10 Perpendicular Lines

A (4, 4) D (-4, 4) B (4, -4) C (-4, -4) 90 0 90 0

Perpendicular Lines 0 y x A (a , b) B (-b , a) After a 90 0 rotation (anti-clockwise) A moves to B As both lines go through origin gradients are: 90 0 NB Fraction has been turned upside down and turned into negative

Copy the following: For perpendicular lines: 1. Lines are perpendicular 2. To find gradient of line perpendicular to given line think: “ Flip the fraction and change the sign”

Example 1 What is the gradient of a line perpendicular to the line through the points P (4 , 7) and Q (5 , 11) ? Solution : ,[object Object],[object Object],Flip fraction- change sign 2. Use m 1 x m 2 = -1 to find gradient of perpendicular line.

Example 2 Two lines have equations 3x + 2y - 7 = 0 & 4x - 6y + 1 = 0 Prove that they are perpendicular. Solution : ,[object Object],[object Object],[object Object],Line 1 3x + 2y - 7 = 0 2y = -3x + 7 Gradient 1 = -3/2 Line 2 4x - 6y + 1 = 0 6y = 4x + 1 Gradient 2 = 2/3 2. Find the gradient of line 2 by rearranging and using y = mx + c

Example 2 Two lines have equations 3x + 2y - 7 = 0 & 4x - 6y + 1 = 0 Prove that they are perpendicular. Solution : 3. Check that m 1 x m 2 = -1 4. Make statement Since m 1 x m 2 = -1 lines are perpendicular

Heinemann, p.6, Ex 1D, Q1, 2, 3 & 6

10 Perpendicular Lines

Recomendados

Recomendados

Mais conteúdo relacionado

Mais procurados

Mais procurados (20)

Destaque

Destaque (14)

Semelhante a 10 Perpendicular Lines

Semelhante a 10 Perpendicular Lines (20)

Último

Último (20)

10 Perpendicular Lines