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Sections 2.1–2.2
         Derivatives and Rates of Changes
          The Derivative as a Function

                    V63.0121, Calculus I


                    February 9–12, 2009



Announcements
   Quiz 2 is next week: Covers up through 1.6
   Midterm is March 4/5: Covers up to 2.4 (next T/W)
Outline

   Rates of Change
      Tangent Lines
      Velocity
      Population growth
      Marginal costs

   The derivative, defined
      Derivatives of (some) power functions
      What does f tell you about f ?

   How can a function fail to be differentiable?

   Other notations

   The second derivative
The tangent problem

   Problem
   Given a curve and a point on the curve, find the slope of the line
   tangent to the curve at that point.
The tangent problem

   Problem
   Given a curve and a point on the curve, find the slope of the line
   tangent to the curve at that point.

   Example
   Find the slope of the line tangent to the curve y = x 2 at the point
   (2, 4).
Graphically and numerically

        y

                              x   m




    4




                       x
               2
Graphically and numerically

        y

                              x   m
                              3   5
    9




    4




                        x
               2    3
Graphically and numerically

         y

                              x     m
                              3     5
                              2.5   4.25


  6.25

    4




                       x
               2 2.5
Graphically and numerically

         y

                              x     m
                              3     5
                              2.5   4.25
                              2.1   4.1



  4.41
     4




                       x
               2.1
               2
Graphically and numerically

         y

                              x      m
                              3      5
                              2.5    4.25
                              2.1    4.1
                              2.01   4.01



4.0401
     4




                       x
              2.01
               2
Graphically and numerically

        y

                              x      m
                              3      5
                              2.5    4.25
                              2.1    4.1
                              2.01   4.01



    4

                              1      3
    1
                       x
            1   2
Graphically and numerically

         y

                              x      m
                              3      5
                              2.5    4.25
                              2.1    4.1
                              2.01   4.01



    4
                              1.5    3.5
  2.25                        1      3

                       x
             1.5 2
Graphically and numerically

         y

                              x      m
                              3      5
                              2.5    4.25
                              2.1    4.1
                              2.01   4.01


                              1.9    3.9
     4
  3.61
                              1.5    3.5
                              1      3

                       x
              1.9
                2
Graphically and numerically

         y

                              x      m
                              3      5
                              2.5    4.25
                              2.1    4.1
                              2.01   4.01

                              1.99   3.99
                              1.9    3.9
     4
3.9601
                              1.5    3.5
                              1      3

                       x
              1.99
                2
Graphically and numerically

         y

                                x       m
                                3       5
                                2.5     4.25
    9
                                2.1     4.1
                                2.01    4.01
  6.25                          limit   4
                                1.99    3.99
  4.41                          1.9     3.9
4.0401
     4
3.9601
  3.61
                                1.5     3.5
  2.25                          1       3
    1
                            x
             1 1.5 2.1 3
                 1.99
                  1.9 2.5
                  2.01
                    2
The tangent problem

   Problem
   Given a curve and a point on the curve, find the slope of the line
   tangent to the curve at that point.

   Example
   Find the slope of the line tangent to the curve y = x 2 at the point
   (2, 4).

   Upshot
   If the curve is given by y = f (x), and the point on the curve is
   (a, f (a)), then the slope of the tangent line is given by

                                        f (x) − f (a)
                       mtangent = lim
                                            x −a
                                  x→a
Velocity

   Problem
   Given the position function of a moving object, find the velocity of
   the object at a certain instant in time.

   Example
   Drop a ball off the roof of the Silver Center so that its height can
   be described by
                            h(t) = 50 − 10t 2
   where t is seconds after dropping it and h is meters above the
   ground. How fast is it falling one second after we drop it?
Velocity

   Problem
   Given the position function of a moving object, find the velocity of
   the object at a certain instant in time.

   Example
   Drop a ball off the roof of the Silver Center so that its height can
   be described by
                            h(t) = 50 − 10t 2
   where t is seconds after dropping it and h is meters above the
   ground. How fast is it falling one second after we drop it?

   Solution
   The answer is
                          (50 − 10t 2 ) − 40
                                             = −20.
                      lim
                               t −1
                      t→1
Numerical evidence




                                  h(t) − h(1)
                 t       vave =
                                     t −1
                         −30
                 2
                         −25
                 1.5
                         −21
                 1.1
                         −20.01
                 1.01
                         −20.001
                 1.001
Velocity

   Problem
   Given the position function of a moving object, find the velocity of
   the object at a certain instant in time.

   Example
   Drop a ball off the roof of the Silver Center so that its height can
   be described by
                            h(t) = 50 − 10t 2
   where t is seconds after dropping it and h is meters above the
   ground. How fast is it falling one second after we drop it?

   Solution
   The answer is
                          (50 − 10t 2 ) − 40
                                             = −20.
                      lim
                               t −1
                      t→1
Upshot
If the height function is given by h(t), the instantaneous velocity
at time t is given by

                             h(t + ∆t) − h(t)
                    v = lim
                                   ∆t
                        ∆t→0
Population growth

   Problem
   Given the population function of a group of organisms, find the
   rate of growth of the population at a particular instant.
Population growth

   Problem
   Given the population function of a group of organisms, find the
   rate of growth of the population at a particular instant.

   Example
   Suppose the population of fish in the East River is given by the
   function
                                        3e t
                              P(t) =
                                      1 + et
   where t is in years since 2000 and P is in millions of fish. Is the
   fish population growing fastest in 1990, 2000, or 2010? (Estimate
   numerically)?
Numerical evidence




                     P(−10 + 0.1) − P(−10)
           r1990 ≈                         ≈ 0.000136
                              0.1
Numerical evidence




                     P(−10 + 0.1) − P(−10)
           r1990 ≈                         ≈ 0.000136
                              0.1
                               P(0.1) − P(0)
                     r2000 ≈                 ≈ 0.75
                                    0.1
Numerical evidence




                     P(−10 + 0.1) − P(−10)
           r1990 ≈                         ≈ 0.000136
                              0.1
                               P(0.1) − P(0)
                     r2000 ≈                 ≈ 0.75
                                    0.1
                       P(10 + 0.1) − P(10)
            r2010 ≈                        ≈ 0.000136
                               0.1
Population growth

   Problem
   Given the population function of a group of organisms, find the
   rate of growth of the population at a particular instant.

   Example
   Suppose the population of fish in the East River is given by the
   function
                                        3e t
                              P(t) =
                                      1 + et
   where t is in years since 2000 and P is in millions of fish. Is the
   fish population growing fastest in 1990, 2000, or 2010? (Estimate
   numerically)?

   Solution
   The estimated rates of growth are 0.000136, 0.75, and 0.000136.
Upshot
The instantaneous population growth is given by

                         P(t + ∆t) − P(t)
                     lim
                               ∆t
                    ∆t→0
Marginal costs


   Problem
   Given the production cost of a good, find the marginal cost of
   production after having produced a certain quantity.
Marginal costs


   Problem
   Given the production cost of a good, find the marginal cost of
   production after having produced a certain quantity.

   Example
   Suppose the cost of producing q tons of rice on our paddy in a
   year is
                       C (q) = q 3 − 12q 2 + 60q
   We are currently producing 5 tons a year. Should we change that?
Comparisons




       q C (q) AC (q) = C (q)/q ∆C = C (q + 1) − C (q)
       4 112          28                 13
       5 125          25                 19
       6 144          24                 31
Marginal costs


   Problem
   Given the production cost of a good, find the marginal cost of
   production after having produced a certain quantity.

   Example
   Suppose the cost of producing q tons of rice on our paddy in a
   year is
                       C (q) = q 3 − 12q 2 + 60q
   We are currently producing 5 tons a year. Should we change that?

   Example
   If q = 5, then C = 125, ∆C = 19, while AC = 25. So we should
   produce more to lower average costs.
Upshot
   The incremental cost

                      ∆C = C (q + 1) − C (q)

   is useful, but depends on units.
Upshot
   The incremental cost

                      ∆C = C (q + 1) − C (q)

   is useful, but depends on units.
   The marginal cost after producing q given by

                               C (q + ∆q) − C (q)
                  MC = lim
                                      ∆q
                          ∆q→0

   is more useful since it’s unit-independent.
Outline

   Rates of Change
      Tangent Lines
      Velocity
      Population growth
      Marginal costs

   The derivative, defined
      Derivatives of (some) power functions
      What does f tell you about f ?

   How can a function fail to be differentiable?

   Other notations

   The second derivative
The definition



   All of these rates of change are found the same way!
The definition



   All of these rates of change are found the same way!
   Definition
   Let f be a function and a a point in the domain of f . If the limit

                                     f (a + h) − f (a)
                      f (a) = lim
                                             h
                               h→0

   exists, the function is said to be differentiable at a and f (a) is
   the derivative of f at a.
Derivative of the squaring function


   Example
   Suppose f (x) = x 2 . Use the definition of derivative to find f (a).
Derivative of the squaring function


   Example
   Suppose f (x) = x 2 . Use the definition of derivative to find f (a).

   Solution

                                                (a + h)2 − a2
                        f (a + h) − f (a)
           f (a) = lim                    = lim
                                h                     h
                   h→0                      h→0
                           2 + 2ah + h2 ) − a2       2ah + h2
                        (a
                 = lim                         = lim
                                  h                      h
                   h→0                           h→0
                 = lim (2a + h) = 2a.
                   h→0
What does f tell you about f ?



      If f is a function, we can compute the derivative f (x) at each
      point x where f is differentiable, and come up with another
      function, the derivative function.
      What can we say about this function f ?
          If f is decreasing on an interval, f is negative (well,
          nonpositive) on that interval
          If f is increasing on an interval, f is positive (well,
          nonnegative) on that interval
Outline

   Rates of Change
      Tangent Lines
      Velocity
      Population growth
      Marginal costs

   The derivative, defined
      Derivatives of (some) power functions
      What does f tell you about f ?

   How can a function fail to be differentiable?

   Other notations

   The second derivative
Differentiability is super-continuity

   Theorem
   If f is differentiable at a, then f is continuous at a.
Differentiability is super-continuity

   Theorem
   If f is differentiable at a, then f is continuous at a.

   Proof.
   We have
                                      f (x) − f (a)
             lim (f (x) − f (a)) = lim              · (x − a)
                                          x −a
             x→a                  x→a
                                      f (x) − f (a)
                                                    · lim (x − a)
                               = lim
                                          x −a
                                 x→a                  x→a
                               = f (a) · 0 = 0
Differentiability is super-continuity

   Theorem
   If f is differentiable at a, then f is continuous at a.

   Proof.
   We have
                                      f (x) − f (a)
             lim (f (x) − f (a)) = lim              · (x − a)
                                          x −a
             x→a                  x→a
                                      f (x) − f (a)
                                                    · lim (x − a)
                               = lim
                                          x −a
                                 x→a                  x→a
                               = f (a) · 0 = 0


   Note the proper use of the limit law: if the factors each have a
   limit at a, the limit of the product is the product of the limits.
How can a function fail to be differentiable?
Kinks




            f (x)




                      x
How can a function fail to be differentiable?
Kinks




            f (x)                         f (x)




                      x                           x
How can a function fail to be differentiable?
Kinks




            f (x)                         f (x)




                      x                           x
How can a function fail to be differentiable?
Cusps




            f (x)




                      x
How can a function fail to be differentiable?
Cusps




            f (x)                         f (x)




                      x                           x
How can a function fail to be differentiable?
Cusps




            f (x)                         f (x)




                      x                           x
How can a function fail to be differentiable?
Vertical Tangents




                    f (x)




                            x
How can a function fail to be differentiable?
Vertical Tangents




                    f (x)                 f (x)




                            x                     x
How can a function fail to be differentiable?
Vertical Tangents




                    f (x)                 f (x)




                            x                     x
How can a function fail to be differentiable?
Weird, Wild, Stuff




                    f (x)




                            x
How can a function fail to be differentiable?
Weird, Wild, Stuff




                    f (x)                 f (x)




                            x                     x
Outline

   Rates of Change
      Tangent Lines
      Velocity
      Population growth
      Marginal costs

   The derivative, defined
      Derivatives of (some) power functions
      What does f tell you about f ?

   How can a function fail to be differentiable?

   Other notations

   The second derivative
Notation



       Newtonian notation

                             f (x)     y (x)    y

       Leibnizian notation
                             dy      d          df
                                        f (x)
                             dx      dx         dx
   These all mean the same thing.
Meet the Mathematician: Isaac Newton




     English, 1643–1727
     Professor at Cambridge
     (England)
     Philosophiae Naturalis
     Principia Mathematica
     published 1687
Meet the Mathematician: Gottfried Leibniz




     German, 1646–1716
     Eminent philosopher as
     well as mathematician
     Contemporarily disgraced
     by the calculus priority
     dispute
Outline

   Rates of Change
      Tangent Lines
      Velocity
      Population growth
      Marginal costs

   The derivative, defined
      Derivatives of (some) power functions
      What does f tell you about f ?

   How can a function fail to be differentiable?

   Other notations

   The second derivative
The second derivative



   If f is a function, so is f , and we can seek its derivative.

                                 f = (f )

   It measures the rate of change of the rate of change!
The second derivative



   If f is a function, so is f , and we can seek its derivative.

                                 f = (f )

   It measures the rate of change of the rate of change! Leibnizian
   notation:
                       d 2y      d2           d 2f
                                     f (x)
                        dx 2    dx 2          dx 2
function, derivative, second derivative

                         y
                                          f (x) = x 2




                                          f (x) = 2x


                                          f (x) = 2
                                           x

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Lesson 7-8: Derivatives and Rates of Change, The Derivative as a function

  • 1. Sections 2.1–2.2 Derivatives and Rates of Changes The Derivative as a Function V63.0121, Calculus I February 9–12, 2009 Announcements Quiz 2 is next week: Covers up through 1.6 Midterm is March 4/5: Covers up to 2.4 (next T/W)
  • 2. Outline Rates of Change Tangent Lines Velocity Population growth Marginal costs The derivative, defined Derivatives of (some) power functions What does f tell you about f ? How can a function fail to be differentiable? Other notations The second derivative
  • 3. The tangent problem Problem Given a curve and a point on the curve, find the slope of the line tangent to the curve at that point.
  • 4. The tangent problem Problem Given a curve and a point on the curve, find the slope of the line tangent to the curve at that point. Example Find the slope of the line tangent to the curve y = x 2 at the point (2, 4).
  • 6. Graphically and numerically y x m 3 5 9 4 x 2 3
  • 7. Graphically and numerically y x m 3 5 2.5 4.25 6.25 4 x 2 2.5
  • 8. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 4.41 4 x 2.1 2
  • 9. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 2.01 4.01 4.0401 4 x 2.01 2
  • 10. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 2.01 4.01 4 1 3 1 x 1 2
  • 11. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 2.01 4.01 4 1.5 3.5 2.25 1 3 x 1.5 2
  • 12. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 2.01 4.01 1.9 3.9 4 3.61 1.5 3.5 1 3 x 1.9 2
  • 13. Graphically and numerically y x m 3 5 2.5 4.25 2.1 4.1 2.01 4.01 1.99 3.99 1.9 3.9 4 3.9601 1.5 3.5 1 3 x 1.99 2
  • 14. Graphically and numerically y x m 3 5 2.5 4.25 9 2.1 4.1 2.01 4.01 6.25 limit 4 1.99 3.99 4.41 1.9 3.9 4.0401 4 3.9601 3.61 1.5 3.5 2.25 1 3 1 x 1 1.5 2.1 3 1.99 1.9 2.5 2.01 2
  • 15. The tangent problem Problem Given a curve and a point on the curve, find the slope of the line tangent to the curve at that point. Example Find the slope of the line tangent to the curve y = x 2 at the point (2, 4). Upshot If the curve is given by y = f (x), and the point on the curve is (a, f (a)), then the slope of the tangent line is given by f (x) − f (a) mtangent = lim x −a x→a
  • 16. Velocity Problem Given the position function of a moving object, find the velocity of the object at a certain instant in time. Example Drop a ball off the roof of the Silver Center so that its height can be described by h(t) = 50 − 10t 2 where t is seconds after dropping it and h is meters above the ground. How fast is it falling one second after we drop it?
  • 17. Velocity Problem Given the position function of a moving object, find the velocity of the object at a certain instant in time. Example Drop a ball off the roof of the Silver Center so that its height can be described by h(t) = 50 − 10t 2 where t is seconds after dropping it and h is meters above the ground. How fast is it falling one second after we drop it? Solution The answer is (50 − 10t 2 ) − 40 = −20. lim t −1 t→1
  • 18. Numerical evidence h(t) − h(1) t vave = t −1 −30 2 −25 1.5 −21 1.1 −20.01 1.01 −20.001 1.001
  • 19. Velocity Problem Given the position function of a moving object, find the velocity of the object at a certain instant in time. Example Drop a ball off the roof of the Silver Center so that its height can be described by h(t) = 50 − 10t 2 where t is seconds after dropping it and h is meters above the ground. How fast is it falling one second after we drop it? Solution The answer is (50 − 10t 2 ) − 40 = −20. lim t −1 t→1
  • 20. Upshot If the height function is given by h(t), the instantaneous velocity at time t is given by h(t + ∆t) − h(t) v = lim ∆t ∆t→0
  • 21. Population growth Problem Given the population function of a group of organisms, find the rate of growth of the population at a particular instant.
  • 22. Population growth Problem Given the population function of a group of organisms, find the rate of growth of the population at a particular instant. Example Suppose the population of fish in the East River is given by the function 3e t P(t) = 1 + et where t is in years since 2000 and P is in millions of fish. Is the fish population growing fastest in 1990, 2000, or 2010? (Estimate numerically)?
  • 23. Numerical evidence P(−10 + 0.1) − P(−10) r1990 ≈ ≈ 0.000136 0.1
  • 24. Numerical evidence P(−10 + 0.1) − P(−10) r1990 ≈ ≈ 0.000136 0.1 P(0.1) − P(0) r2000 ≈ ≈ 0.75 0.1
  • 25. Numerical evidence P(−10 + 0.1) − P(−10) r1990 ≈ ≈ 0.000136 0.1 P(0.1) − P(0) r2000 ≈ ≈ 0.75 0.1 P(10 + 0.1) − P(10) r2010 ≈ ≈ 0.000136 0.1
  • 26. Population growth Problem Given the population function of a group of organisms, find the rate of growth of the population at a particular instant. Example Suppose the population of fish in the East River is given by the function 3e t P(t) = 1 + et where t is in years since 2000 and P is in millions of fish. Is the fish population growing fastest in 1990, 2000, or 2010? (Estimate numerically)? Solution The estimated rates of growth are 0.000136, 0.75, and 0.000136.
  • 27. Upshot The instantaneous population growth is given by P(t + ∆t) − P(t) lim ∆t ∆t→0
  • 28. Marginal costs Problem Given the production cost of a good, find the marginal cost of production after having produced a certain quantity.
  • 29. Marginal costs Problem Given the production cost of a good, find the marginal cost of production after having produced a certain quantity. Example Suppose the cost of producing q tons of rice on our paddy in a year is C (q) = q 3 − 12q 2 + 60q We are currently producing 5 tons a year. Should we change that?
  • 30. Comparisons q C (q) AC (q) = C (q)/q ∆C = C (q + 1) − C (q) 4 112 28 13 5 125 25 19 6 144 24 31
  • 31. Marginal costs Problem Given the production cost of a good, find the marginal cost of production after having produced a certain quantity. Example Suppose the cost of producing q tons of rice on our paddy in a year is C (q) = q 3 − 12q 2 + 60q We are currently producing 5 tons a year. Should we change that? Example If q = 5, then C = 125, ∆C = 19, while AC = 25. So we should produce more to lower average costs.
  • 32. Upshot The incremental cost ∆C = C (q + 1) − C (q) is useful, but depends on units.
  • 33. Upshot The incremental cost ∆C = C (q + 1) − C (q) is useful, but depends on units. The marginal cost after producing q given by C (q + ∆q) − C (q) MC = lim ∆q ∆q→0 is more useful since it’s unit-independent.
  • 34. Outline Rates of Change Tangent Lines Velocity Population growth Marginal costs The derivative, defined Derivatives of (some) power functions What does f tell you about f ? How can a function fail to be differentiable? Other notations The second derivative
  • 35. The definition All of these rates of change are found the same way!
  • 36. The definition All of these rates of change are found the same way! Definition Let f be a function and a a point in the domain of f . If the limit f (a + h) − f (a) f (a) = lim h h→0 exists, the function is said to be differentiable at a and f (a) is the derivative of f at a.
  • 37. Derivative of the squaring function Example Suppose f (x) = x 2 . Use the definition of derivative to find f (a).
  • 38. Derivative of the squaring function Example Suppose f (x) = x 2 . Use the definition of derivative to find f (a). Solution (a + h)2 − a2 f (a + h) − f (a) f (a) = lim = lim h h h→0 h→0 2 + 2ah + h2 ) − a2 2ah + h2 (a = lim = lim h h h→0 h→0 = lim (2a + h) = 2a. h→0
  • 39. What does f tell you about f ? If f is a function, we can compute the derivative f (x) at each point x where f is differentiable, and come up with another function, the derivative function. What can we say about this function f ? If f is decreasing on an interval, f is negative (well, nonpositive) on that interval If f is increasing on an interval, f is positive (well, nonnegative) on that interval
  • 40. Outline Rates of Change Tangent Lines Velocity Population growth Marginal costs The derivative, defined Derivatives of (some) power functions What does f tell you about f ? How can a function fail to be differentiable? Other notations The second derivative
  • 41. Differentiability is super-continuity Theorem If f is differentiable at a, then f is continuous at a.
  • 42. Differentiability is super-continuity Theorem If f is differentiable at a, then f is continuous at a. Proof. We have f (x) − f (a) lim (f (x) − f (a)) = lim · (x − a) x −a x→a x→a f (x) − f (a) · lim (x − a) = lim x −a x→a x→a = f (a) · 0 = 0
  • 43. Differentiability is super-continuity Theorem If f is differentiable at a, then f is continuous at a. Proof. We have f (x) − f (a) lim (f (x) − f (a)) = lim · (x − a) x −a x→a x→a f (x) − f (a) · lim (x − a) = lim x −a x→a x→a = f (a) · 0 = 0 Note the proper use of the limit law: if the factors each have a limit at a, the limit of the product is the product of the limits.
  • 44. How can a function fail to be differentiable? Kinks f (x) x
  • 45. How can a function fail to be differentiable? Kinks f (x) f (x) x x
  • 46. How can a function fail to be differentiable? Kinks f (x) f (x) x x
  • 47. How can a function fail to be differentiable? Cusps f (x) x
  • 48. How can a function fail to be differentiable? Cusps f (x) f (x) x x
  • 49. How can a function fail to be differentiable? Cusps f (x) f (x) x x
  • 50. How can a function fail to be differentiable? Vertical Tangents f (x) x
  • 51. How can a function fail to be differentiable? Vertical Tangents f (x) f (x) x x
  • 52. How can a function fail to be differentiable? Vertical Tangents f (x) f (x) x x
  • 53. How can a function fail to be differentiable? Weird, Wild, Stuff f (x) x
  • 54. How can a function fail to be differentiable? Weird, Wild, Stuff f (x) f (x) x x
  • 55. Outline Rates of Change Tangent Lines Velocity Population growth Marginal costs The derivative, defined Derivatives of (some) power functions What does f tell you about f ? How can a function fail to be differentiable? Other notations The second derivative
  • 56. Notation Newtonian notation f (x) y (x) y Leibnizian notation dy d df f (x) dx dx dx These all mean the same thing.
  • 57. Meet the Mathematician: Isaac Newton English, 1643–1727 Professor at Cambridge (England) Philosophiae Naturalis Principia Mathematica published 1687
  • 58. Meet the Mathematician: Gottfried Leibniz German, 1646–1716 Eminent philosopher as well as mathematician Contemporarily disgraced by the calculus priority dispute
  • 59. Outline Rates of Change Tangent Lines Velocity Population growth Marginal costs The derivative, defined Derivatives of (some) power functions What does f tell you about f ? How can a function fail to be differentiable? Other notations The second derivative
  • 60. The second derivative If f is a function, so is f , and we can seek its derivative. f = (f ) It measures the rate of change of the rate of change!
  • 61. The second derivative If f is a function, so is f , and we can seek its derivative. f = (f ) It measures the rate of change of the rate of change! Leibnizian notation: d 2y d2 d 2f f (x) dx 2 dx 2 dx 2
  • 62. function, derivative, second derivative y f (x) = x 2 f (x) = 2x f (x) = 2 x