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Experiment 4 - Testing of Materials in Tension Object: The object of this experiment is to measure the tensile properties of two polymeric materials, steel and aluminum at a constant strain rate on the Tension testing machine. Background: For structural applications of materials such as bridges, pressure vessels, ships, and automobiles, the tensile properties of the metal material set the criteria for a safe design. Polymeric materials are being used more and more in structural applications, particularly in automobiles and pressure vessels. New applications emerge as designers become aware of the differences in the properties of metals and polymers and take full advantage of them. The analyses of structures using metals or plastics require that the data be available. Stress-Strain: The tensile properties of a material are obtained by pulling a specimen of known geometry apart at a fixed rate of straining until it breaks or stretches to the machines limit. It is useful to define the load per unit area (stress) as a parameter rather than load to avoid the confusion that would arise from the fact that the load and the change in length are dependent on the cross-sectional area and original length of the specimen. The stress, however, changes during the test for two reasons: the load increases and the cross-sectional area decreases as the specimen gets longer. Therefore, the stress can be calculated by two formulae which are distinguished as engineering stress and true stress, respectively. (1) = P/Ao= Engineering Stress (lbs/in 2 or psi) P = load (lbs) Ao= original cross-sectional area (in 2) (2) T= P/Ai = True Stress Ai = instantaneous cross-sectional area (in 2) Likewise, the elongation is normalized per unit length of specimen and is called strain. The strain may be based on the original length or the instantaneous length such that (3) =(lf - lo)/ lo = l / lo = Engineering Strain, where lf= final gage length (in) lo= original gage length (in) (4) T= ln ( li / lo ) = ln (1 +) = True Strain, where li = instantaneous gage length (in) ln = natural logarithm For a small elongation the engineering strain is very close to the true strain when l=1.2 lo, then = 0.2 and T= ln 1.2 = 0.182. The engineering stress is related to the true stress by (5) T= (1 + ) The true stress would be 20% higher in the case above where the specimen is 20% longer than the original length. As the relative elongation increases, the true strain will become significantly less than the engineering strain while the true stress becomes much greater than the engineering stress. When l= 4.0 lo then = 3.0 but the true strain =ln 4.0 = 1.39. Therefore, the true strain is less than 1/2 of the engineering strain. The true stress (T) = (1+ 3.0) = 4, or the true stress is 4 times the engineering stress. Tensile Test Nom ...
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Making communications land - Are they received and understood as intended? we...
Making communications land - Are they received and understood as intended? we...
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Making communications land - Are they received and understood as intended? we...
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