SlideShare uma empresa Scribd logo
1 de 10
Baixar para ler offline
Section 4.2
Derivatives and the Shapes of Curves
V63.0121.041, Calculus I
New York University
November 15, 2010
Announcements
Quiz this week in recitation on 3.3, 3.4, 3.5, 3.7
There is class on November 24
Announcements
Quiz this week in recitation
on 3.3, 3.4, 3.5, 3.7
There is class on November
24
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 2 / 31
Objectives
Use the derivative of a
function to determine the
intervals along which the
function is increasing or
decreasing (The
Increasing/Decreasing Test)
Use the First Derivative Test
to classify critical points of a
function as local maxima,
local minima, or neither.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 3 / 31
Notes
Notes
Notes
1
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Objectives
Use the second derivative of
a function to determine the
intervals along which the
graph of the function is
concave up or concave down
(The Concavity Test)
Use the first and second
derivative of a function to
classify critical points as
local maxima or local
minima, when applicable
(The Second Derivative
Test)
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 4 / 31
Outline
Recall: The Mean Value Theorem
Monotonicity
The Increasing/Decreasing Test
Finding intervals of monotonicity
The First Derivative Test
Concavity
Definitions
Testing for Concavity
The Second Derivative Test
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 5 / 31
Recall: The Mean Value Theorem
Theorem (The Mean Value Theorem)
Let f be continuous on [a, b] and
differentiable on (a, b). Then
there exists a point c in (a, b)
such that
f (b) − f (a)
b − a
= f (c).
a
b
c
Another way to put this is that there exists a point c such that
f (b) = f (a) + f (c)(b − a)
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 6 / 31
Notes
Notes
Notes
2
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Why the MVT is the MITC
Most Important Theorem In Calculus!
Theorem
Let f = 0 on an interval (a, b). Then f is constant on (a, b).
Proof.
Pick any points x and y in (a, b) with x < y. Then f is continuous on
[x, y] and differentiable on (x, y). By MVT there exists a point z in (x, y)
such that
f (y) = f (x) + f (z)(y − x)
So f (y) = f (x). Since this is true for all x and y in (a, b), then f is
constant.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 7 / 31
Outline
Recall: The Mean Value Theorem
Monotonicity
The Increasing/Decreasing Test
Finding intervals of monotonicity
The First Derivative Test
Concavity
Definitions
Testing for Concavity
The Second Derivative Test
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 8 / 31
What does it mean for a function to be increasing?
Definition
A function f is increasing on (a, b) if
f (x) < f (y)
whenever x and y are two points in (a, b) with x < y.
An increasing function “preserves order.”
Write your own definition (mutatis mutandis) of decreasing,
nonincreasing, nondecreasing
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 9 / 31
Notes
Notes
Notes
3
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
The Increasing/Decreasing Test
Theorem (The Increasing/Decreasing Test)
If f > 0 on (a, b), then f is increasing on (a, b). If f < 0 on (a, b), then
f is decreasing on (a, b).
Proof.
It works the same as the last theorem. Pick two points x and y in (a, b)
with x < y. We must show f (x) < f (y). By MVT there exists a point c
in (x, y) such that
f (y) − f (x) = f (c)(y − x) > 0.
So f (y) > f (x).
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 10 / 31
Finding intervals of monotonicity I
Example
Find the intervals of monotonicity of f (x) = 2x − 5.
Solution
f (x) = 2 is always positive, so f is increasing on (−∞, ∞).
Example
Describe the monotonicity of f (x) = arctan(x).
Solution
Since f (x) =
1
1 + x2
is always positive, f (x) is always increasing.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 11 / 31
Finding intervals of monotonicity II
Example
Find the intervals of monotonicity of f (x) = x2
− 1.
Solution
f (x) = 2x, which is positive when x > 0 and negative when x is.
We can draw a number line:
f
f
−
0
0 +
So f is decreasing on (−∞, 0) and increasing on (0, ∞).
In fact we can say f is decreasing on (−∞, 0] and increasing on [0, ∞)
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 12 / 31
Notes
Notes
Notes
4
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Finding intervals of monotonicity III
Example
Find the intervals of monotonicity of f (x) = x2/3
(x + 2).
Solution
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 13 / 31
The First Derivative Test
Theorem (The First Derivative Test)
Let f be continuous on [a, b] and c a critical point of f in (a, b).
If f (x) > 0 on (a, c) and f (x) < 0 on (c, b), then c is a local
maximum.
If f (x) < 0 on (a, c) and f (x) > 0 on (c, b), then c is a local
minimum.
If f (x) has the same sign on (a, c) and (c, b), then c is not a local
extremum.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 14 / 31
Outline
Recall: The Mean Value Theorem
Monotonicity
The Increasing/Decreasing Test
Finding intervals of monotonicity
The First Derivative Test
Concavity
Definitions
Testing for Concavity
The Second Derivative Test
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 17 / 31
Notes
Notes
Notes
5
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Concavity
Definition
The graph of f is called concave up on an interval I if it lies above all its
tangents on I. The graph of f is called concave down on I if it lies below
all its tangents on I.
concave up concave down
We sometimes say a concave up graph “holds water” and a concave down
graph “spills water”.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 18 / 31
Inflection points indicate a change in concavity
Definition
A point P on a curve y = f (x) is called an inflection point if f is
continuous at P and the curve changes from concave upward to concave
downward at P (or vice versa).
concave
down
concave up
inflection point
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 19 / 31
Theorem (Concavity Test)
If f (x) > 0 for all x in an interval I, then the graph of f is concave
upward on I.
If f (x) < 0 for all x in I, then the graph of f is concave downward
on I.
Proof.
Suppose f (x) > 0 on I. This means f is increasing on I. Let a and x be
in I. The tangent line through (a, f (a)) is the graph of
L(x) = f (a) + f (a)(x − a)
By MVT, there exists a c between a and x with
f (x) = f (a) + f (c)(x − a)
Since f is increasing, f (x) > L(x).
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 20 / 31
Notes
Notes
Notes
6
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Finding Intervals of Concavity I
Example
Find the intervals of concavity for the graph of f (x) = x3
+ x2
.
Solution
We have f (x) = 3x2
+ 2x, so f (x) = 6x + 2.
This is negative when x < −1/3, positive when x > −1/3, and 0 when
x = −1/3
So f is concave down on (−∞, −1/3), concave up on (−1/3, ∞), and
has an inflection point at (−1/3, 2/27)
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 21 / 31
Finding Intervals of Concavity II
Example
Find the intervals of concavity of the graph of f (x) = x2/3
(x + 2).
Solution
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 22 / 31
The Second Derivative Test
Theorem (The Second Derivative Test)
Let f , f , and f be continuous on [a, b]. Let c be be a point in (a, b)
with f (c) = 0.
If f (c) < 0, then c is a local maximum.
If f (c) > 0, then c is a local minimum.
Remarks
If f (c) = 0, the second derivative test is inconclusive (this does not
mean c is neither; we just don’t know yet).
We look for zeroes of f and plug them into f to determine if their f
values are local extreme values.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 23 / 31
Notes
Notes
Notes
7
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Proof of the Second Derivative Test
Proof.
Suppose f (c) = 0 and f (c) > 0. Since f is continuous, f (x) > 0 for
all x sufficiently close to c. Since f = (f ) , we know f is increasing near
c. Since f (c) = 0 and f is increasing, f (x) < 0 for x close to c and less
than c, and f (x) > 0 for x close to c and more than c. This means f
changes sign from negative to positive at c, which means (by the First
Derivative Test) that f has a local minimum at c.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 24 / 31
Using the Second Derivative Test I
Example
Find the local extrema of f (x) = x3
+ x2
.
Solution
f (x) = 3x2
+ 2x = x(3x + 2) is 0 when x = 0 or x = −2/3.
Remember f (x) = 6x + 2
Since f (−2/3) = −2 < 0, −2/3 is a local maximum.
Since f (0) = 2 > 0, 0 is a local minimum.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 25 / 31
Using the Second Derivative Test II
Example
Find the local extrema of f (x) = x2/3
(x + 2)
Solution
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 26 / 31
Notes
Notes
Notes
8
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
Using the Second Derivative Test II: Graph
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 27 / 31
When the second derivative is zero
At inflection points c, if f is differentiable at c, then f (c) = 0
Is it necessarily true, though?
Consider these examples:
f (x) = x4
g(x) = −x4
h(x) = x3
All of them have critical points at zero with a second derivative of zero.
But the first has a local min at 0, the second has a local max at 0, and the
third has an inflection point at 0. This is why we say 2DT has nothing to
say when f (c) = 0.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 28 / 31
When first and second derivative are zero
function derivatives graph type
f (x) = x4
f (x) = 4x3, f (0) = 0
min
f (x) = 12x2, f (0) = 0
g(x) = −x4
g (x) = −4x3, g (0) = 0
max
g (x) = −12x2, g (0) = 0
h(x) = x3
h (x) = 3x2, h (0) = 0
infl.
h (x) = 6x, h (0) = 0
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 29 / 31
Notes
Notes
Notes
9
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
When the second derivative is zero
At inflection points c, if f is differentiable at c, then f (c) = 0
Is it necessarily true, though?
Consider these examples:
f (x) = x4
g(x) = −x4
h(x) = x3
All of them have critical points at zero with a second derivative of zero.
But the first has a local min at 0, the second has a local max at 0, and the
third has an inflection point at 0. This is why we say 2DT has nothing to
say when f (c) = 0.
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 30 / 31
Summary
Concepts: Mean Value Theorem, monotonicity, concavity
Facts: derivatives can detect monotonicity and concavity
Techniques for drawing curves: the Increasing/Decreasing Test and
the Concavity Test
Techniques for finding extrema: the First Derivative Test and the
Second Derivative Test
V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 31 / 31
Notes
Notes
Notes
10
Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010

Mais conteúdo relacionado

Mais procurados

The Application of Derivatives
The Application of DerivativesThe Application of Derivatives
The Application of Derivatives
divaprincess09
 
All Differentiation
All  DifferentiationAll  Differentiation
All Differentiation
mrmcdowall
 
Indefinite Integral
Indefinite IntegralIndefinite Integral
Indefinite Integral
JelaiAujero
 
Differentiation
DifferentiationDifferentiation
Differentiation
timschmitz
 
Vector differentiation, the ∇ operator,
Vector differentiation, the ∇ operator,Vector differentiation, the ∇ operator,
Vector differentiation, the ∇ operator,
Tarun Gehlot
 

Mais procurados (18)

Ch04
Ch04Ch04
Ch04
 
Basic mathematics differentiation application
Basic mathematics differentiation applicationBasic mathematics differentiation application
Basic mathematics differentiation application
 
Differentiation
DifferentiationDifferentiation
Differentiation
 
Ch02
Ch02Ch02
Ch02
 
The Application of Derivatives
The Application of DerivativesThe Application of Derivatives
The Application of Derivatives
 
All Differentiation
All  DifferentiationAll  Differentiation
All Differentiation
 
Lesson 21: Antiderivatives (slides)
Lesson 21: Antiderivatives (slides)Lesson 21: Antiderivatives (slides)
Lesson 21: Antiderivatives (slides)
 
Indefinite Integral
Indefinite IntegralIndefinite Integral
Indefinite Integral
 
Differentiation
DifferentiationDifferentiation
Differentiation
 
Vector differentiation, the ∇ operator,
Vector differentiation, the ∇ operator,Vector differentiation, the ∇ operator,
Vector differentiation, the ∇ operator,
 
Application of derivative
Application of derivativeApplication of derivative
Application of derivative
 
Lesson 8 the definite integrals
Lesson 8 the definite integralsLesson 8 the definite integrals
Lesson 8 the definite integrals
 
Lesson 10 techniques of integration
Lesson 10 techniques of integrationLesson 10 techniques of integration
Lesson 10 techniques of integration
 
Application of derivatives 2 maxima and minima
Application of derivatives 2  maxima and minimaApplication of derivatives 2  maxima and minima
Application of derivatives 2 maxima and minima
 
1519 differentiation-integration-02
1519 differentiation-integration-021519 differentiation-integration-02
1519 differentiation-integration-02
 
Introduction to differentiation
Introduction to differentiationIntroduction to differentiation
Introduction to differentiation
 
Lesson 22: Optimization II (Section 041 slides)
Lesson 22: Optimization II (Section 041 slides)Lesson 22: Optimization II (Section 041 slides)
Lesson 22: Optimization II (Section 041 slides)
 
PRESENTATION ON INTRODUCTION TO SEVERAL VARIABLES AND PARTIAL DERIVATIVES
PRESENTATION ON INTRODUCTION TO SEVERAL VARIABLES AND PARTIAL DERIVATIVES   PRESENTATION ON INTRODUCTION TO SEVERAL VARIABLES AND PARTIAL DERIVATIVES
PRESENTATION ON INTRODUCTION TO SEVERAL VARIABLES AND PARTIAL DERIVATIVES
 

Destaque (6)

Lesson 23: Antiderivatives (Section 041 handout)
Lesson 23: Antiderivatives (Section 041 handout)Lesson 23: Antiderivatives (Section 041 handout)
Lesson 23: Antiderivatives (Section 041 handout)
 
Lesson 27: Integration by Substitution (Section 021 handout)
Lesson 27: Integration by Substitution (Section 021 handout)Lesson 27: Integration by Substitution (Section 021 handout)
Lesson 27: Integration by Substitution (Section 021 handout)
 
Lesson 28: Integration by Substitution (worksheet solutions)
Lesson 28: Integration by Substitution (worksheet solutions)Lesson 28: Integration by Substitution (worksheet solutions)
Lesson 28: Integration by Substitution (worksheet solutions)
 
Lesson 25: Evaluating Definite Integrals (Section 041 handout)
Lesson 25: Evaluating Definite Integrals (Section 041 handout)Lesson 25: Evaluating Definite Integrals (Section 041 handout)
Lesson 25: Evaluating Definite Integrals (Section 041 handout)
 
Lesson 22: Optimization Problems (worksheet solutions)
Lesson 22: Optimization Problems (worksheet solutions)Lesson 22: Optimization Problems (worksheet solutions)
Lesson 22: Optimization Problems (worksheet solutions)
 
Lesson 21: Curve Sketching (Section 021 handout)
Lesson 21: Curve Sketching (Section 021 handout)Lesson 21: Curve Sketching (Section 021 handout)
Lesson 21: Curve Sketching (Section 021 handout)
 

Semelhante a Lesson 20: Derivatives and the Shape of Curves (Section 041 handout)

Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20  -derivatives_and_the_shape_of_curves_021_slidesLesson20  -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Matthew Leingang
 
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slidesLesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Mel Anthony Pepito
 
Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus
Mel Anthony Pepito
 
Lesson 21: Curve Sketching
Lesson 21: Curve SketchingLesson 21: Curve Sketching
Lesson 21: Curve Sketching
Matthew Leingang
 
Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)
Mel Anthony Pepito
 
Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)
Matthew Leingang
 

Semelhante a Lesson 20: Derivatives and the Shape of Curves (Section 041 handout) (20)

Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20  -derivatives_and_the_shape_of_curves_021_slidesLesson20  -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
 
Lesson 20: Derivatives and the Shape of Curves (Section 041 slides)
Lesson 20: Derivatives and the Shape of Curves (Section 041 slides)Lesson 20: Derivatives and the Shape of Curves (Section 041 slides)
Lesson 20: Derivatives and the Shape of Curves (Section 041 slides)
 
Lesson 19: The Mean Value Theorem (Section 021 slides)
Lesson 19: The Mean Value Theorem (Section 021 slides)Lesson 19: The Mean Value Theorem (Section 021 slides)
Lesson 19: The Mean Value Theorem (Section 021 slides)
 
Lesson 19: The Mean Value Theorem (Section 041 handout)
Lesson 19: The Mean Value Theorem (Section 041 handout)Lesson 19: The Mean Value Theorem (Section 041 handout)
Lesson 19: The Mean Value Theorem (Section 041 handout)
 
Lesson 19: The Mean Value Theorem (Section 021 handout)
Lesson 19: The Mean Value Theorem (Section 021 handout)Lesson 19: The Mean Value Theorem (Section 021 handout)
Lesson 19: The Mean Value Theorem (Section 021 handout)
 
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slidesLesson20 -derivatives_and_the_shape_of_curves_021_slides
Lesson20 -derivatives_and_the_shape_of_curves_021_slides
 
Lesson 23: Antiderivatives (Section 021 handout)
Lesson 23: Antiderivatives (Section 021 handout)Lesson 23: Antiderivatives (Section 021 handout)
Lesson 23: Antiderivatives (Section 021 handout)
 
Lesson 18: Maximum and Minimum Values (Section 021 handout)
Lesson 18: Maximum and Minimum Values (Section 021 handout)Lesson 18: Maximum and Minimum Values (Section 021 handout)
Lesson 18: Maximum and Minimum Values (Section 021 handout)
 
Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus Lesson 27: The Fundamental Theorem of Calculus
Lesson 27: The Fundamental Theorem of Calculus
 
Lesson 21: Curve Sketching (Section 041 handout)
Lesson 21: Curve Sketching (Section 041 handout)Lesson 21: Curve Sketching (Section 041 handout)
Lesson 21: Curve Sketching (Section 041 handout)
 
Lesson 20: Derivatives and the Shapes of Curves (slides)
Lesson 20: Derivatives and the Shapes of Curves (slides)Lesson 20: Derivatives and the Shapes of Curves (slides)
Lesson 20: Derivatives and the Shapes of Curves (slides)
 
Lesson 20: Derivatives and the Shapes of Curves (slides)
Lesson 20: Derivatives and the Shapes of Curves (slides)Lesson 20: Derivatives and the Shapes of Curves (slides)
Lesson 20: Derivatives and the Shapes of Curves (slides)
 
Lesson 22: Optimization (Section 021 handout)
Lesson 22: Optimization (Section 021 handout)Lesson 22: Optimization (Section 021 handout)
Lesson 22: Optimization (Section 021 handout)
 
Lesson 22: Optimization II (Section 021 slides)
Lesson 22: Optimization II (Section 021 slides)Lesson 22: Optimization II (Section 021 slides)
Lesson 22: Optimization II (Section 021 slides)
 
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
 
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
Lesson 26: The Fundamental Theorem of Calculus (Section 021 slides)
 
Lesson 21: Curve Sketching
Lesson 21: Curve SketchingLesson 21: Curve Sketching
Lesson 21: Curve Sketching
 
Lesson 21: Curve Sketching
Lesson 21: Curve SketchingLesson 21: Curve Sketching
Lesson 21: Curve Sketching
 
Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)
 
Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)Lesson 5: Continuity (Section 41 slides)
Lesson 5: Continuity (Section 41 slides)
 

Mais de Matthew Leingang

Mais de Matthew Leingang (20)

Making Lesson Plans
Making Lesson PlansMaking Lesson Plans
Making Lesson Plans
 
Streamlining assessment, feedback, and archival with auto-multiple-choice
Streamlining assessment, feedback, and archival with auto-multiple-choiceStreamlining assessment, feedback, and archival with auto-multiple-choice
Streamlining assessment, feedback, and archival with auto-multiple-choice
 
Electronic Grading of Paper Assessments
Electronic Grading of Paper AssessmentsElectronic Grading of Paper Assessments
Electronic Grading of Paper Assessments
 
Lesson 27: Integration by Substitution (slides)
Lesson 27: Integration by Substitution (slides)Lesson 27: Integration by Substitution (slides)
Lesson 27: Integration by Substitution (slides)
 
Lesson 26: The Fundamental Theorem of Calculus (slides)
Lesson 26: The Fundamental Theorem of Calculus (slides)Lesson 26: The Fundamental Theorem of Calculus (slides)
Lesson 26: The Fundamental Theorem of Calculus (slides)
 
Lesson 26: The Fundamental Theorem of Calculus (slides)
Lesson 26: The Fundamental Theorem of Calculus (slides)Lesson 26: The Fundamental Theorem of Calculus (slides)
Lesson 26: The Fundamental Theorem of Calculus (slides)
 
Lesson 27: Integration by Substitution (handout)
Lesson 27: Integration by Substitution (handout)Lesson 27: Integration by Substitution (handout)
Lesson 27: Integration by Substitution (handout)
 
Lesson 26: The Fundamental Theorem of Calculus (handout)
Lesson 26: The Fundamental Theorem of Calculus (handout)Lesson 26: The Fundamental Theorem of Calculus (handout)
Lesson 26: The Fundamental Theorem of Calculus (handout)
 
Lesson 25: Evaluating Definite Integrals (slides)
Lesson 25: Evaluating Definite Integrals (slides)Lesson 25: Evaluating Definite Integrals (slides)
Lesson 25: Evaluating Definite Integrals (slides)
 
Lesson 25: Evaluating Definite Integrals (handout)
Lesson 25: Evaluating Definite Integrals (handout)Lesson 25: Evaluating Definite Integrals (handout)
Lesson 25: Evaluating Definite Integrals (handout)
 
Lesson 24: Areas and Distances, The Definite Integral (handout)
Lesson 24: Areas and Distances, The Definite Integral (handout)Lesson 24: Areas and Distances, The Definite Integral (handout)
Lesson 24: Areas and Distances, The Definite Integral (handout)
 
Lesson 24: Areas and Distances, The Definite Integral (slides)
Lesson 24: Areas and Distances, The Definite Integral (slides)Lesson 24: Areas and Distances, The Definite Integral (slides)
Lesson 24: Areas and Distances, The Definite Integral (slides)
 
Lesson 23: Antiderivatives (slides)
Lesson 23: Antiderivatives (slides)Lesson 23: Antiderivatives (slides)
Lesson 23: Antiderivatives (slides)
 
Lesson 23: Antiderivatives (slides)
Lesson 23: Antiderivatives (slides)Lesson 23: Antiderivatives (slides)
Lesson 23: Antiderivatives (slides)
 
Lesson 22: Optimization Problems (slides)
Lesson 22: Optimization Problems (slides)Lesson 22: Optimization Problems (slides)
Lesson 22: Optimization Problems (slides)
 
Lesson 22: Optimization Problems (handout)
Lesson 22: Optimization Problems (handout)Lesson 22: Optimization Problems (handout)
Lesson 22: Optimization Problems (handout)
 
Lesson 21: Curve Sketching (slides)
Lesson 21: Curve Sketching (slides)Lesson 21: Curve Sketching (slides)
Lesson 21: Curve Sketching (slides)
 
Lesson 21: Curve Sketching (handout)
Lesson 21: Curve Sketching (handout)Lesson 21: Curve Sketching (handout)
Lesson 21: Curve Sketching (handout)
 
Lesson 20: Derivatives and the Shapes of Curves (handout)
Lesson 20: Derivatives and the Shapes of Curves (handout)Lesson 20: Derivatives and the Shapes of Curves (handout)
Lesson 20: Derivatives and the Shapes of Curves (handout)
 
Lesson 19: The Mean Value Theorem (slides)
Lesson 19: The Mean Value Theorem (slides)Lesson 19: The Mean Value Theorem (slides)
Lesson 19: The Mean Value Theorem (slides)
 

Lesson 20: Derivatives and the Shape of Curves (Section 041 handout)

  • 1. Section 4.2 Derivatives and the Shapes of Curves V63.0121.041, Calculus I New York University November 15, 2010 Announcements Quiz this week in recitation on 3.3, 3.4, 3.5, 3.7 There is class on November 24 Announcements Quiz this week in recitation on 3.3, 3.4, 3.5, 3.7 There is class on November 24 V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 2 / 31 Objectives Use the derivative of a function to determine the intervals along which the function is increasing or decreasing (The Increasing/Decreasing Test) Use the First Derivative Test to classify critical points of a function as local maxima, local minima, or neither. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 3 / 31 Notes Notes Notes 1 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 2. Objectives Use the second derivative of a function to determine the intervals along which the graph of the function is concave up or concave down (The Concavity Test) Use the first and second derivative of a function to classify critical points as local maxima or local minima, when applicable (The Second Derivative Test) V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 4 / 31 Outline Recall: The Mean Value Theorem Monotonicity The Increasing/Decreasing Test Finding intervals of monotonicity The First Derivative Test Concavity Definitions Testing for Concavity The Second Derivative Test V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 5 / 31 Recall: The Mean Value Theorem Theorem (The Mean Value Theorem) Let f be continuous on [a, b] and differentiable on (a, b). Then there exists a point c in (a, b) such that f (b) − f (a) b − a = f (c). a b c Another way to put this is that there exists a point c such that f (b) = f (a) + f (c)(b − a) V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 6 / 31 Notes Notes Notes 2 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 3. Why the MVT is the MITC Most Important Theorem In Calculus! Theorem Let f = 0 on an interval (a, b). Then f is constant on (a, b). Proof. Pick any points x and y in (a, b) with x < y. Then f is continuous on [x, y] and differentiable on (x, y). By MVT there exists a point z in (x, y) such that f (y) = f (x) + f (z)(y − x) So f (y) = f (x). Since this is true for all x and y in (a, b), then f is constant. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 7 / 31 Outline Recall: The Mean Value Theorem Monotonicity The Increasing/Decreasing Test Finding intervals of monotonicity The First Derivative Test Concavity Definitions Testing for Concavity The Second Derivative Test V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 8 / 31 What does it mean for a function to be increasing? Definition A function f is increasing on (a, b) if f (x) < f (y) whenever x and y are two points in (a, b) with x < y. An increasing function “preserves order.” Write your own definition (mutatis mutandis) of decreasing, nonincreasing, nondecreasing V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 9 / 31 Notes Notes Notes 3 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 4. The Increasing/Decreasing Test Theorem (The Increasing/Decreasing Test) If f > 0 on (a, b), then f is increasing on (a, b). If f < 0 on (a, b), then f is decreasing on (a, b). Proof. It works the same as the last theorem. Pick two points x and y in (a, b) with x < y. We must show f (x) < f (y). By MVT there exists a point c in (x, y) such that f (y) − f (x) = f (c)(y − x) > 0. So f (y) > f (x). V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 10 / 31 Finding intervals of monotonicity I Example Find the intervals of monotonicity of f (x) = 2x − 5. Solution f (x) = 2 is always positive, so f is increasing on (−∞, ∞). Example Describe the monotonicity of f (x) = arctan(x). Solution Since f (x) = 1 1 + x2 is always positive, f (x) is always increasing. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 11 / 31 Finding intervals of monotonicity II Example Find the intervals of monotonicity of f (x) = x2 − 1. Solution f (x) = 2x, which is positive when x > 0 and negative when x is. We can draw a number line: f f − 0 0 + So f is decreasing on (−∞, 0) and increasing on (0, ∞). In fact we can say f is decreasing on (−∞, 0] and increasing on [0, ∞) V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 12 / 31 Notes Notes Notes 4 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 5. Finding intervals of monotonicity III Example Find the intervals of monotonicity of f (x) = x2/3 (x + 2). Solution V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 13 / 31 The First Derivative Test Theorem (The First Derivative Test) Let f be continuous on [a, b] and c a critical point of f in (a, b). If f (x) > 0 on (a, c) and f (x) < 0 on (c, b), then c is a local maximum. If f (x) < 0 on (a, c) and f (x) > 0 on (c, b), then c is a local minimum. If f (x) has the same sign on (a, c) and (c, b), then c is not a local extremum. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 14 / 31 Outline Recall: The Mean Value Theorem Monotonicity The Increasing/Decreasing Test Finding intervals of monotonicity The First Derivative Test Concavity Definitions Testing for Concavity The Second Derivative Test V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 17 / 31 Notes Notes Notes 5 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 6. Concavity Definition The graph of f is called concave up on an interval I if it lies above all its tangents on I. The graph of f is called concave down on I if it lies below all its tangents on I. concave up concave down We sometimes say a concave up graph “holds water” and a concave down graph “spills water”. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 18 / 31 Inflection points indicate a change in concavity Definition A point P on a curve y = f (x) is called an inflection point if f is continuous at P and the curve changes from concave upward to concave downward at P (or vice versa). concave down concave up inflection point V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 19 / 31 Theorem (Concavity Test) If f (x) > 0 for all x in an interval I, then the graph of f is concave upward on I. If f (x) < 0 for all x in I, then the graph of f is concave downward on I. Proof. Suppose f (x) > 0 on I. This means f is increasing on I. Let a and x be in I. The tangent line through (a, f (a)) is the graph of L(x) = f (a) + f (a)(x − a) By MVT, there exists a c between a and x with f (x) = f (a) + f (c)(x − a) Since f is increasing, f (x) > L(x). V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 20 / 31 Notes Notes Notes 6 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 7. Finding Intervals of Concavity I Example Find the intervals of concavity for the graph of f (x) = x3 + x2 . Solution We have f (x) = 3x2 + 2x, so f (x) = 6x + 2. This is negative when x < −1/3, positive when x > −1/3, and 0 when x = −1/3 So f is concave down on (−∞, −1/3), concave up on (−1/3, ∞), and has an inflection point at (−1/3, 2/27) V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 21 / 31 Finding Intervals of Concavity II Example Find the intervals of concavity of the graph of f (x) = x2/3 (x + 2). Solution V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 22 / 31 The Second Derivative Test Theorem (The Second Derivative Test) Let f , f , and f be continuous on [a, b]. Let c be be a point in (a, b) with f (c) = 0. If f (c) < 0, then c is a local maximum. If f (c) > 0, then c is a local minimum. Remarks If f (c) = 0, the second derivative test is inconclusive (this does not mean c is neither; we just don’t know yet). We look for zeroes of f and plug them into f to determine if their f values are local extreme values. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 23 / 31 Notes Notes Notes 7 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 8. Proof of the Second Derivative Test Proof. Suppose f (c) = 0 and f (c) > 0. Since f is continuous, f (x) > 0 for all x sufficiently close to c. Since f = (f ) , we know f is increasing near c. Since f (c) = 0 and f is increasing, f (x) < 0 for x close to c and less than c, and f (x) > 0 for x close to c and more than c. This means f changes sign from negative to positive at c, which means (by the First Derivative Test) that f has a local minimum at c. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 24 / 31 Using the Second Derivative Test I Example Find the local extrema of f (x) = x3 + x2 . Solution f (x) = 3x2 + 2x = x(3x + 2) is 0 when x = 0 or x = −2/3. Remember f (x) = 6x + 2 Since f (−2/3) = −2 < 0, −2/3 is a local maximum. Since f (0) = 2 > 0, 0 is a local minimum. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 25 / 31 Using the Second Derivative Test II Example Find the local extrema of f (x) = x2/3 (x + 2) Solution V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 26 / 31 Notes Notes Notes 8 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 9. Using the Second Derivative Test II: Graph V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 27 / 31 When the second derivative is zero At inflection points c, if f is differentiable at c, then f (c) = 0 Is it necessarily true, though? Consider these examples: f (x) = x4 g(x) = −x4 h(x) = x3 All of them have critical points at zero with a second derivative of zero. But the first has a local min at 0, the second has a local max at 0, and the third has an inflection point at 0. This is why we say 2DT has nothing to say when f (c) = 0. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 28 / 31 When first and second derivative are zero function derivatives graph type f (x) = x4 f (x) = 4x3, f (0) = 0 min f (x) = 12x2, f (0) = 0 g(x) = −x4 g (x) = −4x3, g (0) = 0 max g (x) = −12x2, g (0) = 0 h(x) = x3 h (x) = 3x2, h (0) = 0 infl. h (x) = 6x, h (0) = 0 V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 29 / 31 Notes Notes Notes 9 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010
  • 10. When the second derivative is zero At inflection points c, if f is differentiable at c, then f (c) = 0 Is it necessarily true, though? Consider these examples: f (x) = x4 g(x) = −x4 h(x) = x3 All of them have critical points at zero with a second derivative of zero. But the first has a local min at 0, the second has a local max at 0, and the third has an inflection point at 0. This is why we say 2DT has nothing to say when f (c) = 0. V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 30 / 31 Summary Concepts: Mean Value Theorem, monotonicity, concavity Facts: derivatives can detect monotonicity and concavity Techniques for drawing curves: the Increasing/Decreasing Test and the Concavity Test Techniques for finding extrema: the First Derivative Test and the Second Derivative Test V63.0121.041, Calculus I (NYU) Section 4.2 The Shapes of Curves November 15, 2010 31 / 31 Notes Notes Notes 10 Section 4.2 : The Shapes of CurvesV63.0121.041, Calculus I November 15, 2010