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Solving Equations by using the Zero Product Rule 5.7 SSC 105
[object Object],[object Object],[object Object],[object Object]
Solve a Quadratic Equation by Factoring ,[object Object],[object Object],[object Object],[object Object]
Example Solve the equation. 6 x 2  =  x  + 1 ,[object Object],[object Object],[object Object]
Example  (continued) Solve the equation. 6 x 2  =  x  + 1 ,[object Object]
More practice
Applications of Quadratic Equations A region of coastline off Biscayne Bay is approximately in the shape of a right angle. The corresponding triangular area has sandbars and is marked off on navigational charts as being shallow water. If one leg of the triangle is 0.5 mi shorter than the other leg, and the hypotenuse is 2.5 mi, find the lengths of the legs of the triangle (Figure 5-6).
Solve One leg of the triangle is 2 miles the other is 1.5 miles.

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Solving Qe

  • 1. Solving Equations by using the Zero Product Rule 5.7 SSC 105
  • 2.
  • 3.
  • 4.
  • 5.
  • 7. Applications of Quadratic Equations A region of coastline off Biscayne Bay is approximately in the shape of a right angle. The corresponding triangular area has sandbars and is marked off on navigational charts as being shallow water. If one leg of the triangle is 0.5 mi shorter than the other leg, and the hypotenuse is 2.5 mi, find the lengths of the legs of the triangle (Figure 5-6).
  • 8. Solve One leg of the triangle is 2 miles the other is 1.5 miles.