Experiment 4
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1) The document is about an experiment conducted by a student to learn about half-wave rectification. 2) Half-wave rectification removes one half of the input signal to establish a DC level. The DC value of the output from a half-wave rectifier is equal to the peak voltage of the input signal divided by pi. 3) The student built the half-wave rectifier circuit, measured the output voltage using a multimeter and oscilloscope, and observed that the output waveform had both DC and AC components as expected.
![WESLEYAN UNIVERSITY – PHILIPPINES<br />Cabanatuan City<br />COLLEGE OF ENGINEERING<br />NAME: EDUARDO S. CUDIADATE:09 – 23 – 11 <br />SCHEDULE: Friday (3:00 – 6:00)<br />EXPERIMENT NO. 4<br />Half – Wave Rectifier<br />OBJECTIVES:<br />To learn how rectification is achieved using diodes in a circuit particularly half – wave rectification.<br />MATERIALS: <br />1 IN4001<br />1 resistor (value assigned by instructor)<br />1 unregulated power supply<br />1 multitester<br />1 oscilloscope<br />1 breadboard<br />Connecting Wires<br />DISCUSSIONS:<br />Rectification is the process of converting AC to DC. However, if we look at the output voltage of a rectifier, it does not look very much like a constant. How then does rectification produce DC.<br />A pure sinusoid has no DC component. It is because for each cycle of the sinusoid, there are much positive areas as there are negative areas, the total are therefore is zero.<br />It is very sure through that there is DC component as well as an AC component.<br />Half - wave rectification is the process of removing one – half of the input signal to establish a DC level. Since half of the input signal is removed by a half – wave rectifier, the DC value of a half – wave rectified signal is given by:<br />Half – wave Rectified signal, Vdc = Vp/π<br />Where : Vdc - is the DC value of a half wave rectified signal<br /> Vp – is the peak voltage of the signal<br />PROCEDURE:<br />,[object Object]](https://image.slidesharecdn.com/experiment4-111006084743-phpapp02/85/Experiment-4-1-320.jpg)
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Experiment 4
- 2. Determine the output voltage of the rectifier circuit by connecting the multitester parallel to R. Note that the positive probe of the tester is connected at point A and the negative probe is connected at point B.
- 3. Determine the output voltage of the same circuit using the oscilloscope. Follow the procedure taught during the familiarization hours.
- 5. Record the peak to peak value of the output voltage as measured by the oscilloscope.
- 6. Determine manually the DC value of the measured output voltage using the multitester.
- 7. Determine manually the DC value of the measured output voltage using the oscilloscope.
- 8. Is the computed DC value for the measured output voltage using the multitester equal to DC value of the measured output voltage using the oscilloscope?
- 9. If not, what accounts for the difference?
- 10. Draw and label the parts of the output waveform as viewed from the oscilloscope.
- 11. Describe the viewed output waveform.
- 12. TABLE 1
- 14. A half – wave rectifier removes the ONE – HALF of the input signal.
- 15. A pure sinusoid has no DC component.
- 16. The output of a rectifier has both DC and AC component.