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Quadratic Formula -b  +   b 2  - 4ac 2a  a x 2  +  b x +  c  = 0 Rewrite quadratic equation in standard form a substitute  a , b , and  c  into formula. x =
Solve:  3x 2  - 5 = 2x
Step 1:  Rewrite in standard form. Solve:  3x 2  - 5 = 2x
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. 3x 2  - 2x - 5 = 0 a b c
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. Step 2:  Plug into formula and simplify. 3x 2  - 2x - 5 = 0 a b c
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. Step 2:  Plug into formula and simplify. 3x 2  - 2x - 5 = 0 a b c x =  -(-2)  +   (-2) 2  - 4(3)(-5) 2(3) x =   -b  +   b 2  - 4ac 2a
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. Step 2:  Plug into formula and simplify. 3x 2  - 2x - 5 = 0 a b c x =  -(-2)  +   (-2) 2  - 4(3)(-5) 2(3) x = 2  +   64 6 x =   -b  +   b 2  - 4ac 2a
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. Step 2:  Plug into formula and simplify. 3x 2  - 2x - 5 = 0 a b c x =  -(-2)  +   (-2) 2  - 4(3)(-5) 2(3) x = 2  +   64 6 x =   2  +  8 6 x =   -b  +   b 2  - 4ac 2a
Solve:  3x 2  - 5 = 2x Step 1:  Rewrite in standard form. Step 2:  Plug into formula and simplify. =  5/3, -1 3x 2  - 2x - 5 = 0 a b c x =  -(-2)  +   (-2) 2  - 4(3)(-5) 2(3) x = 2  +   64 6 x =   2  +  8 6 x =   -b  +   b 2  - 4ac 2a
Solve:  3x 2  = 5x - 2
Solve:  3x 2  = 5x - 2 3x 2  - 5x + 2 = 0
Solve:  3x 2  = 5x - 2 3x 2  - 5x + 2 = 0 x =  -(-5) +  (-5) 2  - 4(3)(2) 2(3)
 
Solve:  3x 2  = 5x - 2 3x 2  - 5x + 2 = 0 = 1, 2/3 x =  -(-5) +  (-5) 2  - 4(3)(2) 2(3) x = 5  +  1 6
Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2  - 4ac
Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2  - 4ac Where do you recognized this formula from?
Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2  - 4ac Where do you recognized this formula from? It’s part of the  quadratic formula.
Discriminant -  used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2  - 4ac Where do you recognized this formula from? It’s part of the  quadratic formula. If d = 0, then there is exactly one solution x =  -b  +   b 2  - 4ac 2a
Discriminant -  used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2  - 4ac Where do you recognized this formula from? It’s part of the  quadratic formula. If d = 0, then there is exactly one solution If d > 0, then there are two solutions. x =  -b  +   b 2  - 4ac 2a
Discriminant -  used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2  - 4ac Where do you recognized this formula from? It’s part of the  quadratic formula. If d = 0, then there is exactly one solution If d > 0, then there are two solutions. If d < 0, then there are no real number solutions. x =  -b  +   b 2  - 4ac 2a
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1)
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4 d = 0
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4 d = 0 One solution
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically.
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically.
How many solutions does  x 2  - 2x + 1 = 0  have? d = b 2  - 4ac d = (-2) 2  - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically. Intersects x-axis only once.
How many solutions does  2x 2  - 2x + 1 = 0  have?
How many solutions does  2x 2  - 2x + 1 = 0  have? d = (-2) 2  - 4(2)(1)
How many solutions does  2x 2  - 2x + 1 = 0  have? d = (-2) 2  - 4(2)(1) d = 4 - 8 d = -4
How many solutions does  2x 2  - 2x + 1 = 0  have? d = (-2) 2  - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions
How many solutions does  2x 2  - 2x + 1 = 0  have? d = (-2) 2  - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions Graphically:
How many solutions does  2x 2  - 2x + 1 = 0  have? d = (-2) 2  - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions Graphically: Does not cross x-axis
How many solutions does  3x 2  - 2x - 1 = 0  have?
d = (-2) 2  - 4(3)(-1) How many solutions does  3x 2  - 2x - 1 = 0  have?
d = (-2) 2  - 4(3)(-1) How many solutions does  3x 2  - 2x - 1 = 0  have? d = 4 + 12 d = 16
d = (-2) 2  - 4(3)(-1) How many solutions does  3x 2  - 2x - 1 = 0  have? d = 4 + 12 d = 16 Two solutions
d = (-2) 2  - 4(3)(-1) How many solutions does  3x 2  - 2x - 1 = 0  have? d = 4 + 12 d = 16 Two solutions Graphically: Crosses x-axis twice

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Quadratic Formula Solver - Find Solutions to Quadratic Equations

  • 1. Quadratic Formula -b + b 2 - 4ac 2a a x 2 + b x + c = 0 Rewrite quadratic equation in standard form a substitute a , b , and c into formula. x =
  • 2. Solve: 3x 2 - 5 = 2x
  • 3. Step 1: Rewrite in standard form. Solve: 3x 2 - 5 = 2x
  • 4. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. 3x 2 - 2x - 5 = 0 a b c
  • 5. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. Step 2: Plug into formula and simplify. 3x 2 - 2x - 5 = 0 a b c
  • 6. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. Step 2: Plug into formula and simplify. 3x 2 - 2x - 5 = 0 a b c x = -(-2) + (-2) 2 - 4(3)(-5) 2(3) x = -b + b 2 - 4ac 2a
  • 7. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. Step 2: Plug into formula and simplify. 3x 2 - 2x - 5 = 0 a b c x = -(-2) + (-2) 2 - 4(3)(-5) 2(3) x = 2 + 64 6 x = -b + b 2 - 4ac 2a
  • 8. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. Step 2: Plug into formula and simplify. 3x 2 - 2x - 5 = 0 a b c x = -(-2) + (-2) 2 - 4(3)(-5) 2(3) x = 2 + 64 6 x = 2 + 8 6 x = -b + b 2 - 4ac 2a
  • 9. Solve: 3x 2 - 5 = 2x Step 1: Rewrite in standard form. Step 2: Plug into formula and simplify. = 5/3, -1 3x 2 - 2x - 5 = 0 a b c x = -(-2) + (-2) 2 - 4(3)(-5) 2(3) x = 2 + 64 6 x = 2 + 8 6 x = -b + b 2 - 4ac 2a
  • 10. Solve: 3x 2 = 5x - 2
  • 11. Solve: 3x 2 = 5x - 2 3x 2 - 5x + 2 = 0
  • 12. Solve: 3x 2 = 5x - 2 3x 2 - 5x + 2 = 0 x = -(-5) + (-5) 2 - 4(3)(2) 2(3)
  • 13.  
  • 14. Solve: 3x 2 = 5x - 2 3x 2 - 5x + 2 = 0 = 1, 2/3 x = -(-5) + (-5) 2 - 4(3)(2) 2(3) x = 5 + 1 6
  • 15. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2 - 4ac
  • 16. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2 - 4ac Where do you recognized this formula from?
  • 17. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 answers. d = b 2 - 4ac Where do you recognized this formula from? It’s part of the quadratic formula.
  • 18. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2 - 4ac Where do you recognized this formula from? It’s part of the quadratic formula. If d = 0, then there is exactly one solution x = -b + b 2 - 4ac 2a
  • 19. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2 - 4ac Where do you recognized this formula from? It’s part of the quadratic formula. If d = 0, then there is exactly one solution If d > 0, then there are two solutions. x = -b + b 2 - 4ac 2a
  • 20. Discriminant - used to determine whether the quadratic equation has 0, 1, or 2 real number solutions. d = b 2 - 4ac Where do you recognized this formula from? It’s part of the quadratic formula. If d = 0, then there is exactly one solution If d > 0, then there are two solutions. If d < 0, then there are no real number solutions. x = -b + b 2 - 4ac 2a
  • 21. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac
  • 22. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1)
  • 23. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4
  • 24. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4 d = 0
  • 25. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4 d = 0 One solution
  • 26. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically.
  • 27. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically.
  • 28. How many solutions does x 2 - 2x + 1 = 0 have? d = b 2 - 4ac d = (-2) 2 - 4(1)(1) d = 4 - 4 d = 0 One solution Let’s look at the equation graphically. Intersects x-axis only once.
  • 29. How many solutions does 2x 2 - 2x + 1 = 0 have?
  • 30. How many solutions does 2x 2 - 2x + 1 = 0 have? d = (-2) 2 - 4(2)(1)
  • 31. How many solutions does 2x 2 - 2x + 1 = 0 have? d = (-2) 2 - 4(2)(1) d = 4 - 8 d = -4
  • 32. How many solutions does 2x 2 - 2x + 1 = 0 have? d = (-2) 2 - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions
  • 33. How many solutions does 2x 2 - 2x + 1 = 0 have? d = (-2) 2 - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions Graphically:
  • 34. How many solutions does 2x 2 - 2x + 1 = 0 have? d = (-2) 2 - 4(2)(1) d = 4 - 8 d = -4 No Real Number Solutions Graphically: Does not cross x-axis
  • 35. How many solutions does 3x 2 - 2x - 1 = 0 have?
  • 36. d = (-2) 2 - 4(3)(-1) How many solutions does 3x 2 - 2x - 1 = 0 have?
  • 37. d = (-2) 2 - 4(3)(-1) How many solutions does 3x 2 - 2x - 1 = 0 have? d = 4 + 12 d = 16
  • 38. d = (-2) 2 - 4(3)(-1) How many solutions does 3x 2 - 2x - 1 = 0 have? d = 4 + 12 d = 16 Two solutions
  • 39. d = (-2) 2 - 4(3)(-1) How many solutions does 3x 2 - 2x - 1 = 0 have? d = 4 + 12 d = 16 Two solutions Graphically: Crosses x-axis twice