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Last Minute Doubts & Questions about 
FRM‐I Exam

© EduPristine  FRM‐I

© EduPristine – www.edupristine.com
Question 1 – FRM Exam 2008‐F
 A portfolio has an average return over the last year of 13.2%. Its benchmark has provided an 
average return over the same period of 12.3%. The portfolio’s standard deviation is 15.3%, its beta 
is 1.15, its tracking error volatility is 6.5% and its semi‐standard deviation is 9.4%. Lastly the risk 
free rate is 4.5%. Calculate the portfolio’s Information Ratio (IR). 
A.
B.
C.
D.

0.569
0.076
0.138
0.096

© EduPristine  FRM‐I

1
Answer
 C.
• Information Ratio = (Average Return on the Portfolio – Average Return on the benchmark)/Tracking Error 
Volatility 
• IR  = (13.2 – 12.3)/6.5 =  0.138 
• This question tests whether the candidate knows the information ratio. It has a number of destructors that 
make it difficult to ‘guess’ the formula
• A. Incorrect.  
• B. Incorrect.  
• D. Incorrect.  

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2
Question 2
 Albert Franklin wants to estimate the market risk premium for the stock of Arlene Pipes Company. 
He gathers the following information:
1.
2.
3.

Expected Return for Arlene 
Risk free rate
Beta for Arlene

10.75%
6.00%
0.60  

He believes that stock of Arlene Pipes is fairly priced. Based on above information Market risk 
Premium for Arlene Pipes Company is closest to:
A.
B.
C.
D.

1.75%
14%
8%
4.75%

© EduPristine  FRM‐I

3
Answer 
 C (chapter 3, FRM)
•
•
•
•

Using CAPM Model
10.75%=6%+0.6(E(RM)‐Rf)
(E(RM)‐Rf)=(10.75%‐6%)/0.6
(E(RM)‐Rf)=7.92%(close to 8%)

© EduPristine  FRM‐I

4
Question 3 – FRM Exam 2009`
 An investment bank uses the Exponentially Weighted Moving Average (EWMA) technique with 
lambda of 0.9 to model the daily volatility of a security. The current estimate of the daily volatility 
is 1.5%. The closing price of the security is USD 20 yesterday and USD 18 today. Using 
continuously compounded returns, what is the updated estimate of the volatility?
A.
B.
C.
D.

5.44%
3.62%
2.96%
1.31%

© EduPristine  FRM‐I

5
Answer
 B.
The current return of the security is = ln (18/20) = ‐10.536%. Using an EWMA model, the updated 
volatility is given as: V(t) = {lambda* ((V[t‐1]^2) +(1 – lambda)*(current return^2)} ^ 0.5
= {0.9 * ((0.015^2) + (1 ‐ 0.9) * ( ‐0.10536^2 )} ^ 0.5
= 3.62%
• INCORRECT: A – Forgets to square the volatility terms
• INCORRECT: C – Forgets to square the volatility terms and to take the square root of the resulting variance, 
then miscalculates conversion to percentage.
• INCORRECT: D – Forgets to take the square root of the variance, then miscalculates conversion to 
percentage.

© EduPristine  FRM‐I

6
Question 4 – FRM Exam 2008
 A factor analysis of the dividend‐adjusted returns of ABC Ltd.’s stock price was undertaken to 
determine which economic factors contributed to its performance. The regression was performed 
on 460 observations. The results are as follows:
Table 1:
Predictor

Coeffecient

Table 2
Standard Error of 
Coefficient

Intercept

‐0.0243

0.005772

All_Share_Index

0.0256

0.017655

Industrial_Index

0.0469
0.0012

12,466,47

Sum of squared Errors (SSE)

1,013.22

Sum of Squared Total (SST)

13,479.69

0.006398

Financial_Index

Sum of squared regression (SSR)

0.001412

 Which one of the following options correctly describes which variables are significant at the 5% 
level, and the R2 statistic, respectively? Significant Variables at 5%  level R2 statistic
A.
B.
C.
D.

Intercept; Industrial_index 0.924834
Intercept; Industrial_index 0.075166
All_share_index; Industrial_Index 0.924834
All_share_index; Industrial_Index 0.075166

© EduPristine  FRM‐I

7
Answer
 A.
• The following table shows the test statistics for each of the four variables, calculated by dividing the variable 
coefficient by the standard error . The variable is significant if the absolute value of the t‐stat is greater than 
the critical value from the student’s t‐distribution for 456 degrees of freedom (which is very close to the z‐
statistic since the number of observations is so high), i.e. 1.96. Predictor t‐stat Significant?
• Intercept ‐.0243/0.005772 = ‐4.21 Yes 
• All_share_index .0256/0.017655 = 1.45 No
• Industrial_index .0469/0.006398 = 7.33 Yes
• Financial_index .0012/0.001412 = 0.85 No
• The R2 statistic is defined as the ratio of SSR/SST = 12,466.47/13,479.69 = 0.924834. 

© EduPristine  FRM‐I

8
Question 5 – FRM Sample Paper 2011
 The following GARCH(1,1) model is used to forecast the daily return variance of an asset:
σn2 = 0.000005 + 0.05u2n‐1 + 0.92σ2n‐1
Suppose the estimate of the volatility today is 5.0% and the asset return is ‐2.0%. What is the 
estimate of the long‐run average volatility per day?
A.
B.
C.
D.

1.29%
1.73%
1.85%
1.91%

© EduPristine  FRM‐I

9
Answer
 A.
• The model corresponds to α = 0.05, β = 0.92, and ω = 0.000005. Because γ = 1− α− β, it follows that γ =  
0.03.
• Because the long‐run average variance, VL, can be found by VL = ω / γ , it follows that VL = 0.000167. In 
other words, the long‐run average volatility per day implied by the model is sqrt(0. 000167) = 1.29%.

© EduPristine  FRM‐I

10
Question 6 – FRM Sample Paper 2006
 Consider an equity portfolio with market value of USD 100M and a beta of 1.5 with respect to the 
S&P 500 Index. The current S&P 500 index level is 1000 and each futures contract is for delivery of 
USD 250 times the index level. Which of the following strategy will reduce the beta of the equity 
portfolio to 0.8?
A.
B.
C.
D.

Long 600 S&P 500 futures contracts
Short 600 S&P 500 futures contracts
Long 280 S&P 500 futures contracts
Short 280 S&P 500 futures contracts

© EduPristine  FRM‐I

11
Answer
 D.
• To reduce the beta of a portfolio, one needs to lower the position’s exposure to the market. Thus, one needs 
to short futures contracts. The number of futures contracts, N, is:

N  (  new   old ) 
 ( 0 . 8  1 .5 ) 

Size of spot Position
Size of one Futures contract

100 ,000 ,000
 280
250 * 1000

• Thus, one needs to short 280 futures contracts

© EduPristine  FRM‐I

12
Question 7‐ FRM Sample Paper 2007
 An investor enters into a short position in a gold futures contract at USD 294.20. Each futures 
contract controls 100 troy ounces.  The initial margin is USD 3,200, and the maintenance margin is 
USD 2,900.  At the end of the first day, the futures price drops to USD 286.6.  Which of the 
following is the amount is the variation margin at the end of the first day? 
A.
B.
C.
D.

0 
USD 34 
USD 334 
USD 760 

© EduPristine  FRM‐I

13
Answer
 A.
• Since the investor is shorting the futures contract, she/he gains when the futures price goes down.  At the 
end of the first day, the investor has a gain of (294.2 – 286.6) * 100 = $ 760.  Therefore, no variation margin 
is needed

© EduPristine  FRM‐I

14
Question 8 – FRM Sample Paper 2011
 Alan bought a futures contract on a commodity on the New York Commodity Exchange on June 1. 
The futures price was USD 500 per unit and the contract size was 100 units per contract. Alan set 
up a margin account with initial margin of USD 2,000 per contract and maintenance margin of 
USD 1,000 per contract. The futures price of the commodity varied as shown below. What was the 
balance in Alan’s margin account at the end of day on June 5?
Day Futures Price (USD)
June 1 497.30
June 2 492.70
June 3 484.20
June 4 471.70
June 5 468.80
A.
B.
C.
D.

USD 1,120
USD 0
USD 880
USD 1,710

© EduPristine  FRM‐I

15
Answer
 D.
Day

Future’s Price

Daily Gain (Loss)

Cumulative Gain 
(Loss)

Margin Account 
Balance

June 1

497.30

(270)

(270)

1730

June 2

492.70

(460)

(730)

1270

June 3

484.20

(850)

(1580)

420

1580

June 4

471.70

(1250)

(2830)

750

1250

June 5

468.80

(290)

(3120)

1710

© EduPristine  FRM‐I

Margin Call

16
Question 9
 The USD interest rate is 4% per annum and the AUD rate is 6% per annum. Assume that the term 
structure of interest rates is flat in the US and Australia. Assume current value of AUD to be $0.91. 
Company ABC, under the terms of a swap agreement, pays 7% per annum in AUD and receives 3% 
per annum in US$. The principal in the US is 10million USD and that in Australia is 11million AUD. 
Payments are exchanged each year and the swap will last for 3 more years. Determine the value 
of swap assuming continuous compounding in all interest rates.

© EduPristine  FRM‐I

17
Solution
 Valuation of currency swap in terms of bonds (millions):

 Value of swap in million $ = 11.294*0.91 – 9.7225= $0.5448 million

© EduPristine  FRM‐I

18
Question 10 ‐ FRM Sample Paper 2012
 A portfolio has a current market value equal to USD 6,247,000 with a daily variance of 0.0002. 
Assuming there are 250 trading days in a year and that the portfolio return follow  a normal 
distribution. The estimate of annual VaR at 95% confidence level is closes to which of the 
following?
A.
B.
C.
D.

USD 32595
USD 145,770
USD 2,297,854
USD 2,737,868

© EduPristine  FRM‐I

19
Answer
 C
Daily standard deviation = sqrt ( 0.0002) = 0.01414
Annual VaR = 6247000 * sqrt (250) * 0.01414 * 1.645
= 2,297,854

© EduPristine  FRM‐I

20
Question 11 – FRM Exam 2006
 Given the following 30 ordered simulated percentage returns of an asset, calculate the VAR and 
expected shortfall (both expressed in terms of returns) at a 90% confidence level.
‐16, ‐14, ‐10, ‐7, ‐7, ‐5, ‐4, ‐4, ‐4, ‐3, ‐1, ‐1, 0, 0, 0, 1, 2, 2, 4, 6, 7, 8, 9,11, 12, 12, 14, 18, 21, 23
A.
B.
C.
D.

VAR (90%) = 10, Expected shortfall = 14
VAR (90%) = 10, Expected shortfall = 15
VaR (90%) = 14, Expected shortfall = 15
VaR (90%) = 18, Expected shortfall = 22

© EduPristine  FRM‐I

21
Answer
 B.
• Ten percent of the observations will fall at or below the 3rd lowest observation of the 30 listed. Therefore, 
the VaR equals 10. The expected shortfall is the mean of the observations exceeding the VaR. Thus, the 
expected shortfall equals (16 + 14) / 2 = 15

© EduPristine  FRM‐I

22
Question 12 – FRM Exam 2006
 A portfolio is composed of two securities and has the following characteristics
•
•
•
•
•

Investment in security A = USD 1,500,000
Investment in security B = USD 3,000,000
Volatility of security A = 7%
Volatility of security B = 3%
Correlation between security A and B = 10%

What is the closest answer for the portfolio diversified VAR at 95% confident level?
A.
B.
C.
D.

USD 7,351
USD 212,920
USD 365,715
USD 234,630

© EduPristine  FRM‐I

23
Answer
 D.
• To calculate the VAR of the portfolio, we first must calculate the volatility of the portfolio, σ. The variance of 
the portfolio equals:
• σ2 = (1/3)2 (7%)2 + (2/3)2 (3%)2 + 2*(1/3)*(2/3)*10%*7%*3% = 0.001, Thus, σ = 0.0316
• Assuming a 95% confidence interval, VAR = 1.65 * 0.0316 * 4,500,000 = 234,630

© EduPristine  FRM‐I

24
Question 13 – FRM Exam 2011
 Consider a bond with par value of EUR 1,000 maturity in 3 years, and that pays a coupon of 5% 
annually.
The spot rate curve is as follows:

Term

Annual Spot Interest Rate

1

6%

2

7%

3

8%

The value of the bond is closest to:
A.
B.
C.
D.

EUR 904
EUR 924
EUR 930
EUR 950

© EduPristine  FRM‐I

25
Answer
 B.
• Using spot rates, the value of the bond is:
• 50/(1.06) + 50/[(1.07)^2] + 1050/[(1.08)^3] = 924.37

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