPS • STATE THE OBJECTIVE: – SELECT A NEW CAR • DEFINE THE CRITERIA: – STYLE, RELIABILITY, FUEL ECONOMY • PICK THE ALTERNATIVES: – CIVIC COUPE, SATURN COUPE, FORD ESCORT, RENAULT CLIO WHAT ABOUT COST? (BE QUIET, WE’LL TALK ABOUT THAT LATER) 10 SKEPTIC-GATOR Page 5 5
  • 6. THIS INFORMATION IS THEN ARRANGED IN A HIERARCHICAL TREE OBJECTIVE CRITERIA Select a new car Style ALTERNATIVES Reliability Civic Saturn Escort Clio Civic Saturn Escort Clio Fuel Economy Civic Saturn Escort Clio 11 THE INFORMATION IS THEN SYNTHESIZED TO DETERMINE RELATIVE RANKINGS OF ALTERNATIVES BOTH QUALITATIVE AND QUANTITATIVE CRITERIA CAN BE COMPARED USING INFORMED JUDGMENTS TO DERIVE WEIGHTS AND PRIORITIES 12 Page 6 6
  • 7. HOW DO YOU DETERMINE THE RELATIVE IMPORTANCE OF THE CRITERIA? Here’s one way ! STYLE RELIABILITY FUEL ECONOMY 13 Hmm, I think reliability is the most important followed by style and fuel economy is least importeant so I will make the following judgements .... HERE’S ANOTHER WAY USING JUDGMENTS TO DETERMINE THE RANKING OF THE CRITERIA 1. RELIABILITY IS 2 TIMES AS IMPORTANT AS STYLE 2. STYLE IS 3 TIMES AS IMPORTANT AS FUEL ECONOMY 3. RELIABILITY IS 4 TIMES AS IMPORTANT AS FUEL ECONOMY he’s not very consistent here ... that’s o.k. 14 Page 7 7
  • 8. A Pairwise Comparisons B USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED 15 A Pairwise Comparisons B USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED 1 equal 3 moderate 5 strong 7 very strong 9 extreme STYLE STYLE RELIABILITY 1/1 FUEL ECONOMY FUEL ECONOMY 3/1 1/1 RELIABILITY 1/2 4/1 1/1 16 Page 8 8
  • 9. A Pairwise Comparisons B USING PAIRWISE COMPARISONS, THE RELATIVE IMPORTANCE OF ONE CRITERION OVER ANOTHER CAN BE EXPRESSED 1 equal 3 moderate 5 strong 7 very strong 9 extreme STYLE RELIABILITY FUEL ECONOMY STYLE 1/1 1/2 3/1 RELIABILITY 2/1 1/1 4/1 FUEL ECONOMY 1/3 1/4 1/1 17 How do you turn this MATRIX into ranking of criteria? STYLE RELIABILITY FUEL ECONOMY STYLE 1/1 1/2 3/1 RELIABILITY 2/1 1/1 4/1 FUEL ECONOMY 1/3 1/4 1/1 18 Page 9 9
  • 10. HOW DO YOU GET A RANKING OF PRIORITIES FROM A PAIRWISE MATRIX? AND THE SURVEY SAYS EIGENVECTOR !! ACTUALLY... DR THOMAS L. SAATY, CURRENTLY WITH THE UNIVERSITY OF PITTSBURGH, DEMONSTRATED MATHEMATICALLY THAT THE EIGENVECTOR SOLUTION WAS THE BEST APPROACH. REFERENCE : THE ANALYTIC HIERARCHY PROCESS, 1990, THOMAS L. SAATY 19 HERE’S HOW TO SOLVE FOR THE EIGENVECTOR: 1. A SHORT COMPUTATIONAL WAY TO OBTAIN THIS RANKING IS TO RAISE THE PAIRWISE MATRIX TO POWERS THAT ARE SUCCESSIVELY SQUARED EACH TIME. 2. THE ROW SUMS ARE THEN CALCULATED AND NORMALIZED. 3. THE COMPUTER IS INSTRUCTED TO STOP WHEN THE DIFFERENCE BETWEEN THESE SUMS IN TWO CONSECUTIVE CALCULATIONS IS SMALLER THAN A PRESCRIBED VALUE. SAY WHAT! SHOW ME AN EXAMPLE 20 Page 10 10
  • 11. IT’S MATRIX ALGEBRA TIME !!! STYLE RELIABILITY FUEL ECONOMY STYLE 1/1 1/2 3/1 RELIABILITY 2/1 1/1 4/1 FUEL ECONOMY 1/3 1/4 1/1 FOR NOW, LET’S REMOVE THE NAMES AND CONVERT THE FRACTIONS TO DECIMALS : 1.0000 0.5000 3.0000 2.0000 1.0000 4.0000 0.3333 0.2500 1.0000 21 STEP 1: SQUARING THE MATRIX 1.0000 2.0000 1.0000 4.0000 0.2500 1.0000 1.0000 0.5000 3.0000 2.0000 1.0000 4.0000 0.3333 THIS 3.0000 0.3333 THIS TIMES 0.5000 0.2500 1.0000 I.E. (1.0000 * 1.0000) + (0.5000 * 2.0000) +(3.0000 * 0.3333) = 3.0000 3.0000 RESULTS IN THIS 1.7500 8.0000 5.3332 3.0000 14.0000 1.1666 0.6667 3.0000 22 Page 11 11
  • 12. STEP 2 : NOW, LET’S COMPUTE OUR FIRST EIGENVECTOR (TO FOUR DECIMAL PLACES) FIRST, WE SUM THE ROWS 3.0000 + 1.7500 + 8.0000 = 12.7500 0.3194 5.3332 + 3.0000 + 14.0000 = 22.3332 0.5595 1.1666 + 0.6667 + 3.0000 = 4.8333 0.1211 39.9165 1.0000 SECOND, WE SUM THE ROW TOTALS FINALLY, WE NORMALIZE BY DIVIDING THE ROW SUM BY THE ROW TOTALS (I.E. 12.7500 DIVIDED BY 39.9165 EQUALS 0.3194) 0.3194 THE RESULT IS OUR EIGENVECTOR ( A LATER SLIDE WILL EXPLAIN THE MEANING IN TERMS OF OUR EXAMPLE) 0.5595 0.1211 23 THIS PROCESS MUST BE ITERATED UNTIL THE EIGENVECTOR SOLUTION DOES NOT CHANGE FROM THE PREVIOUS ITERATION (REMEMBER TO FOUR DECIMAL PLACES IN OUR EXAMPLE) CONTINUING OUR EXAMPLE, AGAIN, STEP 1: WE SQUARE THIS MATRIX 3.0000 1.7500 8.0000 5.3332 3.0000 14.0000 1.1666 0.6667 3.0000 27.6653 WITH THIS RESULT 15.8330 72.4984 48.3311 27.6662 126.6642 10.5547 6.0414 27.6653 24 Page 12 12
  • 13. AGAIN STEP 2 : COMPUTE THE EIGENVECTOR (TO FOUR DECIMAL PLACES) 27.6653 + 15.8330 + 72.4984 = 115.9967 0.3196 48.3311 + 27.6662 + 126.6642 = 202.6615 0.5584 10.5547 + 6.0414 + = 44.2614 0.1220 TOTALS 362.9196 COMPUTE THE DIFFERENCE OF THE PREVIOUS COMPUTED EIGENVECTOR TO THIS ONE: 0.3194 = - 0.0002 0.3196 1.0000 27.6653 0.5595 0.5584 = 0.0011 0.1211 0.1220 = - 0.0009 TO FOUR DECIMAL PLACES THERE’S NOT MUCH DIFFERENCE HOW ABOUT ONE MORE ITERATION? 25 I SURRENDER !! DON’T MAKE ME COMPUTE ANOTHER EIGENVECTOR OKAY,OKAY ACTUALLY, ONE MORE ITERATION WOULD SHOW NO DIFFERENCE TO FOUR DECIMAL PLACES LET’S NOW LOOK AT THE MEANING OF THE EIGENVECTOR 26 Page 13 13
  • 14. HERE’S OUR PAIRWISE MATRIX WITH THE NAMES STYLE RELIABILITY FUEL ECONOMY STYLE 1/1 1/2 3/1 RELIABILITY 2/1 1/1 4/1 FUEL ECONOMY 1/3 1/4 1/1 AND THE COMPUTED EIGENVECTOR GIVES US THE RELATIVE RANKING OF OUR CRITERIA STYLE 0.3196 THE SECOND MOST IMPORTANT CRITERION RELIABILITY 0.5584 THE MOST IMPORTANT CRITERION FUEL ECONOMY 0.1220 THE LEAST IMPORTANT CRITERION NOW BACK TO THE HIEARCHICAL TREE... 27 HERE’S THE TREE WITH THE CRITERIA WEIGHTS OBJECTIVE CRITERIA Select a new car 1.00 Style .3196 ALTERNATIVES Civic Saturn Escort Clio Reliability .5584 Civic Saturn Escort Clio Fuel Economy .1220 Civic Saturn Escort Clio WHAT ABOUT THE ALTERNATIVES? I’M GLAD YOU ASKED... 28 SKEPTIC-GATOR Page 14 14
  • 15. IN TERMS OF STYLE, PAIRWISE COMPARISONS DETERMINES THE PREFERENCE OF EACH ALTERNATIVE OVER ANOTHER STYLE CIVIC SATURN ESCORT CLIO CIVIC 1/1 1/4 4/1 1/6 SATURN 4/1 1/1 4/1 1/4 ESCORT 1/4 1/4 1/1 1/5 CLIO 6/1 4/1 5/1 1/1 AND... 29 IN TERMS OF RELIABILITY, PAIRWISE COMPARISONS DETERMINES THE PREFERENCE OF EACH ALTERNATIVE OVER ANOTHER RELIABILITY CIVIC SATURN ESCORT CLIO CIVIC 1/1 2/1 5/1 1/1 SATURN 1/2 1/1 3/1 2/1 ESCORT 1/5 1/3 1/1 1/4 CLIO 1/1 1/2 4/1 1/1 ITS MATRIX ALGEBRA TIME!!! 30 Page 15 15
  • 16. COMPUTING THE EIGENVECTOR DETERMINES THE RELATIVE RANKING OF ATERNATIVES UNDER EACH CRITERION RANKING STYLE RELIABILITY RANKING 3 CIVIC .1160 1 CIVIC .3790 2 SATURN .2470 2 SATURN .2900 4 ESCORT .0600 4 ESCORT .0740 1 CLIO .5770 3 CLIO .2570 WHAT ABOUT FUEL ECONOMY? ANOTHER GOOD QUESTION... 31 SKEPTIC-GATOR AS STATED EARLIER, AHP CAN COMBINE BOTH QUALITATIVE AND QUANITATIVE INFORMATION FUEL ECONOMY INFORMATION IS OBTAINED FOR EACH ALTERNATIVE: FUEL ECONOMY (MILES/GALLON) CIVIC 34 34 / 113 = .3010 SATURN 27 27 / 113 = .2390 ESCORT 24 24 / 113 = .2120 CLIO 28 28 / 113 = .2480 113 1.0000 NORMALIZING THE FUEL ECONOMY INFO ALLOWS US TO USE IT WITH OTHER RANKINGS 32 Page 16 16
  • 17. HERE’S THE TREE WITH ALL THE WEIGHTS OBJECTIVE CRITERIA Select a new car 1.00 Style .3196 ALTERNATIVES Civic Saturn Escort Clio Reliability .5584 .1160 .2470 .0600 .5770 Civic Saturn Escort Clio Fuel Economy .1220 .3790 .2900 .0740 .2570 Civic Saturn Escort Clio .3010 .2390 .2120 .2480 OKAY, NOW WHAT ? I THINK WE’RE READY FOR THE ANSWER... 33 A LITTLE MORE MATRIX ALGEBRA GIVES US THE SOLUTION: STYLE RELIFUEL ABILITY ECONOMY CIVIC .1160 .3790 .3010 SATURN .2470 .2900 .2390 ESCORT .0600 .0740 .2120 CLIO .5770 .2570 .2480 CRITERIA RANKING 0.3196 0.5584 RELIABILITY 0.1220 * STYLE FUEL ECONOMY I.E. FOR THE CIVIC (.1160 * .3196) + (.3790 * .5584) + (.3010 * .1220) = .3060 Civic = .3060 Saturn .2720 Escort .0940 Clio AND THE WINNER IS !!! .3280 THE CLIO IS THE HIGHEST RANKED CAR 34 Page 17 17
  • 18. IN SUMMARY, THE ANALYTIC HIERARCHY PROCESS PROVIDES A LOGICAL FRAMEWORK TO DETERMINE THE BENEFITS OF EACH ALTERNATIVE 1. Clio .3280 2. Civic .3060 3. Saturn .2720 4. Escort .0940 WHAT ABOUT COSTS? WELL, I’LL TELL YOU... SKEPTIC-GATOR 35 ALTHOUGH COSTS COULD HAVE BEEN INCLUDED, IN MANY COMPLEX DECISIONS, COSTS SHOULD BE SET ASIDE UNTIL THE BENEFITS OF THE ALTERNATIVES ARE EVALUATED OTHERWISE THIS COULD HAPPEN... YOUR PROGRAM COST TOO MUCH I DON’T CARE ABOUT ITS BENEFITS DISCUSSING COSTS TOGETHER WITH BENEFITS CAN SOMETIMES BRING FORTH MANY POLITICAL AND EMOTIONAL RESPONSES 36 Page 18 18
  • 19. WAYS TO HANDLE BENEFITS AND COSTS INCLUDE THE FOLLOWING: 1. GRAPHING BENEFITS AND COSTS OF EACH ALTERNATIVE . BENEFITS . . . CHOSE ALTERNATIVE WITH LOWEST COST AND HIGHEST BENEFIT COSTS 2. BENEFIT TO COST RATIOS 3. LINEAR PROGRAMMING 4. SEPARATE BENEFIT AND COST HIERARCHICAL TREES AND THEN COMBINE THE RESULTS IN OUR EXAMPLE... 37 LET’S USE BENEFIT TO COST RATIOS NORMALIZED COSTS BENEFIT - COST RATIOS .3333 .3280 / .3333 = .9840 1. CLIO COST $ 18,000 2. CIVIC 12,000 .2222 .3060 / .2222 = 1.3771 3. SATURN 15,000 .2778 .2720 / .2778 = .9791 4. ESCORT 9,000 .1667 .0940 / .1667 = .5639 54,000 1.0000 (REMEMBER THE BENEFITS WERE DERIVED EARLIER FROM THE AHP) AND... THE CIVIC IS THE WINNER WITH THE HIGHEST BENEFIT TO COST RATIO 38 Page 19 19
  • 20. AHP CAN BE USED FOR VERY COMPLEX DECISIONS GOAL MANY LEVELS OF CRITERIA AND SUBCRITERIA CAN BE INCLUDED HERE’S SOME EXAMPLES 39 AHP CAN BE USED FOR A WIDE VARIETY OF APPLICATIONS STRATEGIC PLANNING RESOURCE ALLOCATION SOURCE SELECTION BUSINESS/PUBLIC POLICY PROGAM SELECTION AND MUCH MUCH MORE... 40 Page 20 20