A mass on a string of unknown length oscillates as a pendulum with a p.docx

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A mass on a string of unknown length oscillates as a pendulum with a period of 4.9 s . Parts A to D are independent questions, each referring to the initial situation. Part B What is the period if the string length is doubled? Part C What is the period if the string length is halved? Part D What is the period if the amplitude is doubled? Solution Time period of a pendulum T = 2*pi*sqrt(L/g) part(B) (T2/T1)^2= L2/L1 if L2 = 2*L1 (T2/T1)^2 = 2 T2 = T1*sqrt2 T2 = 4.9*sqrt2 time period T2 = 6.9 s ====================== part C if L2 = L1/2 (T2/T1)^2 = 1/2 T2 = T1/sqrt2 T2 = 4.9/sqrt2 = 4.9/1.41 T2 = 3.5 s ============================== part D time period is independent of amplitude time period remains same 4.9 s .

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A photographer works part-time in a shopping center, 2 hours per day, 4 days per week. On the average,six customers arrive each hour,and the arrivals appear to occur independently of one another. Twenty minutes after she arrives one day,the photographer wonders what the chances are that exactly one customer will arrive during the next 15 minutes.Find this prbability 1) if two customers just arrived within the first 20 minutes and 2)if no customers have come into the shop yet on this particular day. Solution There were a number of loose ends from the first two series, and changes in the third series, that were explained off by a text intro to the first show of Series III. This was done in the form of scrolling text across outer space, in a parody of the introductions to the Star Wars movies. The loose ends included the return of Kryten, Lister being pregnant, delivering twins Jim and Bexley, who grow up in a matter of days, then wind up in the parallel universe with the female version of Lister. The regular cast changed for Series III: Robert Llewellyn came in as Kryten, and Hattie Hayridge replaced the departing Lovett. [26] Craig Charles, Chris Barrie and Danny John-Jules remained as Lister, Rimmer and Cat respectively. [27] The character of Kryten was originally intended as a one-off appearance in the series-two episode \"Kryten\", but had returned mainly to broaden the story potential. The show was becoming difficult to write for. At the insistence of Naylor, Kryten returned to complete the team. [28] They had approached David Ross with the intention of bringing him back to play the regular role of Kryten. Ross, however, was in a stage play Flea In Her Ear and was not available, so they went to see Robert Llewellyn. Llewellyn was also in a stage show called Mammon: Robot Born of Woman , playing a robot. They saw his performance and were impressedhis book actually began with another book .

A photographer works part-time in a shopping center- 2 hours per day-.docx

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Consider the following definitions for linked lists for problems 6 through 9. typedef int elementType; class LinkedList { public: LinkedList(); //other member functions . . . private: struct node { elementType data; node * next; }; node * first; }; 9. Write the method of the LinkedList class to calculate and return the range of the data values stored in an unsorted singly linked list. (Note: range = largest value â€“ smallest value). Note: If list is empty return 0. int LinkedList::range() Solution //function to calculate range in linked list int LinkedList::range() { elementType smallest,largest,range; // point to the beginning of the list node* ptr=first; //if list empty, return 0 if(ptr==NULL) return 0; //list is not empty //assume element in the beginning of the list is smallest smallest==first->data; //start from second element in list ptr=ptr->next; //traverse the list till end while(ptr!=NULL) { //compare smallest with the items in the list if(ptr->data<smallest) { //if any element is less than smallest //replace the smallest with that element smallest=ptr->data; } //move to the next node ptr=ptr->next; } largest=first->data; ptr=first->next; while(ptr!=NULL) { if(ptr->data>largest) { largest=ptr->data; } ptr=ptr->next; } //find range and return it range=largest-smallest; return range; } .

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Consider the following chemical compounds. Classify each as either an IONIC or a MOLECULAR compound. ionic/ molecularÂ Â sodium chloride ionic/ molecularÂ Â carbon monoxide ionic /molecularÂ Â barium selenide ionic /molecularÂ Â strontium selenide ionic/ molecularÂ Â arsenic monoxide ionic /molecularÂ Â silicon monoxide Solution sodium chloride(NaCl) = ionic compound carbon monoxide(CO2) = molecular compound barium selenide (BaSe) = ionic compound strontium selenide (srSe) = ionic compound arsenic monoxide (AsO) = ionic compound silicon monoxide (SiO) = molecular compound if the compound is formed by the combination of meta,non-metal with electronegativity difference greaterthan 1.6 gives formation of ionic compound. and if,both are non-metals gives formation of molecular compound. .

Consider the following chemical compounds- Classify each as either an.docx

kaseya1

Consider the plane R 2 and consider any two lines that pass through the origin. Are these lines subspaces of the plane? Are they isomorphic? Are they \"the same\"? Clearly the \"look different\", but mathematically, do they behave the same structurally? Thank you, Please show work Solution 1 . lines cannot be subspaces , they can be made boundaries of a sub space,In rough terms we can call them a subspaces of zero area. 2 . for two graphs to be isomorphic,the relation between output of one graph and input of the other graph must be a bijection.in easy terms for every value of input taken for 2nd graph from the output values of the first, there should be a unique output.as it is a real plane and both are straight lines passiing through orign,both lines are isomorphic 3 . They are absolutely not same but the behaviour will same as i)they have no intercepts ii) they have constant slopes these two propertes make them structurally similar .

Consider the plane R2 and consider any two lines that pass through the.docx

kaseya1

Consider the following statements about the investment in working capital in a capital budgeting analysis: I. Working capital often increases as the result of higher balances in accounts receivable or inventory necessary to support a project. II. Working capital increases are sources of cash and should be included in a discounted-cash-flow analysis. III. The time 0 cash investment in working capital is included in a discounted-cash-flow analysis as a cash outflow. Which of the above statements is (are) correct? I only. II only. III only. I and II. I and III. Solution Option-E:- I & III is the correct answer ..100% sure . .

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kaseya1

Consider the following method definitions intended to find the smallest integer value in the ArrayList parameter. You may assume that the array list contains at least one value. I. public static int findSmallest(ArrayList<Integerâ€º nums) { Integer small = nums.get(0); for (int i = 1; i < nums.size(); i++) { Integer tempSmall = nums.get(i); if (tempSmall.compareTo(small) < 0) { small = tempSmall; } } return small.intValue(); } II. public static int findSmallest(ArrayList<Integer> nums) { Integer small = nums.get(0); for (int i = 1; i < nums.size(); i++) { Integer tempSmall = nums.get(i); if (tempSmall.intValue() < small.intValue()) { small = tempSmall; } } return small.intValue(); } III. public static int findSmallest(ArrayList<Integer> nums) { int small = (nums.get(0)).intValue(); for (int i= 1; i < nums.size(); i++) { int tempSmall = (nums.get(i)).intValue(): if (tempSmall < small) { small = tempSmall; } } return small; } Which of the method definitions above will work as intended? a . I o n l y b . I I o n l y c . I and II only d . II and III only e . I, II, and III Solution a. I only II and III shows error .

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A mass on a string of unknown length oscillates as a pendulum with a p.docx