Determine the zeroes of dy if y=(4x+2)/(2x-4) . Solution y = (4x+2)/(2x-4) To determine the zeros of dy ,we difrentiate the function and set dy/dx to zero and solve for x. y = (4x+2)/(2x-4) = 2+ [4x+2-2(2x-4)]/(2x-4) y\' = (2X)\' +[10/(2X-4)]\' y\' = 0 + 10(-2)/(2x-4)^2 = -20/(x-4) ^2. Therefore y\' = 0 implies -20/(x-4) = 0. This requires x = + or - infinity. Or y\' = 0 can not be for any finite values of x.x..