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Krittika    Poksawat N0.2  Class M.6/4 Tatcha   Tratornpisuttikul N0.12  Class M.6/4 Worawoot   Sumontra N0.23  Class M.6/4 Mahidol Wittayanusorn Constructing the quadrilateral with the  maximum area when given the lengths
Adviser Miss Nongluck   Arpasut  Mr. Sunya   Phumkumarn   Constructing the quadrilateral with the maximum area  when given the lengths
Introduction Currently, to find the area of any geometric figure is usually from any ready made figure. In another way, if the sides of figure are given then many geometric figures can be made. Our group will study how to construct maximal area figures especially in quadrilateral. The study is to examine that how the given four sides can be arranged and how to adjust the angles to construct a maximal area quadrilateral.  Constructing the quadrilateral with the maximum area  when given the lengths
Objective ,[object Object],[object Object],[object Object],Constructing the quadrilateral with the maximum area  when given the lengths
ระยะเวลาในการดำเนินงาน From July 2007 to December 2007 Constructing the quadrilateral with the maximum area  when given the lengths
that   cos ( A+B)   equal  to 0 . So that Consider , the area of the quadrilateral  Area  =  When given   The area will be the maximum when   Constructing the quadrilateral with the maximum area  when given the lengths Method is the smallest  That is we must construct the quadrilateral  in the circle.
So that, we can find the maximum area  Area  =  When given Constructing the quadrilateral with the maximum area  when given the lengths Method
Consider, the quadrilateral with the sum of the opposite angle equal to 180 Given the   quadrilateral   mnop  with the sides,   a,b,c,d .  Constructing the quadrilateral with the maximum area  when given the lengths Method
Figure 1 Figure 2     When figure 1 change to figure 2, we can suppose that  the sum of the opposite angle must equal to  Constructing the quadrilateral with the maximum area  when given the lengths Method
Constructing the quadrilateral with the maximum area  when given the lengths Method 1.) Consider the order of four sides. We found that it can be 3! or 6 figures and the sum of  length of three sides of quadrilateral  must more than another one. Thus   every quadrilaterals can construct 6 figures. 2.) Consider the order of four sides. We found that the 6 figures must have the same maximum area . The maximum area can calculate from the formula that is  when
consider   triangle   ADC   จาก  law of cosine then consider triangle   ABC   from   law of cosine then   … ..1 … ..2 (1) = (2) when Finding the relation Constructing the quadrilateral with the maximum area  when given the lengths Method
consider triangle   AEC from   law of cosine then … .(3) thus   From 1=3 Finding radius of circle Constructing the quadrilateral with the maximum area  when given the lengths Method
finding , , and giving is the angle between radius of circle in triangle CED is the angle between radius of circle in triangle AED is the angle between radius of circle in triangle AEB  is the angle between radius of circle in triangle BEC Consider triangle   CED   of   law of cosine then thus   In the same way Finding the angle at the center of circle Constructing the quadrilateral with the maximum area  when given the lengths Method
consider     then … .(1)   (1)+(2)  thus     … .(2)     Finding the relation of angles Constructing the quadrilateral with the maximum area  when given the lengths Method
when ผลการศึกษาที่  1 Constructing the quadrilateral with the maximum area  when given the lengths The relationship between angles and sides of the quadrilateral in the circle when the angle is between two sides that are adjacent sides.
[object Object],[object Object],[object Object],[object Object],given The second result Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],ผลการศึกษาที่  3 Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],ผลการศึกษาที่  4 Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],[object Object],The fourth result Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],The fourth result Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],The fourth result Constructing the quadrilateral with the maximum area  when given the lengths
[object Object],The fifth result Constructing the quadrilateral with the maximum area  when given the lengths

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Present(Eng)

  • 1. Krittika Poksawat N0.2 Class M.6/4 Tatcha Tratornpisuttikul N0.12 Class M.6/4 Worawoot Sumontra N0.23 Class M.6/4 Mahidol Wittayanusorn Constructing the quadrilateral with the maximum area when given the lengths
  • 2. Adviser Miss Nongluck Arpasut Mr. Sunya Phumkumarn Constructing the quadrilateral with the maximum area when given the lengths
  • 3. Introduction Currently, to find the area of any geometric figure is usually from any ready made figure. In another way, if the sides of figure are given then many geometric figures can be made. Our group will study how to construct maximal area figures especially in quadrilateral. The study is to examine that how the given four sides can be arranged and how to adjust the angles to construct a maximal area quadrilateral. Constructing the quadrilateral with the maximum area when given the lengths
  • 4.
  • 5. ระยะเวลาในการดำเนินงาน From July 2007 to December 2007 Constructing the quadrilateral with the maximum area when given the lengths
  • 6. that cos ( A+B) equal to 0 . So that Consider , the area of the quadrilateral Area = When given The area will be the maximum when Constructing the quadrilateral with the maximum area when given the lengths Method is the smallest That is we must construct the quadrilateral in the circle.
  • 7. So that, we can find the maximum area Area = When given Constructing the quadrilateral with the maximum area when given the lengths Method
  • 8. Consider, the quadrilateral with the sum of the opposite angle equal to 180 Given the quadrilateral mnop with the sides, a,b,c,d . Constructing the quadrilateral with the maximum area when given the lengths Method
  • 9. Figure 1 Figure 2 When figure 1 change to figure 2, we can suppose that the sum of the opposite angle must equal to Constructing the quadrilateral with the maximum area when given the lengths Method
  • 10. Constructing the quadrilateral with the maximum area when given the lengths Method 1.) Consider the order of four sides. We found that it can be 3! or 6 figures and the sum of length of three sides of quadrilateral must more than another one. Thus every quadrilaterals can construct 6 figures. 2.) Consider the order of four sides. We found that the 6 figures must have the same maximum area . The maximum area can calculate from the formula that is when
  • 11. consider triangle ADC จาก law of cosine then consider triangle ABC from law of cosine then … ..1 … ..2 (1) = (2) when Finding the relation Constructing the quadrilateral with the maximum area when given the lengths Method
  • 12. consider triangle AEC from law of cosine then … .(3) thus From 1=3 Finding radius of circle Constructing the quadrilateral with the maximum area when given the lengths Method
  • 13. finding , , and giving is the angle between radius of circle in triangle CED is the angle between radius of circle in triangle AED is the angle between radius of circle in triangle AEB is the angle between radius of circle in triangle BEC Consider triangle CED of law of cosine then thus In the same way Finding the angle at the center of circle Constructing the quadrilateral with the maximum area when given the lengths Method
  • 14. consider then … .(1) (1)+(2) thus … .(2) Finding the relation of angles Constructing the quadrilateral with the maximum area when given the lengths Method
  • 15. when ผลการศึกษาที่ 1 Constructing the quadrilateral with the maximum area when given the lengths The relationship between angles and sides of the quadrilateral in the circle when the angle is between two sides that are adjacent sides.
  • 16.
  • 17.
  • 18.
  • 19.
  • 20.
  • 21.
  • 22.