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Dx = (−1 , 0 , 1)
Dy = (−1 , 0 , 1)T
I
Ix = I ∗ Dx
Iy = I ∗ Dy
| G |=

I2
x + I2
y
θ = arctan(Iy
Ix
)
[0 , 40 )
[40 , 80 )
[80 , 120 )
v  v k ε
v → v/( v 1 +ε)
v → v/

 v 2
2 +ε2
(4 × 8) × (2 × 2) × 9 = 1152
{xk , yk} ∈ χ×{−1, 1} xk
yk
xk φ
f(x) = w ·φ(x)+b f(x)
φ(xi) x
f(x)
yi, i = 1, . . . , n
Hi
ˆf(y) =
1
n(2π)3/2
n
i=1
| Hi |−1/2
t(wi) exp(−
D2
[y, yi, Hi]
2
)
D2
[y, yi, Hi] = (y − yi)
H−1
i (y − yi)
y yi t(wi)
∇ ˆf(y) =
1
n(2π)3/2
n
i=1
| Hi |−1/2
H−1
i (yi − y)t(wi) exp(−
D2
[y, yi, Hi]
2
) =
1
n(2π)3/2
 n
i=1
| Hi |−1/2
H−1
i yit(wi) exp(−
D2
[y, yi, Hi]
2
)

−
1
n(2π)3/2
 n
i=1
| Hi |−1/2
H−1
i t(wi) exp(−
D2
[y, yi, Hi]
2
)

y

i
i(y) =
| Hi |−1/2
t(wi) exp(−D2[y,yi,Hi]
2
)
n
i=1
| Hi |−1/2 t(wi) exp(−D2[y,yi,Hi]
2
)
n
i=1
i = 1
∇ ˆf(y)
ˆf(y)
=
n
i=1
i(y)H−1
i yi −
 n
i=1
i(y)H−1
i

y
H−1
h (y) =
n
i=1
i(y)H−1
i
Hi
m(y) = Hh
∇ ˆf(y)
ˆf(y)
≡ Hh(y)
 n
i=1
i(y)H−1
i yi

− y
∇ ˆf(y) = 0 m(y) = 0
ym = Hh(ym)
 n
i=1
i(y)H−1
i yi

yi ym
yi, i =
1, . . . , n ym
Hi Hi diag [Hi]
diag [Hi] =

(exp (si) σx)2
, (exp (si) σy) , (σs)2
σx, σy, σs
MissRate = #falseNegatives
#truePositives+#falseNegatives
Precision = #truePositives
#truePositives+#falsePositives
#falseNegatives
#truePositives
#falsePositives
ao bp
bgt
ao =
area (bp ∩ bgt)
area (bp ∪ bgt)
ao
area (bp ∩ bgt) = (396 − 305) × (411 − 127) = 91 × 284 = 25844
area (bp ∪ bgt) = (443 − 259) × (458 − 90) = 184 × 368 = 67712
ao = 25844
67712
= 0.38
Hog processing
Hog processing
Hog processing
Hog processing
Hog processing
Hog processing
Hog processing
Hog processing

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Hog processing

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  • 8. Dx = (−1 , 0 , 1) Dy = (−1 , 0 , 1)T I Ix = I ∗ Dx Iy = I ∗ Dy
  • 9. | G |= I2 x + I2 y θ = arctan(Iy Ix )
  • 10. [0 , 40 ) [40 , 80 ) [80 , 120 )
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  • 13. v v k ε v → v/( v 1 +ε) v → v/ v 2 2 +ε2
  • 14. (4 × 8) × (2 × 2) × 9 = 1152 {xk , yk} ∈ χ×{−1, 1} xk yk xk φ
  • 15. f(x) = w ·φ(x)+b f(x) φ(xi) x f(x)
  • 16. yi, i = 1, . . . , n Hi ˆf(y) = 1 n(2π)3/2 n i=1 | Hi |−1/2 t(wi) exp(− D2 [y, yi, Hi] 2 )
  • 17. D2 [y, yi, Hi] = (y − yi) H−1 i (y − yi) y yi t(wi) ∇ ˆf(y) = 1 n(2π)3/2 n i=1 | Hi |−1/2 H−1 i (yi − y)t(wi) exp(− D2 [y, yi, Hi] 2 ) = 1 n(2π)3/2 n i=1 | Hi |−1/2 H−1 i yit(wi) exp(− D2 [y, yi, Hi] 2 ) − 1 n(2π)3/2 n i=1 | Hi |−1/2 H−1 i t(wi) exp(− D2 [y, yi, Hi] 2 ) y i i(y) = | Hi |−1/2 t(wi) exp(−D2[y,yi,Hi] 2 ) n i=1 | Hi |−1/2 t(wi) exp(−D2[y,yi,Hi] 2 ) n i=1 i = 1 ∇ ˆf(y) ˆf(y) = n i=1 i(y)H−1 i yi − n i=1 i(y)H−1 i y H−1 h (y) = n i=1 i(y)H−1 i
  • 18. Hi m(y) = Hh ∇ ˆf(y) ˆf(y) ≡ Hh(y) n i=1 i(y)H−1 i yi − y ∇ ˆf(y) = 0 m(y) = 0 ym = Hh(ym) n i=1 i(y)H−1 i yi yi ym yi, i = 1, . . . , n ym Hi Hi diag [Hi] diag [Hi] = (exp (si) σx)2 , (exp (si) σy) , (σs)2 σx, σy, σs
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  • 37. MissRate = #falseNegatives #truePositives+#falseNegatives Precision = #truePositives #truePositives+#falsePositives
  • 39. area (bp ∩ bgt) = (396 − 305) × (411 − 127) = 91 × 284 = 25844 area (bp ∪ bgt) = (443 − 259) × (458 − 90) = 184 × 368 = 67712 ao = 25844 67712 = 0.38