Sis(16 poins) From a 12.5 M stock solurtion ot hc D,r75 of 027 solution Calculate the amount of the stock solunion required to u w tsr Tirel Seven (16 Points), A sample of CO, is ut 2.3 stm., and i Deter mine the amount of the gas presemt in woves stored in a 75 maL. Oack .5 Eight, (16 Points). A 45.5g sample of an wnknown metal is mniniaily hested o 99 8 dropped into I final temperature is 20.7 °C. The Specific Heat of waner is 1 Calg C Dehemine h unknown metal. 152g of water at 1 8.5°C. W 85\"C. when the cofee cap calorimever comes to thermal egonRerivom specifis hesk of t Nine. (16 points) Calculate the A,Ho for the bolded reaction given the information below +211,00) +2 H00 cokg) coAe) ? CH(e) 20, - CH(g) CHOH() 0 Ten (16 Points) Show the complete spdf configuration for the following Solution 6. Dilution formula, M1 * V1 = M2 * V2 12.5 * V1 = 0.275 * 75.0 V1 = 1.65 mL So, take 1.65 mL of stock solution and dilute it to 75.0 mL to get 0.275 M solution. 7. Given, P = 2.3 atm V = 75 mL = 0.075 L T = 25 + 273.15 = 298.15 K R = 0.0821 L.atm.K-1.mol-1 Ideal gas equation, P V = n R T n = P V / R T n = 2.3 * 0.075 / ( 0.0821 * 298.15 ) n = 0.00705 mol 8. Heat change = mass * specific heat * change in temperature Heat lost by metal + heat gained by water = 0 45.5 * s * ( 20.7 - 99.8 ) + 152 * 1 * ( 20.7 - 18.5 ) = 0 - 3599.05 * s + 334.4 = 0 s = specific heat = 0.0929 cal/ 0 C.g .