9. The source vS is a sinusoid with a 24 Vpeak amplitude. The diode is used to charge
a 12 V battery and the 100 resistor limits the current.
We want to determine the fraction of each cycle during which the diode
conducts. We also wish to find the peak-value of the diode current and the
maximum reverse-bias voltage that appears across the diode.
10. Solution
We reason that the diode will not begin to conduct until vS exceeds 12 V. Likewise, the
diode will stop conducting once vS again reaches 12 V.
This defines the conduction angle, 2 (i.e., the fraction of the sinusoidal cycle over which
the diode conducts). Hence, we reason that the diode will conduct provided that 24V sin
12 V. Or 30o ≤ ≤ 150o (or 1/3 of a cycle).
24V 12V
The peak value of the diode current is I D 0.12 Amps
100
12. Let’s begin by assuming that diodes D1 and D2 are conducting:
10 0
I D2 1mA
10k
KCL (node B):
0 ( 10)
I 1mA I 1mA
5k
For this second circuit the same assumption gives
nonsensical results (verify this)
We assume that D1 is OFF and D2 is ON.
Consequently, VB = 3.3 V (verify).