Amazon Interview Questions

PHP:

Example #1 array_unique() example
<?php
$input = array("a" => "green", "red", "b" => "green", "blue", "red");
$result = array_unique($input);
print_r($result);
?>

The above example will output:

Array
(
[a] => green
[0] => red
[1] => blue
)

See Also

 count() - Count all elements in an array, or something in an object
 array_unique() - Removes duplicate values from an array
 array_values() - Return all the values of an array
 count_chars() - Return information about characters used in a string
 Examples
 Example #1 count() example
 <?php
$a[0] = 1;
$a[1] = 3;
$a[2] = 5;
$result = count($a);
// $result == 3

$b[0] = 7;
$b[5] = 9;
$b[10] = 11;
$result = count($b);
// $result == 3

$result = count(null);
// $result == 0

$result = count(false);
// $result == 1
?>
 Example #2 Recursive count() example
 <?php
$food = array('fruits' => array('orange', 'banana', 'apple'),
'veggie' => array('carrot', 'collard', 'pea'));

// recursive count
echo count($food, COUNT_RECURSIVE); // output 8

// normal count
echo count($food); // output 2

?>

hi to all
iam using vb6.0 can any one tell me how to duplicate values in a array if possible i want to delete the
duplicate values
its urgent

yes, there are many ways and methods, some faster than others. The worst, slower, but easier will
be to check each one vs each one, lets say your array is Arr1

1. dim i, j, n as integer
2. dim list() as integer
3. n=0
4. for i = lbound(arr1) to ubound(arr1) - 1
5. for j = i + 1 to ubound(arr1)
6. if arr1(i) = arr1(j) then
7. 'here use "home made function" to delete the j-
th item from the array
8. j=j-1
9. end if
10. next j
11. next i

home made function:

1. arr1(j) = arr1(ubound(arr1))
2. redim preserve arr1(lbound(arr1) to&nbs
p;ubound(arr1) -1)

Overview

Arrays are a very useful and easy way of storing variables - and they're especially easy to
use in VBScript. This is due to several factors:

VBScript is particularly liberal with any variable definition - that means that there is no strict
defining of variables to a particular data type.
The data type is assigned automatically when the variable is loaded with a value.
It is even possible to mix data types within the same array.
It is also possible to define the arrays in different ways:
o Create the array element by element.

o Use the VBScript Array method.
o Use the VBScript Split method.
o It is even possible to create multi-dimensional arrays and to make them dynamic rather
than static.

But, VBScript falls short, compared to other programming languages, when it comes to
providing tools for manipulating arrays. Some common array operations that VBScript does
not provide methods for are:

Adding a new elements to an array.
Appending one array to the end of another array.
Inserting new elements at given positions in an array.
Removing elements from an array.
Removing duplicate items from an array.
Sorting the elements in an array.
Reverse the order of the elements in an array.

For some of these tasks, RhinoScript does provide useful methods.

CullDuplicateNumbers - Remove duplicates from an array of numbers.
CullDuplicatePoints - Remove duplicates from an array of 3-D points.
CullDuplicateStrings - Remove duplicates from an array of strings.
SortNumbers - Sorts an array of numbers.
SortPoints - Sorts an array of 3-D points.
SortStrings - Sorts an array of strings.

For the other tasks, you will need to write your own
procedures. Fortunately, VBScript provides us enough tools to write our own procedures to
do most of what we would ever want to do with an array. Note, the following examples are
general purpose utilities. If you need something more specific, these examples are agood
starting point.

Examples

Add a new element to the end of an array

Sub ArrayAdd(ByRef arr, ByVal val)
Dim ub
If IsArray(arr) Then
On Error Resume Next
ub = UBound(arr)
If Err.Number <> 0 Then ub = -1
ReDim Preserve arr(ub + 1)
arr(UBound(arr)) = val
End If
End Sub

Append another array to the end of an array

Sub ArrayAppend(ByRef arr, ByVal arr0)
Dim i, ub
If IsArray(arr) And IsArray(arr0) Then
ub = UBound(arr)
If Err.Number <> 0 Then ub = -1
ReDim Preserve arr(ub + UBound(arr0) + 1)
For i = 0 To UBound(arr0)
arr(ub + 1 + i) = arr0(i)
Next
End If
End Sub

This example uses the .NET ArrayList object:

Sub ArrayAppend(ByRef arr, ByVal arr0)
Dim i, list
Set list = CreateObject("System.Collections.ArrayList")
For i = 0 To UBound(arr)
Call list.Add(arr(i))
Next
For i = 0 To UBound(arr0)
Call list.Add(arr0(i))
Next
arr = list.ToArray()
End If
End Sub

Insert a new element at a given position in an array

Sub ArrayInsert(ByRef arr, ByVal pos, ByVal val)
Dim i
If pos > UBound(arr) Then
Call ArrayAdd(arr, val)
ElseIf pos >= 0 Then
ReDim Preserve arr(UBound(arr) + 1)
For i = UBound(arr) To pos + 1 Step -1
arr(i) = arr(i - 1)
Next
arr(pos) = val
End If
End If
End Sub


Sub ArrayInsert(ByRef arr, ByVal pos, ByVal val)
Dim i, list

Next
Call list.Insert(pos, val)
End If
End Sub

Remove an element from the end of an array

Sub ArrayRemove(ByRef arr)
If UBound(arr) > -1 Then
ReDim Preserve arr(UBound(arr) - 1)
End If
End If
End Sub

Remove an element at a given position from an array

Sub ArrayRemoveAt(ByRef arr, ByVal pos)
Dim i
If pos >= 0 And pos <= UBound(arr) Then
For i = pos To UBound(arr) - 1
arr(i) = arr(i + 1)
Next
ReDim Preserve arr(UBound(arr) - 1)
End If
End If
End Sub


Sub ArrayRemoveAt(ByRef arr, ByVal pos)
Dim i, list
Next
Call list.RemoveAt(pos)
End If
End Sub

Remove all instances of a value from an array

Sub ArrayRemoveVal(ByRef arr, ByVal val)
Dim i, j
i = 0 : j = -1

If arr(i) <> val Then
j = j + 1
arr(j) = arr(i)
End If
Next
ReDim Preserve arr(j)
End If
End Sub

Remove duplicate items from an array

This example uses VBScript's Dictionary object:

Sub ArrayCull(ByRef arr)
Dim i, dict
Set dict = CreateObject("Scripting.Dictionary")
If Not dict.Exists(arr(i)) Then
Call dict.Add(arr(i), arr(i))
End If
Next
arr = dict.Items
End If
End Sub


Sub ArrayCull(ByRef arr)
Dim i, list, tmp
If Not list.Contains(arr(i)) Then
End If
Next
End If
End Sub

Find the first occurance of a value in an array

Function ArraySearch(ByRef arr, ByVal val)
Dim i
ArraySearch = -1
If arr(i) = val Then
ArraySearch = i
Exit Function
End If

Next
End If
End Function

Sort the elements in an array

This example uses a simple Bubble Sort algorithm:

Sub ArraySort(ByRef arr)
Dim i, j, tmp
For i = UBound(arrShort) - 1 To 0 Step -1
For j = 0 To i
If arr(j) > arr(j + 1) Then
tmp = arr(j + 1)
arr(j + 1) = arr(j)
arr(j) = tmp
End If
Next
Next
End If
End Sub


Sub ArraySort(ByRef arr)
Dim i, list
Next
Call list.Sort()
End If
End Sub

Reverse the order of the elements in an array

Sub ArrayReverse(ByRef arr)
Dim i, ub, ub2, tmp
ub = UBound(arr)
ub2 = Int(ub / 2)
For i = 0 To ub2
tmp = arr(i)
arr(i) = arr(ub - i)
arr(ub - i) = tmp
Next
End Sub


Sub ArrayReverse(ByRef arr)
Dim i, list
Next
Call list.Reverse()
End If
End Sub

Verifies that an array has been "dimmed"

Function IsArrayDim(ByVal arr)
IsArrayDim = False
Call UBound(arr)
If Err.Number = 0 Then IsArrayDim = True
End If
End Function

Returns the number of dimensions to an array

Public Function GetArrayDim(ByVal arr)
Dim i
For i = 1 To 60
Call UBound(arr, i)
If Err.Number <> 0 Then
GetArrayDim = i - 1
Exit Function
End If
Next
GetArrayDim = i
Else
GetArrayDim = Null
End If
End Function

Print the contents of an array

Sub ArrayPrint(ByVal arr)
Dim i
Call Rhino.Print("Item(" & CStr(i) & ") = " &
CStr(arr(i)))
Next
End If
End Sub

Re: write vb script code to delete the duplicate values in an array.
Ans dim a 0 Guest
wer aList=Array(5,5,5,5,12,10,15,10,125,5)
# 1 Dim sNewList
dim newArray
b= ubound(aList)

For x=0 to b
If InStr(sNewList,(aList(x) & ",")) <= 0
Then
sNewList = sNewList & aList(x) & ","
End If

Next
newArray = split(sNewList,",")
MsgBox sNewList

Is This Answer Correct ? 18 Yes 3 No

Ans There are many ways this script can be written. 4 Jay
wer One simple algo which i followed was: Praka
#2 sh
''''''''''''''''''''''''''''''''''''''''''''''''
''''''''''''
'''''''''''Script Starts
Here'''''''''''''''''''''''''''''''

Option Explicit

Dim i, j, k, aMyArr, aNewArr( ), iNewIndex,
iNewLim, bFlag

bFlag = 0

aMyArr = Array("AA","BB","AA", "BB" )

iNewIndex = UBound(aMyArr)

ReDim aNewArr(0)
aNewArr(0) = aMyArr(0)

For i=0 To UBound(aMyArr)

iNewLim = UBound(aNewArr)

For j = 0 To iNewLim
If aMyArr(i) = aNewArr(j) Then
bFlag = 0
Exit For
Else
bFlag = 1
End If
Next

If bflag = 1 Then
k=iNewLim+1
ReDim Preserve aNewArr(k)
aNewArr(k)=aMyArr(i)
End If

Next

' To display the new array...
For i = 0 to UBound(aNewArr)
msgbox aNewArr(i)
Next

Erase aMyArr
Erase aNewArr

''''''''''''''''''''''''''''''''''''''''''''''''
''''''''''''
'''''''''''Script Ends
Here'''''''''''''''''''''''''''''''

Please let me know if it satisfies ur query.


Ans aList=Array(5,5,5,5,12,10,15,10,125,5,1,1,2,3,4,
wer 5,6,7,8,8,8,8,8,8,8)
#3
ReDim newArray(UBound(aList))

count=1

newArray(0)=aList(0)

for i=0 to UBound(aList)

temp=aList(i)

flag=0

for j=0 to UBound(newArray)

if ( newArray(j)=temp) Then

flag=1

End if

Next

if flag=0 then

newArray(count)=temp

count=count+1

End If

Next

ReDim Preserve newArray(count)

for j=0 to UBound(newArray)-1

msgbox newArray(j)

Next


Hello all. I have an array (SortedArray) which contains duplicates, and I would like to count
each of them for a report. I know that I could use SQL to count them, but the results come
from 20 different SQL queries. Anyways, below is the code that I have tried. I'm sure it is
something simple, but I am so tired of looking at this code that I can't even think straight. I
kind of have it, but I need for DupCount not to use 'v_AR_Tot' to size the array, and just
use the size of the unique results.

strHeading = ""
strLoc = ""

vLocCount = 0

Dim DupCount()
ReDim Preserve DupCount (v_AR_Tot,6)
i=0

For x=0 to UBound(SortedArray)

Location = SortedArray(x,1)

If strHeading <> Location Then

DupCount(i,0) = Location
i=i+1
vLocCount = 1
DupCount(i,1) = 1

strHeading = Location

Else

vLocCount = vLocCount + 1
DupCount(i,1) = vLocCount
end if
Next

For j=0 to UBound(DupCount)
response.Write(DupCount(j,0) & " - " & DupCount(j,1) & "<BR>")
next

Array And Duplicate Values

I have an excel sheet containing values in column A and Column B. See bellow for
details.

ABC
_________________________________
aaaalbatros
bbbbirds
ccccanine
dddsomething
eeeeeeotherwise
dddasdblablas

i have a loop that goes through the first column and if the lengthe is > 4, the routines
picksup on ly the firt three letters of column B values and add a 1. However, because
all these values must be unique, i wrote a function that should check for duplicates.

I am trying to find duplicate values in the checkDup function. However, i am having
problems with it. I load the values in the array and the pass it to the function. if it is the
same then add 1 and check again until there are no duplicate. then that value is the
next unique value.

There is a twist: the first three letters can repeat and that is fine as long as the added
interger from the counter is different. But the counter should be reset to 1 when a new
set of values are present.

I need help with this. I am stuck.

Code:
Option Explicit
Dim MyArray(60)
Dim MyArray2(30)
Dim myval, myval2 As String
Dim i, j, count As Integer

Private Sub cmdAcct_Click()
'Dim i, j, count As Integer
Dim myval, myval2 As String
Range("C1:F60").Clear
j=1

count = 0
For i = 2 To 60
Range("A" & i).Select
If Len(Range("A" & i).Value) <= 4 Then
Range("D" & i).Value = Range("A" & i).Value
ElseIf Len(Range("A" & i).Value) > 4 Then
count = count + 1
myval2 = Left(Range("b" & i).Value, 3) & count

'******************** this is to check for duplicate

MyArray(j) = myval2 'assigns the value to the array
myval = checkDup(MyArray(j)) 'then checks throught the function if it is a dup
j=j+1

'********************
Range("D" & i).Value = myval

ElseIf Range("A" & i).Value = "" Then
Range("D" & i).Value = "****"

End If
Next i
'Call checkDup
Range("A1").Select
End Sub

Function checkDup(ParamArray MyArray())
Dim i As Integer
Dim result As String

'********************************
For i = 1 To UBound(MyArray)
result = result & MyArray(i) & vbNewLine
Next i

MsgBox result
End Function

var arr = [9, 9, 111, 2, 3, 4, 4, 5, 7];
var sorted_arr = arr.sort(); // You can define the comparing function here.
// JS by default uses a crappy string compare.
var results = [];
for (var i = 0; i < arr.length - 1; i++) {
if (sorted_arr[i + 1] == sorted_arr[i]) {
results.push(sorted_arr[i]);
}
}

alert(results);

Common questions:
Q: Given two numbers m and n, write a method to return the first number r that is
divisible by both (e.g., the least common multiple).

A:
The Approach:
What does it mean for r to be divisible by m and n? It means that all the primes in m must go into r,
and all primes in n must be in r. What if m and n have primes in common?

For example, if m is divisible by 3^5 and n is divisible by 3^7, what does this mean about r? It means r
must be divisible by 3^7.

The Rule: For each prime p such that pâ m (e.g., m is divisible by pâ) and p^b n, r must be
divisible by p^max(a, b)

The Algorithm:
Define q to be 1.
for each prime number p less than m and n:
find the largest a and b such that pâ m and p^b n
let q = q * p^max(a, b)
return q

Links: http://hpsqtp.blogspot.in/search?updated-min=2012-01-01T00:00:00%2B05:30&updated-
max=2013-01-01T00:00:00%2B05:30&max-results=2

http://itknowledgeexchange.techtarget.com/vbscript-systems-administrator/reversing-a-string-with-
vbscript-using-the-mid-function/

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