a parabola opens downward with y intercept of (0,1) and x intercept is (2,0) and the vertex is on the line y=2. vertex is (x,2) find x
Solution
general equation of a downward open parabola is ;Â where (X1,Y1) refers to the vertex point.
Given Y1 = 2 ; and points (0,1) and (2,0) lie on the parabola.
Substituting (0,1): x1^2 = - 4a(1-2)
=> x1^2 = 4a ;
Substituting (2,0): (2 - x1)^2 = -4a(0-2)
=> 4 + x1^2 - 4x1 = 8a (but 4a = x1^2)
=> 4 +Â x1^2 - 4x1 = 2(x1^2)
=> x1^2 + 4x1 - 4 = 0 ;
solving for x1, we get x1 =
.
a parabola opens downward with y intercept of (0-1) and x intercept is.docx
1. a parabola opens downward with y intercept of (0,1) and x intercept is (2,0) and the vertex is on
the line y=2. vertex is (x,2) find x
Solution
general equation of a downward open parabola is ;Â where (X1,Y1) refers to the vertex
point.
Given Y1 = 2 ; and points (0,1) and (2,0) lie on the parabola.
Substituting (0,1): x1^2 = - 4a(1-2)
=> x1^2 = 4a ;
Substituting (2,0): (2 - x1)^2 = -4a(0-2)
=> 4 + x1^2 - 4x1 = 8a (but 4a = x1^2)
=> 4 +Â x1^2 - 4x1 = 2(x1^2)
=> x1^2 + 4x1 - 4 = 0 ;
solving for x1, we get x1 =
