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# ปริมาณสารสัมพันธ์1

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### ปริมาณสารสัมพันธ์1

1. 1. ʿ F F11. 3>1>2 F 1. Al(NO3)3 = 27+3(14+3(16)) = 213 2. (NH4)3PO4 = 3(14+4(1))+31+4(16)= 195 3. Ca(H2PO4)2 = 40+2(2(1)+31+4(16))= 2342. 2.24 dm3 F FF = 23 6.02 ×10 22.4 6.02 × 10 22 = 6.02 × 10 23 22.4 = 2.24 dm33. 24.36 g MBr2 + Cl2 MCl2 + Br2 MBr2 = 5.35 g Cl2 = 650 cm3 = 0.65 dm3 F M F (g) FF ( g) = 22.4 5.35 0.65 = M + 160 22.4 5.35(22.4) M = - 160 0.65 M = 24.36
2. 2. 4. 0.75 g + AgNO3 - − Cl + AgNO3 AgCl + NO 3 Ag : Cl : AgCl 108 : 35.5 : 143.5 : X : 3.01 X = 3.01 35.5 143.5 X = 0.75 g5. 12.14 g F F NH3 F F N : H : NH3 14 : 3 : 17 10 : 10 : X 10 10 X : : 14 3 35.5 X 0.71 : 3.33 : 35.5 X = 0.71 35.5 X = 12.14 g6. N2O F F F F NO 58 N 27 O 31 F N : O 14 : 16 27 : 31 27 31 : 14 16 1.93 : 1.94 1 : 1 F F F N:O ˈ F 1:1 F ˈ NO F
3. 3. 2 F NaOb 72 N 46 O 26 F F N : O 14 : 16 46 : 26 46 26 : 14 16 3.29 : 1.625 2 : 1 F N:O ˈ 2:1 F N2O7. 51.2 SO2 F S8 F 12.8 SO2 = 12.8 g = = 0.2 mol 64 1 F F S8 F F 0.2 ( g) = ( g) 0.2 = 256 ( g) = 256×0.2 = 51.2 g8. ( .) 17, 18 20, 17 Cl 17 35.5 18 17 18 18 17 19 17 17 18 20 17 17 18 17 Cl = 17 F . . F ˈ F F . . Cl ˈ 35.5 F Cl F F F 2 F ˈ F F .
4. 4. 9. 5.6 F ˈ . ( g) = ×6.02×10 23 ( g) = 0.301×1023 × 56 1×6.02×1023 ( g) = 2.8 g10. 5.1 g F = 22.4 6.72 = 22.4 17 = 5.1 g X11. 6 F O2 4 x F SO2 4 F SO2 A 4 O2 x 16 4 SO2 A 96 4 16 x A= ( × ) (x) = 96 4 612. 136 F 5 Z2O3 = 10 F F 5 F Z2O3 5(2Z+(16×3)) = 10×5×32 Z = 320 – 48 2 Z = 136
5. 5. 13. 60 g F F F F F F X = 20 g O2 96 X X = 96 20 32 X = 60 g14. 112 F ZO3 2.5 ˈ 5 F O5 2.5(Z+48) = 5×5×16 Z = 5×5×16 – 48 2.5 Z = 11215. 39.99 = ∑ ( ×% ) 100 = (36×0.1)+(38×0.3)+(40×99.6) 10016. 10% F F % 15 X F% 15 X ˈ A F = ∑ ( ×% ) 100 14.10 = (14×(100-A))+(15×A) 100 1410 = 1400-14A+15A A = 10%
6. 6. 17. O2 ,C 10 g , CO2 22 g F F F CO2 F F C : O : CO2 12 : 16 : 44 3 : 8 : 11 16 : 16 : X 16 16 X : : 3 8 11 X 5.3 : 2 : 11 X = 22 g F F O2 ,C 10 g, CO2 22 g18. 24 g F F F CO2 88 C C : O : CO2 12 : 16 : 44 3 : 8 : 11 X : Y : 88 X Y 88 : : 3 8 11 F F C C CO2 F X 88 = 3 11 X = 24 g19. 6g F F F F A:B C F F C F C F F A : B : C 2 : 5 : 7 X : Y : 21 X Y 21 : : 2 5 7 X 21 A:C : 2 7 X = 6g
7. 7. 20. 3.01×1011 X α He F F He 1×10 8 X 10 F F He 0.112 cm3 X He 1×108 mol X 10 6.02 ×1023 He 0.112×10-3 mol X A 22.4 A = 10×0.112×10-3×6.02 ×1023 22.4×1×108 A = 3.01×1011