What output is produced by the following code? Int count = 0; do { system. out. print in(count); cout ++} while (count
Solution
Answer:
0
Count after loop = 2
Explanation:
There are some systex errors. i have fixed it. Below is the right code for execution. Highlighted (Bold) areas are the code changes.
int count = 0;
do{
System.out.println(count);
count++ ;
}while(count < 0);
System.out.println(\"Count after loop = \"+ (++count) );
At First line, count variable value is 0. Since we are using do while loop, without checking condition do statements will execute. So line 3 will execute and print count variabe as 0. At line 4, count variable will increment by 1. so count variable value at line 4 is 1. at line 5, condition fails so loop will terminate. So line 6 will execute and print count variable as 2.
So The final output is below
0
Count after loop = 2
.
What output is produced by the following code- Int count - 0- do { sys.docx
1. What output is produced by the following code? Int count = 0; do { system. out. print in(count);
cout ++} while (count
Solution
Answer:
0
Count after loop = 2
Explanation:
There are some systex errors. i have fixed it. Below is the right code for execution. Highlighted
(Bold) areas are the code changes.
int count = 0;
do{
System.out.println(count);
count++ ;
}while(count < 0);
System.out.println("Count after loop = "+ (++count) );
At First line, count variable value is 0. Since we are using do while loop, without checking
condition do statements will execute. So line 3 will execute and print count variabe as 0. At line
4, count variable will increment by 1. so count variable value at line 4 is 1. at line 5, condition
fails so loop will terminate. So line 6 will execute and print count variable as 2.
So The final output is below
0
Count after loop = 2
